Question

Qno.1 Part(A).

IN jAVA if

1.Int abc; 2. Int def = 8; 3. abc = def; ➢ Describe the procedure how much memory will be allocated when these three lines of codes will execute. ➢ Describe what will happened after execution of each of these line of code in term of memory allocation and data storage

Qno.1 Part(B)

A capacitor is constructed from two conductive metal plates 30cm x 50cm which are spaced 6mm
apart from each other, and uses dry air as its only dielectric material. Calculate the capacitance of
the capacitor using following formula.
C = (die-electric permittivity * Area of plates) / distance between plates
Note: The die-electric permittivity of dry air is 8.84 x 10-12
➢ Write a java program that can calculate the capacitance of any capacitor if we provide it
area of plates, distance between plates and die-electric permittivity of the die-electric.

NOTE:DO ANSWER BOTH PARTS..SOLVE PART (A) IN JAVA THEN PASTE IT HERE AND FOR PART (B) JUST WRITE THE ANSWER

Answer 1

Part A:

1. Total of 12 bytes will be allocated to the 3 variables(primitive) with 4bytes to each variable.

2. 3 variables will be allocated memory of 4 bytes and will have their respective stored in them in Stack.

Part B:

1. Answer : 0.220nF (nF -> nano Farad)

2. Find the code below,

import java.util.*;

public class CapacitanceCalc {

    //Write a java program that can calculate the capacitance of any capacitor if we provide it
    //area of plates, distance between plates and die-electric permittivity of the die-electric.
    private static final Scanner sc = new Scanner(System.in);

    public static void main(String[] args) {

        System.out.println("Enter Area of plates (in meters): ");
        double areaOfPlates = sc.nextDouble();
        System.out.println("Enter distance b/w plates (in meters): ");
        double distanceBwPlates = sc.nextDouble();
        System.out.println("Enter die-electric permittivity of the die-electric : ");
        double permittivity = sc.nextDouble();

        double capacitance = (permittivity * areaOfPlates)/distanceBwPlates;
        System.out.println("Capacitance : "+ capacitance);
    }
}

OUTPUT with PartB (1) question:

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