Question

In: Computer Science

Why is 1 example of my code failing? def current_player_score(score_one: int, score_two: int,current_player: str) -> int:...

Why is 1 example of my code failing?

def current_player_score(score_one: int, score_two: int,current_player: str) -> int:
"""Return <score_one> if the <current_player> represents player one, or
<score_two> if the <current_player> represents player two.

>>> current_player_score(2, 4, "Player one")
2
>>> current_player_score(2, 3, "Player two")
3
"""

if current_player == PLAYER_ONE:
return score_one
return score_two

Solutions

Expert Solution

You code failed because in function  current_player_score() , current_player is declared as string type but in if statement you were using PLAYER_ONE which is undefine inside this function.

Solution of this problem are

1) . Use if current_player == "Player one": in condition

2) Declared a variable inside function as

PLAYER_ONE=Player one then you code will work fine

Here is a code for both solution:

===============================

Solution 1

def current_player_score(score_one: int, score_two: int,current_player: str) -> int:
"""Return <score_one> if the <current_player> represents player one, or
<score_two> if the <current_player> represents player two.

>>> current_player_score(2, 4, "Player one")
2
>>> current_player_score(2, 3, "Player two")
3
"""

if current_player == "Player one":
return score_one
return score_two

Soluiton 2

def current_player_score(score_one: int, score_two: int,current_player: str) -> int:
"""Return <score_one> if the <current_player> represents player one, or
<score_two> if the <current_player> represents player two.

>>> current_player_score(2, 4, "Player one")
2
>>> current_player_score(2, 3, "Player two")
3
"""
PLAYER_ONE="Player one"
if current_player == PLAYER_ONE:
return score_one
return score_two

Code Snapshot:

=====================

Solution 1

=======================

Solution 2

=================

Output

===============


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