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In: Advanced Math

Encipher each plaintext trigraph code by computing (Plaintext trigraph code)Public Key, dividing the result by the...

  • Encipher each plaintext trigraph code by computing (Plaintext trigraph code)Public Key, dividing the result by the Modulus and taking the remainder.

Okay so the trigraph key is 2723 and the public key is 97 and the modulus is 50657. Literally every calculator i use says the number is too large. I am so confused. These are the numbers what is the problem. Is this the wrong formula the teacher gave us this formula. I am so confused.

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