In: Chemistry
An electrochemical cell is based on the following two half-reactions:
Ox: Sn(s)→Sn2+(aq, 1.65 M )+2e−
Red: ClO2(g, 0.165 atm )+e−→ClO−2(aq, 1.90 M )
Compute the cell potential at 25 ∘C.
Ans:- Compute the cell potential at 25 ∘C.
Ox: Sn(s)→Sn2+(aq, 1.65 M )+ 2e− : E = -0.14v
Red: ClO2(g, 0.165 atm )+ e−→ClO−2(aq, 1.90 M): E = 0.954v
E0 = EC - EA
= 0.954-(-0.14)
= 1.094v
NERNST EQUTION: E = E0 -0.0591/2*log (cathode)/(anode)
E = 1.094-0.029*log(1.90)2/(1.65)
E = 1.094-0.029*log 2.1878
E = 1.094-0.029*0.34
E = 1.0842 Volts