Question

In: Physics

The motion of Halley’s comet and its motion. Halley’s comet travels in an elliptical orbit of...

The motion of Halley’s comet and its motion. Halley’s comet travels in an elliptical orbit of eccentricity ϵ = 0.97 around the Sun. At perihelion (closest approach), Halley’s comet is observed to be approximately 0.59 AU from the Sun. At aphelion the distance is about 35.08 AU, the semi-major axis of the elliptical orbit is 17.83 AU, and the orbital period is about 75.3 Earth years.

1) Since Earth has an essentially circular orbit that is 1 AU from the Sun. Use any approach that you like to determine the Earth’s orbital speed is v_E = sqrt(GM_S/R_E) and then determine a numerical value in kilometers/second.

2) Use the perihelion, aphelion, semi-major axis, and period above for Halley’s comet to determine the value of the characteristic length, r_c, that describes the elliptical orbital path, r(φ), for Halley’s comet.

3) Use the definition of r_c to estimate the speed of Halley’s comet at perihelion. Write the result in symbolic first, which should look like the result in part 1, then write it as the result from part (a) and appropriate ratios to estimate the numerical value of Halley’s comet’s speed at perihelion.

Solutions

Expert Solution

  1. Let the Earth have a mass and it orbits around the Sun of mass in a circular orbit of radius . Then, the necessary centripetal force for the orbital motion is provided by the gravitational pull of the Sun. Thus, if is the orbital velocity of Earth,

where is the gravitational constant. Equation (1) rearranges to give

Now, plugging in the numerical values,

, , , we get

  1. Given data:

Let the characteristic length of the elliptical orbit of Halley's comet be . Then, the semi-major axis length is given by

from which we can calculate as

Thus, the orbital position of the comet as a function of the angle is

  1. Let the speed of the comet at the perihelion be . The angular momentum of the comet at the perihelion is

where is the mass of Halley's comet. There is no need for subscript for angular momentum as it is a conserved quantity in central force motion. Now, the angular momentum is related to the characteristic length according to

Comparing (7) and (8), we get

from which the perihelion velocity becomes

which is the expression for the perihelion speed of the comet. Now, from the given data,

Thus, the perihelion speed is

Feel free to leave a comment for any queries and rate the answer if you find it helpful.

Regards.


Related Solutions

The motion of Halley’s comet and its motion. Halley’s comet travels in an elliptical orbit of...
The motion of Halley’s comet and its motion. Halley’s comet travels in an elliptical orbit of eccentricity ϵ = 0.97 around the Sun. At perihelion (closest approach), Halley’s comet is observed to be approximately 0.59 AU from the Sun. At aphelion the distance is about 35.08 AU, the semi-major axis of the elliptical orbit is 17.83 AU, and the orbital period is about 75.3 Earth years. 1) Since Earth has an essentially circular orbit that is 1 AU from the...
A comet moves in an elliptical orbit around the sun. As the comet moves from aphelion...
A comet moves in an elliptical orbit around the sun. As the comet moves from aphelion (the point on the orbit farthest from the sun) to perihelion (the point on the orbit closest to the sun), which of the following results is true? Speed of the comet Angular momentum of the comet/sun system Gravitational potential energy of the comet/sun system A Increases Increases Decreases B Increases Constant Decreases C Decreases Decreases Increases D Increases Increases Constant E Constant Constant Constant
Draw a free body diagram for a satellite in an elliptical orbit showing why its speed...
Draw a free body diagram for a satellite in an elliptical orbit showing why its speed increases as it approaches its parent body and decreases as it moves away
Planet X has a moon that has a very elliptical orbit. Its furthest point from the...
Planet X has a moon that has a very elliptical orbit. Its furthest point from the planet X is 4 × 10^8 m and its closest point is 3 × 10^8 m. If its speed at the furthest point is 700 m/s, what is its speed at its closest point? The mass of planet X is 2.68 X 10^24 kg and the radius of planet X is 4079 km. (please show work and drawing)
A satellite is put into an elliptical orbit around the Earth. When the satellite is at...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is hp=215.0 km,hp=215.0 km, and it is moving with a speed of vp=8.450 km/s.vp=8.450 km/s. The gravitational constant GG equals 6.67×10−11 m3⋅kg−1⋅s−26.67×10−11 m3·kg−1·s−2 and the mass of Earth equals 5.972×1024 kg.5.972×1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what is its height haha above...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is ℎp=215.0 km, and it is moving with a speed of ?p=8.850 km/s. The gravitational constant ? equals 6.67×10−11 m3·kg−1·s−2 and the mass of Earth equals 5.972×1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what is its height ℎa above the ground? For this...
A satellite is placed in an elongated elliptical (not circular) orbit around the Earth. At the...
A satellite is placed in an elongated elliptical (not circular) orbit around the Earth. At the point in its orbit where it is closest to the Earth, it is a distance of 1.00 × 10^6 m from the surface (not the center) of the Earth, and is moving at a velocity of 5.14 km/s. At the point in its orbit when it is furthest from the Earth it is a distance of 2.00×10^6 m from the surface of the Earth....
A satellite is put into an elliptical orbit around the Earth. When the satellite is at...
A satellite is put into an elliptical orbit around the Earth. When the satellite is at its perigee, its nearest point to the Earth, its height above the ground is hp=215.0 km,hp=215.0 km, and it is moving with a speed of vp=8.450 km/s.vp=8.450 km/s. The gravitational constant GG equals 6.67×10−11 m3⋅kg−1⋅s−26.67×10−11 m3·kg−1·s−2 and the mass of Earth equals 5.972×1024 kg.5.972×1024 kg. When the satellite reaches its apogee, at its farthest point from the Earth, what is its height haha above...
A satellite is in an elliptical orbit around the earth. The distance from the satellite to...
A satellite is in an elliptical orbit around the earth. The distance from the satellite to the center of the earth ranges from 7.2 Mm at perigee (where the speed is 8.0 km/s) to 9.9 Mm at apogee. 1. Assume the initial conditions are x = 0, y = 7.2 × 106 m, vx = 8.0×103 m/s, and vy = 0. Use python program to print its speed, distance from the earth, kinetic energy, potential energy, and total mechanical energy...
Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed...
Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.8×104 m/s when at a distance of 2.6×1011 m from the center of the sun, what is its speed when at a distance of 5.2×1010 m v=…..m/s
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT