In: Statistics and Probability
The Acme Company manufactures large capacity Flash drives using two different manufacturing processes. The company is interested in determining if there is a significant difference in the average manufacturing time of the two processes. For Process #1, a sample of 28 items shows a sample mean of 9 minutes and a sample standard deviation of 3.5 minutes. For Process #2, a sample of 23 items shows a sample mean of 13 minutes and a sample standard deviation of 4.5 minutes. At a 5% level of significance, Test the claim of no difference in the average time for the two processes. What is your conclusion?
SOLUTION:
From given data,
For Process #1, a sample of 28 items shows a sample mean of 9 minutes and a sample standard deviation of 3.5 minutes.
For Process #2, a sample of 23 items shows a sample mean of 13 minutes and a sample standard deviation of 4.5 minutes. At a 5% level of significance.
Given as,
For Process #1:
= 9
= 3.5
= 28
For Process #2:
= 13
= 4.5
= 23
Formula for test statistic
test statistic = ( - ) /
= (9 - 13) /
= -4 / 1.1480134
= -3.484279
level of significance is 5%
= 0.05
/2 = 0.05 / 2 = 0.025
Critical value = invt(0.025 ,df=22) = -2.074
conclusion
Since the test statistic is less than the critical value ,
you would reject the null hypothesis.
There is enough evidence at a 5% level of significance to conclude that there is difference in the manufacturing time.