In: Statistics and Probability
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A university classifies faculty by rank as instructors, assistant professors, associate professors, and full professors. The data, by faculty rank and gender, are given in the following contingency table. Test to see if faculty rank and gender are independent.
FACULTY |
instructor | assistant prof | associate prof | full prof |
male | 62 | 238 | 185 | 115 |
famle | 118 | 122 | 123 | 37 |
Claim: Faculty rank and gender are independent.
The null and alternative hypothesis is
H0: Faculty rank and gender are independent.
H1: Faculty rank and gender are not independent.
Level of significance = 0.05
Test statistic is
O: Observed frequency
E: Expected frequency.
E = ( Row total*Column total) / Grand total
FACULTY | instructor | assistant prof | associate prof | full prof | Total |
male | 62 | 238 | 185 | 115 | 600 |
famle | 118 | 122 | 123 | 37 | 400 |
Total | 180 | 360 | 308 | 152 | 1000 |
O | E | (O-E) | (O-E)^2 | (O-E)^2/E |
62 | 108 | -46 | 2116 | 19.59259 |
238 | 216 | 22 | 484 | 2.240741 |
185 | 184.8 | 0.2 | 0.04 | 0.000216 |
115 | 91.2 | 23.8 | 566.44 | 6.210965 |
118 | 72 | 46 | 2116 | 29.38889 |
122 | 144 | -22 | 484 | 3.361111 |
123 | 123.2 | -0.2 | 0.04 | 0.000325 |
37 | 60.8 | -23.8 | 566.44 | 9.316447 |
Total | 70.11 |
Degrees of freedom = ( Number of rows - 1 ) * ( Number of column
- 1) = ( 2 - 1) * (4 - 1) = 1 * 3 = 3
Critical value = 7.815
( From chi-square table)
Test statistic > critical value we reject null hypothesis.
Conclusion:
Faculty rank and gender are not independent.