In: Physics
a) energy of the first excited state = -10eV
so energy of 10eV is needed to ionize
b) the possible transitions are
n=4 to n=3 energy given out = 5 -2 = 3eV
n= 4 to n=2 energy given out = 10 -2 = 8eV
n= 3 t0 n=2 energy given out = 10 -5 = 5eV
hence photons with energies of 3eV, 5eV and 8 eV can be emitted
c) if a photon of 5eV is absorbed , the electron would jump to second excited state that is n=3
d) the photon would not be absorbed as a photon can not be partially absorbed
e) the minimum value of work function is 5 eV
and maximum value of work function is 15eV