In: Physics
A mass of 11.0 kg , fastened to the end of an aluminum wire with an unstretched length of 0.47 m , is whirled in a vertical circle with a constant angular speed of 118 rev/min . The cross-sectional area of the wire is 2.0×10−2 cm2 .
Part A:
Calculate the elongation of the wire when the mass is at the lowest point of the path.
Express your answer using two significant figures.
Part B:
Calculate the elongation of the wire when the mass is at the highest point of its path.
Express your answer using two significant figures.
Calculate the elongation of the wire when the mass is at the highest point of its path.
Express your answer using two significant figures.
angular velocity ω = 118 rev/s = 118 * 2π rad/s
= 741.4 rad/s
Centrifugal force Fc = m * r * ω2
= 11 * 0.47 * 741.42
= 2841936.00N
Net force F = Fc + m * g
= 2841936.00+ 11 * 9.8
= 2842043.8 N
Young's modulus is defined as
Y = F * L / A * ΔL
Where ΔL is elongation produced and L = r = length of wire
ΔL = F * L / A * Y
=> ΔL = 2842043.8* 0.47/ 2.0 * 10-6 * 2.0 * 1011
= 3.3 * 10-3 m
= 3.3 mm