Question

In: Computer Science

Please use c++ Consider the code on the next page. It creates a vector of five...

Please use c++

Consider the code on the next page. It creates a vector of five strings of vegetable names and you want to make the vector contain only vegetable names that you like. In the spaces designated, perform the following:

  1. Declare an iterator for a vector of strings, move it to the position of 'Tomato', and erase it because it's not a vegetable.
  2. With the same iterator, use .begin() to point it to the beginning of the list, and erase the first item, ‘Broccoli’ (Because no one likes broccoli.)
  3. Write two lines of code that will add two vegetable names that you DO like that isn't already on this list.

#include

#include

using namespace std;

void printVector(vector);

int main()

{

       vector vegs;

       vegs.push_back("Broccoli");

       vegs.push_back("Celery");

       vegs.push_back("Kale");

       vegs.push_back("Tomato");

       vegs.push_back("Carrot");

      

       printVector(vegs);

       cout << "Declare an iterator for a vector of strings, move it to the position of 'Tomato', and erase it because it's not a vegetable: " << endl;

       printVector(vegs);

       cout << "With the same iterator, point it to the beginning of the list, and erase the first item, ‘Broccoli’ (Because no one likes broccoli.): " << endl;

      

       printVector(vegs);

       cout << "Write two lines of code that will add two vegetable names that you DO like that isn't already on this list." << endl;

      

       printVector(vegs);

      

       return 0;

}

void printVector(vector v)

{

       for (int i = 0; i < v.size(); i++)

       {

              cout << v[i] << " ";

       }

       cout << endl << endl;

}

Solutions

Expert Solution

Ans:-

(a.)  vector<string>:: iterator itr; // it will declare an iterator for vector
for(auto itr=vegs.begin();itr!=vegs.end();++itr) // loop to iterate through vector using iterator
{
if(*itr=="Tomato") // check if the iterator points to the "Tomato"
vegs.erase(itr); // remove the item using erase function
}

(b.)  itr=vegs.begin(); // now iterator points to the begining of vector
vegs.erase(itr); // remove the item using erase function

(c.) vegs.push_back("Cauliflower"); // it will add vegetable cauliflower to the vector
vegs.push_back("Capsicum");  // it will add vegetable capsicum to the vector

The whole updated code is shown below:-

#include <iostream>

#include <vector>

using namespace std;

void printVector(vector<string>);

int main()

{

       vector<string> vegs;

       vegs.push_back("Broccoli");

       vegs.push_back("Celery");

       vegs.push_back("Kale");

       vegs.push_back("Tomato");

       vegs.push_back("Carrot");

      

       printVector(vegs);

       cout << "Declare an iterator for a vector of strings, move it to the position of 'Tomato', and erase it because it's not a vegetable: " << endl;
       
       vector<string>:: iterator itr; //it will declare an iterator for vector
    for(auto itr=vegs.begin();itr!=vegs.end();++itr) //loop to iterate through vector using iterator
    {
        if(*itr=="Tomato")  // check if the iterator points to the "Tomato"
          vegs.erase(itr); //remove the item using erase function
    }
       printVector(vegs);

       cout << "With the same iterator, point it to the beginning of the list, and erase the first item, ‘Broccoli’ (Because no one likes broccoli.): " << endl;

       itr=vegs.begin(); //now iterator points to the begining of vector
       vegs.erase(itr);  //remove the item using erase function
       printVector(vegs);

       cout << "Write two lines of code that will add two vegetable names that you DO like that isn't already on this list." << endl;

       vegs.push_back("Cauliflower"); // insert cauliflower to the list
       vegs.push_back("Capsicum");  // insert capsicum to the list
       printVector(vegs);

      

       return 0;

}

void printVector(vector<string> v)

{

       for (int i = 0; i < v.size(); i++)

       {

              cout << v[i] << " ";

       }

       cout << endl << endl;

}

Output:-

Note:- In the c part, if you want to check whether the new vegetable that you are adding to the vector is already present or not, then you can update your c part, with the following code:

if(find(vegs.begin(),vegs.end(),"Cauliflower") == vegs.end())
vegs.push_back("Cauliflower");
if(find(vegs.begin(),vegs.end(),"Capsicum") == vegs.end())
vegs.push_back("Capsicum");

However, the question strictly ask to write only two line of code, that's why, I didn't opt this method.


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