The credit scores of 35-year-olds applying for a mortgage at Ulysses Mortgage Associates are normally distributed with a mean of 600 and a standard deviation of 90. (a) Find the credit score that defines the upper 5 percent. (Use Excel or Appendix C to calculate the z-value. Round your final answer to 2 decimal places.) Credit score (b) Seventy-five percent of the customers will have a credit score higher than what value? (Use Excel or Appendix C for calculation of z-value. Round your final answer to 2 decimal places.) Credit score (c) Within what range would the middle 80 percent of credit scores lie? (Use Excel or Appendix C for calculation of z-value. Round your final answer to 2 decimal places.) Range-- to---
In: Math
In: Math
Complete the following problems using R. Name the file with your last name, e.g., “Prob set 6-Smith.eoc”Clearly label problems, and be sure to turn in explanations and interpretations where appropriate.
3.Total cholesterol has been reported to be 200 mg/dL on average in the US by the Centers for Disease Control. You measure total cholesterol on a random sample of 80 Alabama adults, with the intention of comparing Alabamians’ cholesterol level to that of the US average. Data are included in the assignment .xlsx file. Assume
that cholesterol is approximately normally distributed with a known standard deviation of 70 mg/dL.
a.What is the mean value observed for Alabamians’ cholesterol?
b.What is the standard error of Alabamians’ cholesterol assuming the given known standard deviation?
c.Find the 95% confidence interval for the unknown population mean of Alabamians’ cholesterol level values and interpret its meaning.
d.Test the hypothesis that Alabamians have higher average cholesterol than that of the US at the =0.05 level. (Be sure to right down all steps, as in the lecture notes, and interpret the meaning of the test!)
e.How would your answer in (d) change if you used an =0.01 level?
116 |
282 |
213 |
252 |
150 |
219 |
221 |
289 |
226 |
265 |
234 |
256 |
208 |
263 |
155 |
206 |
201 |
283 |
208 |
142 |
279 |
155 |
231 |
143 |
218 |
243 |
162 |
125 |
212 |
149 |
250 |
184 |
210 |
236 |
241 |
294 |
196 |
226 |
184 |
208 |
278 |
144 |
263 |
245 |
212 |
205 |
208 |
151 |
266 |
224 |
276 |
203 |
222 |
199 |
272 |
197 |
176 |
241 |
269 |
217 |
206 |
239 |
238 |
237 |
187 |
203 |
283 |
156 |
283 |
138 |
234 |
198 |
172 |
277 |
172 |
157 |
267 |
160 |
243 |
189 |
In: Math
A recent college graduate is planning to take the first three actuarial certification exams over the course of the next year, the first one in June, second in July and third in August. If she fails any, she will not take the remaining exams. The probability she passes the first is 0.9. Given that she passes the first exam, she has a 0.75 chance of passing the second and given that she passes both the first and second, she has a 0.65 chance of passing the third. (a) What is the probability she passes all three exams? (b) Given that she did not pass all three exams, what is the probability that she failed the second? (c) Given that she did not pass all three exams, what is the probability that she failed the third?
In: Math
In: Math
Cream cheese is sold in cans that have a net weight of 8 ounces. The weights are normally distributed with a mean of 8.025 ounces and a standard deviation of 0.125 ounces. You take a sample of 36 cans. Compute the probability that the sample would have a mean 7.995 ounces or more.
(( NO HANDWRITING PLEASE ))
In: Math
Each statement represents a scenario in which a linear transformation has occurred. Select the correct statements regarding the standard deviation of the variables after the linear transformation.
-A malfunctioning machine produces a particular part with a mean length of 30 in and a standard deviation of 1 in. If a second part with a consistent length of 2 in is added to the end of the first part, then the standard deviation of the total part lengths will be equal to 3 in.
-The distribution of heights of adult males in the United States has a standard deviation of 4 in. If these heights in inches are converted to feet, then the standard deviation of heights will be 13 ft.
-Prices on a menu at a particular restaurant have a mean cost of $10 and a standard deviation of $4. If the restaurant decides to raise its prices by 50%, then the standard deviation of the new prices will be $6.
-For a particular set of daily TV-watching data, the average number of hours of TV watched per day is 3 hrs, and the standard deviation is 2 hrs. If these daily results are translated to weekly TV-watching results, the standard deviation for the total number of hours of TV watched per week remains unchanged from the standard deviation of 2 hrs.
-The final times (in minutes) for a high school foot race are distributed with a mean of 20 min and a standard deviation of 4 min. The person charged with keeping track of time realized that he started the stopwatch 1 minlate for all runners. Thus, he decides to add 1 min to everyone's time. The standard deviation of the new final times will remain unchanged at 4 min.
In: Math
Jim Mead is a veterinarian who visits a Vermont farm to examine prize bulls. In order to examine a bull, Jim first gives the animal a tranquilizer shot. The effect of the shot is supposed to last an average of 65 minutes, and it usually does. However, Jim sometimes gets chased out of the pasture by a bull that recovers too soon, and other times he becomes worried about prize bulls that take too long to recover. By reading journals, Jim has found that the tranquilizer should have a mean duration time of 65 minutes, with a standard deviation of 15 minutes. A random sample of 14 of Jim's bulls had a mean tranquilized duration time of close to 65 minutes but a standard deviation of 22 minutes. At the 1% level of significance, is Jim justified in the claim that the variance is larger than that stated in his journal? Find a 95% confidence interval for the population standard deviation.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ2 = 225; H1: σ2 < 225
Ho: σ2 = 225; H1: σ2 ≠ 225
Ho: σ2 > 225; H1: σ2 = 225
Ho: σ2 = 225; H1: σ2 > 225
(b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)
What are the degrees of freedom?
What assumptions are you making about the original distribution?
We assume a exponential population distribution.
We assume a binomial population distribution.
We assume a normal population distribution.
We assume a uniform population distribution.
(c) Find or estimate the P-value of the sample test statistic.
P-value > 0.100
0.050 < P-value < 0.100
0.025 < P-value < 0.050
0.010 < P-value < 0.025
0.005 < P-value < 0.010
P-value < 0.005
(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?
Since the P-value > α, we fail to reject the null hypothesis.
Since the P-value > α, we reject the null hypothesis.
Since the P-value ≤ α, we reject the null hypothesis.
Since the P-value ≤ α, we fail to reject the null hypothesis.
(e) Interpret your conclusion in the context of the application.
At the 1% level of significance, there is insufficient evidence to conclude that the variance of the duration times of the tranquilizer is larger than stated in the journal.
At the 1% level of significance, there is sufficient evidence to conclude that the variance of the duration times of the tranquilizer is larger than stated in the journal.
(f) Find the requested confidence interval for the population standard deviation. (Round your answers to two decimal place.)
lower limit |
min |
upper limit |
min |
Interpret the results in the context of the application.
We are 95% confident that σ lies above this interval.
We are 95% confident that σ lies outside this interval.
We are 95% confident that σ lies below this interval.
We are 95% confident that σ lies within this interval.
In: Math
Begin this discussion by first stating your intended future career. Then give an example of a proportion that applies to two Populations for which you would like to do a Hypothesis Test in your future career. In your Hypothesis Test you will be testing the difference between these two Population proportions. Your discussion MUST include for the two target Populations along with the Population characteristic that your proportion is measuring. As shown in the text your Null and Alternative Hypotheses MUST include a symbol for each of the two Population Proportions along with the relational operator that describes the difference being tested between these two parameters as stated in your discussion.
In: Math
3. A machine is used to fill containers with orange juice. Fill volume can be assumed to be normally distributed. A random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99. (a) Construct and run an appropriate test of hypothesis in order that manufacturer can be sure that the mean net contents exceed 12 oz. What conclusions can be drawn from the data (use α = 0.01)? (b) Construct a 95% two-sided confidence interval on the mean fill volume. (c) Does the assumption of normality seem appropriate for the fill volume data? Why or why not? |
In: Math
hello i wanted to know the process for finding the z value when area is given and also vice versa using spss software
In: Math
Problem 16-05 (Algorithmic)
A major traffic problem in the Greater Cincinnati area involves traffic attempting to cross the Ohio River from Cincinnati to Kentucky using Interstate 75. Let us assume that the probability of no traffic delay in one period, given no traffic delay in the preceding period, is 0.8 and that the probability of finding a traffic delay in one period, given a delay in the preceding period, is 0.65. Traffic is classified as having either a delay or a no-delay state, and the period considered is 30 minutes.
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Statistics indicate that 4% of males and 0.3% of females are color-blind.Assume thata population is half female.What is the probability that a randomly selected person isfemale, given that the person is color-blind?
In: Math
1. The marketing manager of a large supermarket chain would like to use shelf space to predict the sales of a specialty pet food. Data are collected from a random sample of 8 equal-sized stores, with the following results:
Store |
Shelf Space (in square feet) |
Weekly Sales (in Dollars) |
1 |
4 |
120 |
2 |
4 |
150 |
3 |
8 |
160 |
4 |
8 |
180 |
5 |
12 |
200 |
6 |
16 |
210 |
7 |
16 |
240 |
8 |
20 |
260 |
Use Excel to find the regression results for this problem. Include Excel results with your submission.
a. at the 0.05 level of significance, is there evidence of a linear relationship between shelf space and weekly sales?
b. construct a 95% confidence interval estimate of the population slope, β1.
In: Math
A manufacturer of electronic components is interested in determining the lifetime of a certain type of battery. A sample, in hours of life, is as follows 123, 116, 122, 110, 175, 126, 125, 111, 118, 117.
Calculate: Sample Mean, Sample Median, 20% trimmed Mean, Quartiles: Q1, Q2 and Q3
Interquartile range: IQR = Q3 –Q1 , Lower bound = Q1 - 1.5(Q3 - Q1), Upper bound = Q3 + 1.5(Q3 - Q1).
Maximum, Minimum, Range = Max – Min, Sample Variance, Sample Standard deviation. Stem and leaf, Dot plot.
In: Math