Questions
A factorial experiment was designed to test for any significant differences in the time needed to...

A factorial experiment was designed to test for any significant differences in the time needed to perform English to foreign language translations with two computerized language translators. Because the type of language translated was also considered a significant factor, translations were made with both systems for three different languages: Spanish, French, and German. Use the following data for translation time in hours.

Language
Spanish French German
System 1 6 11 10
10 15 14
System 2 5 18 14
9 20 20

Test for any significant differences due to language translator system (Factor A), type of language (Factor B), and interaction. Use  = .05.

  1. Complete the following ANOVA table (to 2 decimals, if necessary). Round p-value to four decimal places.
    Source of Variation Sum of Squares Degrees of Freedom Mean Square F p-value
    Factor A
    Factor B
    Interaction
    Error
    Total

  2. The p-value for Factor A is
    1. less than .005
    2. between .005 and .0125
    3. between .0125 and .025
    4. between .025 and .05
    5. greater than .05
  1. What is your conclusion with respect to Factor A?
    1. Factor A is significant
    2. Factor A is not significant
  2. The p-value for Factor B is
    1. less than .005
    2. between .005 and .0125
    3. between .0125 and .025
    4. between .025 and .05
    5. greater than .05

      What is your conclusion with respect to Factor B?
      1. Factor B is significant
      2. Factor B is not significant
  3. The p-value for the interaction of factors A and B is
    1. less than .005
    2. between .005 and .0125
    3. between .0125 and .025
    4. between .025 and .05
    5. greater than .05

      What is your conclusion with respect to the interaction of Factors A and B?
      1. The interaction of factors A and B is significant
      2. The interaction of factors A and B is not significant

In: Math

Using the simple random sample of weights of women from a data​ set, we obtain these...

Using the simple random sample of weights of women from a data​ set, we obtain these sample​ statistics: n equals = 35 and x =146.25 lb. Research from other sources suggests that the population of weights of women has a standard deviation given by sigma σ equals = 30.78 lb. a. Find the best point estimate of the mean weight of all women. b. Find a 95​% confidence interval estimate of the mean weight of all women.

In: Math

Let A, B, and C be independent random variables, uniformly distributed over [0,6],[0,11], and [0,2] respectively....

Let A, B, and C be independent random variables, uniformly distributed over [0,6],[0,11], and [0,2] respectively. What is the probability that both roots of the equation Ax^2+Bx+C=0 are real?

In: Math

Someone claims that the mean number of sick days that employees in New Jersey take per...

Someone claims that the mean number of sick days that employees in New Jersey take per year is 5.3. To look into that claim, you take a representative sample of 78 employees in New Jersey and find that the mean number of sick days is 5.5 in the sample. The population standard deviation is 1.6.

Part (a)   

Given that the sample mean is different from the claimed population mean, does that show that the claim in H0 is false? Explain your answer.

Part (b)

Carry out a hypothesis test for the claim above (with α = 0.05) using the 6-step procedure.

Part (c)   

Carry out a hypothesis test for the claim above (with α = 0.05) using the p-value method.

In: Math

Professor Fair believes that extra time does not improve grades on exams. He randomly divided a...

Professor Fair believes that extra time does not improve grades on exams. He randomly divided a group of 300 students into two groups and gave them all the same test. One group had exactly 1 hour in which to finish the test, and the other group could stay as long as desired. The results are shown in the following table. Test at the 0.01 level of significance that time to complete a test and test results are independent.

Time A B C F Row Total
1 h 24 43 61 10 138
Unlimited 16 45 83 18 162
Column Total 40 88 144 28 300

(i) Give the value of the level of significance.


State the null and alternate hypotheses.

H0: Time to take a test and test score are not independent.
H1: Time to take a test and test score are independent. H0: The distributions for a timed test and an unlimited test are the same.
H1: The distributions for a timed test and an unlimited test are different.     H0: The distributions for a timed test and an unlimited test are different.
H1: The distributions for a timed test and an unlimited test are the same. H0: Time to take a test and test score are independent.
H1: Time to take a test and test score are not independent.


(ii) Find the sample test statistic. (Round your answer to two decimal places.)


(iii) Find or estimate the P-value of the sample test statistic.

P-value > 0.100 0.050 < P-value < 0.100     0.025 < P-value < 0.050 0.010 < P-value < 0.025 0.005 < P-value < 0.010 P-value < 0.005


(iv) Conclude the test.

Since the P-value < α, we reject the null hypothesis. Since the P-value is ≥ α, we do not reject the null hypothesis.     Since the P-value < α, we do not reject the null hypothesis. Since the P-value ≥ α, we reject the null hypothesis.


(v) Interpret the conclusion in the context of the application.

At the 1% level of significance, there is insufficient evidence to claim that time to do a test and test results are not independent. At the 1% level of significance, there is sufficient evidence to claim that time to do a test and test results are not independent.    

In: Math

In a poll of 525 human rescourse professionals, 49.5% said that body piercings and tattoos were...

In a poll of 525 human rescourse professionals, 49.5% said that body piercings and tattoos were big red flags. Complete parts a through d below.

A. Among the 525 how many of them said it’s a red flag

B. Construct a 99% confidence interval estimate of the proportion of all professionals believing that it’s a red flag

C. Repeat part B with a 80% confidence level

D. Is B or C a wider interval and why?

In: Math

"A random survey of 927 adults in California found that 63% of them say they are...

"A random survey of 927 adults in California found that 63% of them say they are likely to sleep when they stay home sick."

e. Construct a 95% confidence interval for p. (Be sure to follow the whole process).

f. Is it plausible to say that 70% of all California adults would sleep when they stay home sick?

g. Perform a hypothesis test to determine if more than 60% of adults would sleep when they stay home sick.

h. If we made an error here, then would it be a Type I or a Type II error?

In: Math

The director of a Masters of Public Administration Program is preparing a brochure to promote the...

The director of a Masters of Public Administration Program is preparing a brochure to promote the

program. She would like to include in the brochure the average grade point average (GPA) of first-

year students in the program, but since time is pressing she decides to estimate this figure with a

sample of ten students (GPAs are normally distributed). The GPAs are listed below. What is the best

estimate of the average GPA for all first-year students? With 95% confidence, can the director

conclude the average GPAs for first-year students is a B or better (3.0 on a 4.0 scale)?

2.8

3.6

3.4

2.5

2.2

2.6

4.0

3.1

2.7

3.5

In: Math

In a recent issue of Consumer Reports, Consumers Union reported on their investigation of bacterial contamination...

In a recent issue of Consumer Reports, Consumers Union reported on their investigation of bacterial contamination in packages of name brand chicken sold in supermarkets.

Packages of Tyson and Perdue chicken were purchased. Laboratory tests found campylobacter contamination in 35 of the 75 Tyson packages and 22 of the 75 Perdue packages.

Question 1. Find 90% confidence intervals for the proportion of Tyson packages with contamination and the proportion of Perdue packages with contamination (use 3 decimal places in your answers).

lower bound of Tyson interval
upper bound of Tyson interval
lower bound of Perdue interval
upper bound of Perdue interval

Question 2. The confidence intervals in question 1 overlap. What does this suggest about the difference in the proportion of Tyson and Perdue packages that have bacterial contamination? One submission only; no exceptions

The overlap suggests that there is no significant difference in the proportions of packages of Tyson and Perdue chicken with bacterial contamination.

Even though there is overlap, Tyson's sample proportion is higher than Perdue's so clearly Tyson has the greater true proportion of contaminated chicken.    

Question 3. Find the 90% confidence interval for the difference in the proportions of Tyson and Perdue chicken packages that have bacterial contamination (use 3 decimal places in your answers).

lower bound of confidence interval
upper bound of confidence interval

Question 4. What does this interval suggest about the difference in the proportions of Tyson and Perdue chicken packages with bacterial contamination? One submission only; no exceptions

Tyson's sample proportion is higher than Perdue's so clearly Tyson has the greater true proportion of contaminated chicken.

Natural sampling variation is the only reason that Tyson appears to have a higher proportion of packages with bacterial contamination.    

We are 90% confident that the interval in question 3 captures the true difference in proportions, so it appears that Tyson chicken has a greater proportion of packages with bacterial contamination than Perdue chicken.

Question 5. The results in questions 2 and 4 seem contradictory. Which method is correct: doing two-sample inference, or doing one-sample inference twice? One submission only; no exceptions

one-sample inference twice

two-sample inference    

Question 6. Why don't the results agree? 2 submission only; no exceptions

Different methods were used in the two samples to detect bacterial contamination.

The one- and two-sample procedures for analyzing the data are equivalent; the results differ in this problem only because of natural sampling variation.    

If you attempt to use two confidence intervals to assess a difference between proportions, you are adding standard deviations. But it's the variances that add, not the standard deviations. The two-sample difference-of-proportions procedure takes this into account.

Tyson chicken is sold in less sanitary supermarkets.

In: Math

Use R to complete the following questions. You should include your R code, output and plots...

Use R to complete the following questions. You should include your R code, output and plots in your answer.

Two methods of generating a standard normal random variable are:

a. Take the sum of 5 uniform (0,1) random numbers and scale to have mean 0 and standard deviation 1. (Use the properties of the uniform distribution to determine the required transformation).

b. Generate a standard uniform and then apply inverse cdf function to obtain a normal random variate (Hint: use qnorm).


QUESTION 1.

For each method generate 10,000 random numbers and check the distribution using

a. Normal probability plot

b. Mean and standard deviation

c. The proportion of the data lying within the theoretical 2.5 and 97.5 percentiles and the 0.5 and 99.5 percentiles. (Hint: The ifelse function will be useful)

In: Math

Suppose a hypertension trial is mounted and 18 participants are randomly assigned to one of the...

Suppose a hypertension trial is mounted and 18 participants are randomly assigned to one of the comparison treatments. Each participant takes the assigned medication and their systolic blood pressure (SBP) is recorded after 6 months on the assigned treatment. Is there a difference in mean SBP among the three treatment groups at the 5% significance level? The data are as follows.  

Standard Treatment

Placebo

New Treatment

124

134

114

111

143

117

133

148

121

125

142

124

128

150

122

115

160

128

What is total variance (or as what it's called in ANOVA, "MStotal")?

  

A. 13.8

B.   189.6

C. 3222.9

D. 179.1

In: Math

A child development specialist is interested in learning if a new learning program increases students’ memory....

A child development specialist is interested in learning if a new learning program increases students’ memory. 15 Subjects learned a list of 50 words. Learning performance was measured using a recall test. Students were initially tested and then tested again after using the new program. Below is the number of words remembered by each student.

Student #                    Score 1                  Score 2

         1                              24                           26          

                2                              17                           24

                3                              32                           31

                4                              14                           17

                5                              16                           17

                6                              22                           25

                7                              26                           25

                8                              19                           24

                9                              19                           22

               10                             22                           23

              11                          21                           26

              12                             25                           28

             13                             16                           19

            14                         24                           23

            15                           18                           22

Did the learning program significantly improve the student’s ability to recall words? Report standard error of means, df, obtained and critical t, and whether you would accept or reject the null hypothesis.

In: Math

Iconic memory is a type of memory that holds visual information for about half a second...

Iconic memory is a type of memory that holds visual information for about half a second (0.5 seconds). To demonstrate this type of memory, participants were shown three rows of four letters for 50 milliseconds. They were then asked to recall as many letters as possible, with a 0-, 0.5-, or 1.0-second delay before responding. Researchers hypothesized that longer delays would result in poorer recall. The number of letters correctly recalled is given in the table.

Delay Before Recall
0 0.5 1
6 5 7
13 2 2
10 10 5
7 5 5
8 8 4
10 6 1

(a) Complete the F-table. (Round your values for MS and F to two decimal places.)

Source of Variation SS df MS F
Between groups
Within groups (error)
Total


(b) Compute Tukey's HSD post hoc test and interpret the results. (Assume alpha equal to 0.05. Round your answer to two decimal places.)

The critical value is_______ for each pairwise comparison.


Which of the comparisons had significant differences? (Select all that apply.)

A.) The null hypothesis of no difference should be retained because none of the pairwise comparisons demonstrate a significant difference.

B.) Recall following no delay was significantly different from recall following a half second delay.

C.) Recall following a half second delay was significantly different from recall following a one second delay.

D.) Recall following no delay was significantly different from recall following a one second delay.

In: Math

People claim that women say more words per day than men. Estimates claim that a woman...

  1. People claim that women say more words per day than men. Estimates claim that a woman uses roughly 20,000 words per day, while a man uses approximately 7,000. To investigate this, a researcher recorded conversations of male college students over a 5-day period. The results are as follows:

7220

13932

4727

10419

9258

9717

10728

5265

12215

9944

7979

12252

9307

9086

10780

3357

The researcher believes that many use more than 7,000 words per day.

  1. State the problem in your own words.
  2. Create a plan for testing the researcher’s claim. Be sure to state the null and alternate hypotheses.
  3. Carry out the appropriate hypothesis test. Begin by finding the sample mean and standard deviation. Give the value of the t statistic and give the p-value (or an estimate).
  4. Formulate the statistical conclusion in terms of the null hypothesis and a practical conclusion. You may compare the p-value to 0.05 to determine if the null hypothesis should be rejected. When the p-value is less than 0.05, we reject the null hypothesis. Otherwise, we fail to reject the null.

In: Math

Many high school students take the SAT's twice; once in their Junior year and once in...

Many high school students take the SAT's twice; once in their Junior year and once in their Senior year. The Senior year scores (x) and associated Junior year scores (y) are given in the table below. This came from a random sample of 35 students. Use this data to test the claim that retaking the SAT increases the score on average by more than 25 points. Test this claim at the 0.10 significance level.



(a) The claim is that the mean difference (x - y) is greater than 25 (μd > 25). What type of test is this?

This is a two-tailed test.This is a left-tailed test.    This is a right-tailed test.


(b) What is the test statistic? Round your answer to 2 decimal places.
t

d

=

(c) Use software to get the P-value of the test statistic. Round to 4 decimal places.
P-value =

(d) What is the conclusion regarding the null hypothesis?

reject H0fail to reject H0    


(e) Choose the appropriate concluding statement.

The data supports the claim that retaking the SAT increases the score on average by more than 25 points.There is not enough data to support the claim that retaking the SAT increases the score on average by more than 25 points.    We reject the claim that retaking the SAT increases the score on average by more than 25 points.We have proven that retaking the SAT increases the score on average by more than 25 points.

    
    
Senior Score (x) Junior Score (y) (x - y)
1265 1238 27
1150 1110 40
1225 1174 51
1081 1070 11
1264 1224 40
1220 1205 15
1108 1102 6
1321 1274 47
1317 1264 53
1177 1167 10
1102 1063 39
1291 1252 39
1235 1195 40
1091 1060 31
1097 1062 35
1101 1073 28
1278 1222 56
1214 1187 27
1100 1061 39
1101 1066 35
1240 1217 23
1216 1183 33
1120 1091 29
1295 1273 22
1131 1095 36
1293 1263 30
1174 1122 52
1212 1193 19
1124 1116 8
1114 1084 30
1109 1087 22
1177 1134 43
1151 1076 75
1289 1267 22
1061 1064 -3

In: Math