Questions
Tully Tyres sells cheap imported tyres. The manager believes its profits are in decline. You have...

Tully Tyres sells cheap imported tyres. The manager believes its profits are in decline. You have just been hired as an analyst by the manager of Tully Tyres to investigate the expected profit over the next 12 months based on current data.

•Monthly demand varies from 100 to 200 tyres – probabilities shown in the partial section of the spreadsheet below, but you have to insert formulas to ge the cumulative probability distribution which can be used in Excel with the VLOOKUP command.
•The average selling price per tyre follows a discrete uniform distribution ranging from $160 to $180 each. This means that it can take on equally likely integer values between $160 and $180 – more on this below.
•The average profit margin per tyre after covering variable costs follows a continuous uniform distribution between 20% and 30% of the selling price.
•Fixed costs per month are $2000.

(a)Using Excel set up a model to simulate the next 12 months to determine the expected average monthly profit for the year. You need to have loaded the Analysis Toolpak Add-In to your version of Excel. You must keep the data separate from the model. The model should show only formulas, no numbers whatsoever except for the month number.

Tully Tyres
Data
Probability Cumulative Prob Demand Selling price $160 $180
0.05 100 Monthly fixed cost $2000
0.10 120 Profit margin 20% 30%
0.20 140
0.30 160
0.25 180
0.10 200
1
Model
Month RN1 Demand Selling price RN2 Profit margin Fixed cost Profit
1 0.23297 #N/A $180 0.227625 0.2

The first random number (RN 1) is to simulate monthly demands for tyres.
•The average selling price follows a discrete uniform distribution and can be determined by the function =RANDBETWEEN(160,180) in this case. But of course you will not enter (160,180) but the data cell references where they are recorded.
•The second random number (RN 2) is used to help simulate the profit margin.
•The average profit margin follows a continuous uniform distribution ranging between 20% and 30% and can be determined by the formula =0.2+(0.3-0.2)*the second random number (RN 2). Again you do not enter 0.2 and 0.3 but the data cell references where they are located. Note that if the random number is high, say 1, then 0.3-0.2 becomes 1 and when added to 0.2 it becomes 0.3. If the random number is low, say 0, then 0.3-0.2 becomes zero and the profit margin becomes 0.2.
•Add the 12 monthly profit figures and then find the average monthly profit.

Show the data and the model in two printouts: (1) the results, and (2) the formulas. Both printouts must show the grid (ie., row and column numbers) and be copied from Excel and pasted into Word. See Spreadsheet Advice in Interact Resources for guidance.

(b)Provide the average monthly profit to Ajax Tyres over the 12-month period.

(c)You present your findings to the manager of Ajax Tyres. He thinks that with market forces he can increase the average selling price by $40 (ie from $200 to $220) without losing sales. However he does suggest that the profit margin would then increase from 22% to 32%.

He has suggested that you examine the effect of these changes and report the results to him. Change the data accordingly in your model to make the changes and paste the output in your Word answer then write a report to the manager explaining your conclusions with respect to his suggestions. Also mention any reservations you might have about the change in selling prices.

The report must be dated, addressed to the Manager and signed off by you.
(Word limit: No more than 150 words)

In: Math

My factory makes thermometers and I am testing if they are accurate. I will test this...

My factory makes thermometers and I am testing if they are accurate. I will test this by measuring the average temperatures of different thermometers in ice-water. The null hypothesis is that the true average reading of thermometers from this factory in ice-water is 0◦ against the two-sided alternative. I will construct a p-value. What will the value of the p-value mean? If you wish, you can pretend the value of the p-value will be 0.06.

In: Math

Parking lots; A survey of autos parked in student and staff lots at a large university...

Parking lots; A survey of autos parked in student and staff lots at a large university classified the brands by country of origin, as seen in the table

                               Driver

                       Student      Staff

American         104            105

European         33               11

Asian                55               48

a) What percentage of all cars surveyed wcre American?

b) What percentage of the American cars were owned by students?

c) What percen of the students owned American

d) What is the marginal distribution of origin ?

e) What is the condition of drivers American cars?

f) Do you think that the origin of the car is independent of the type of driver? Explain

In: Math

A population proportion is 0.5. A sample of size 200 will be taken and the sample...

A population proportion is 0.5. A sample of size 200 will be taken and the sample proportion will be used to estimate the population proportion. Use z-table.

Round your answers to four decimal places. Do not round intermediate calculations.

a. What is the probability that the sample proportion will be within +/-0.02 of the population proportion?

b. What is the probability that the sample proportion will be within +/-0.07 of the population proportion?

In: Math

Practice Problems SIBNUM work age RELSTAT DRKFRQ Mean 1.75 9.65 22.6 2.13 3.04 Std. Deviation 1.117...

Practice Problems

SIBNUM

work

age

RELSTAT

DRKFRQ

Mean

1.75

9.65

22.6

2.13

3.04

Std. Deviation

1.117

9.20

2.4

1.124

0.77

Minimum

0

0

2

1

1

Maximum

6

40

45

6

5

  1. Using the 50-35-14-2 rule, sketch each of the distributions above.

  1. For each variable, calculate the value of X at the 40th %ile and the 61nd %ile.

  1. For each variable, calculate the %ile corresponding to a score of 4 on the variable.

  1. 2013 SAT subscores for the nation are given below.

A) For the composite, what score do you need to qualify for Mensa, which requires you to be in the top 2% of the population?

B) Oddly enough, Phillip scored exactly 500 on each subscore… what percent of students scored higher in each subscore? What percent of students scored LOWER than his composite score of 1000?

C) MU admissions accept a 1080 composite score as sufficient to demonstrate potential success as a student. What percent of students qualify?

D) The MU honor’s college accepts incoming freshmen with a composite SAT of 1380 (if you were ALSO top 15%ile of high school class). What percent of students qualify with that composite score?

Subscore

Reading

Math

Writing

Composite

Mean

413

556

468

1010

SD

114

117

113

231

In: Math

State Alabama Alaska Arizona Arkansas California Connecticut Delaware District of Columbia Florida Idaho Illinois Indiana Iowa...

State

Alabama
Alaska
Arizona
Arkansas
California
Connecticut
Delaware
District of Columbia
Florida
Idaho
Illinois
Indiana
Iowa
Kansas
Kentucky
Louisiana
Maine
Maryland
Massachusetts
Michigan
Minnesota
Mississippi
Missouri
Montana
Nebraska
Nevada
New Jersey
New Mexico
New York
North Dakota
Ohio
Oklahoma
Pennsylvania
Rhode Island
South Carolina
South Dakota
Tennessee
Texas
Utah
Vermont
Washington
West Virginia
Wisconsin
Wyoming

Cigarettes

1820
3034
2582
1824
2860
3110
3360
4046
2827
2010
2791
2618
2212
2184
2344
2158
2892
2591
2692
2496
2206
1608
2756
2375
2332
4240
2864
2116
2914
1996
2638
2344
2378
2918
1806
2094
2008
2257
1400
2589
2117
2125
2286
2804

Can you create a pie chart for “Cigarettes”? If so, display it. If this cannot be created in Minitab, explain why.

Can you create a bar chart for “Cigarettes”? Is so, display it. If this cannot be created in Minitab, explain why.

Concerning the descriptive statistics for “Cigarettes,” what should “N*” or “N missing” be? (Minitab won’t tell you this answer, but you can figure it out.)

In: Math

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone...

The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 64% of the cases. Suppose the 15 cases reported today are representative of all complaints. a-1. How many of the problems would you expect to be resolved today? (Round your answer to 2 decimal places.) Number of Problems a-2. What is the standard deviation? (Round your answer to 4 decimal places.) Standard Deviation b. What is the probability 8 of the problems can be resolved today? (Round your answer to 4 decimal places.) Probability c. What is the probability 8 or 9 of the problems can be resolved today? (Round your answer to 4 decimal places.) Probability d. What is the probability more than 10 of the problems can be resolved today? (Round your answer to 4 decimal places.) Probability

In: Math

suppose the proportion of all college students who have used marijuana in the past 6months is...

suppose the proportion of all college students who have used marijuana in the past 6months is p=0.40 in a class of 200 students that are representative of all college students would it be unusual for the proportion who have used marijuana in the past 6 months to be less than 0.32? Explain how you made your decision in this question





In: Math

In the M/M/1 system, derive P0 by equating the rate at which customers arrive with the...

In the M/M/1 system, derive P0 by equating the rate at which customers arrive with the rate at which they depart

In: Math

Using the most appropriate type of graph to present weekly closing price of the Bitcoin and...

Using the most appropriate type of graph to present weekly closing price of the Bitcoin and provide a general description. Hint: What are the main features of this graph, is there a trend? [Topic 1]                                  

Calculate the weekly return and construct a histogram. Does the data appear normally distributed?   Is there evidence of outliers? Hint: the formula for a return is (Current Price – Previous price)/Previous price multiplied by 100 [Topics 1-3]                                                         

Calculate and interpret the three aspects of Descriptive Analysis, Location, Shape and Spread, for weekly return. [Topic 1]

What is the empirical probability of a loss? [Topic 2]

Repeat the same steps (steps 1-4 above) for three share prices in the Australia Securities Exchange: BHP Billiton (BHP) from the mining sector, Commonwealth Bank of Australia (CBA) from the bank sector, and Telstra Corporation (TLS) from the telecom sector.

Construct a 95% confidence interval of the return to Bitcoin, and interpret the interval. How does your interval change if the level of confidence is 90% and 95% respectively, and explain why. [Topics 6-7]

Construct a 95% confidence interval of the return to BHP, CBA, and TLS respectively. [Topics 6-7]

An investment advisor claimed that the return to Bitcoin is 4% while the returns to other three shares are no different from zero. Do you agree? Justify your reasoning using a two-tailed hypothesis test approach at the significance level of 5%. [Topic 8]

Data source: Yahoo Finance
Data frenquecy: weekly closing price
Data measurement unit: AU$
Short Name Full Name
BIT Bitcoin
BHP BHP Billiton
CBA Commonwealth Bank of Australia
TLS Telstra Corporation
Date BIT CBA BHP TLS
15/6/14 690 80.9812 33.5932 5.17
22/6/14 665 81.031 34.0324 5.26
29/6/14 661.2 81.5084 35.107 5.34
6/7/14 692.14 80.7923 35.1163 5.33
13/7/14 614.12 80.832 35.8732 5.43
20/7/14 600.84 81.8366 36.4432 5.45
27/7/14 665.93 82.3737 35.8919 5.44
3/8/14 687.76 79.6982 35.2658 5.39
10/8/14 584.97 80.7624 36.4899 5.58
17/8/14 543 80.1756 35.3219 5.71
24/8/14 510.53 80.8818 34.266 5.56
31/8/14 537.92 80.8619 33.3128 5.64
7/9/14 562.43 79.7977 33.4437 5.54
14/9/14 424.44 77.3907 33.154 5.41
21/9/14 460.15 74.8544 31.9205 5.31
28/9/14 353.36 76.237 31.2571 5.39
5/10/14 481.64 74.3969 30.1918 5.29
12/10/14 485.55 76.1275 31.2103 5.38
19/10/14 449.98 78.3455 31.528 5.5
27/10/14 419.9 80.0463 31.7336 5.63
3/11/14 440.98 82.314 32.2289 5.77
10/11/14 463.96 81.3294 31.0702 5.8
17/11/14 448.09 79.6584 29.6218 5.65
24/11/14 471.5 80.285 28.8929 5.69
1/12/14 476 81.2001 28.4257 5.67
8/12/14 419.55 81.2995 26.5942 5.7
15/12/14 434.97 83.2589 27.0801 5.89
22/12/14 443.46 84.4624 27.0708 5.91
29/12/14 362.8 85.278 27.6034 5.97
5/1/15 350.09 85.5763 27.2483 6.07
12/1/15 290.02 83.1197 25.2766 6.22
19/1/15 480.51 85.7653 27.4539 6.34
26/1/15 289.48 88.8486 27.3418 6.5
2/2/15 309.59 92.479 29.4816 6.59
9/2/15 323.9 92.648 30.061 6.59
16/2/15 323.5 89.7239 30.1825 6.61
23/2/15 354.85 91.4247 31.444 6.37
2/3/15 351.34 90.5991 30.5002 6.28
9/3/15 405.86 90.8279 27.809 6.2
16/3/15 349.82 95.8009 28.6593 6.37
23/3/15 380 93.8316 28.7341 6.38
29/3/15 320.56 93.8913 28.2388 6.32
5/4/15 379.94 93.6227 28.1641 6.28
12/4/15 365 91.5838 28.0052 6.14
19/4/15 300 91.6037 29.9489 6.32
26/4/15 324.68 88.4408 30.3694 6.24
3/5/15 295.91 82.1947 29.248 6.17
10/5/15 345.03 84.2933 30.36 6.2
17/5/15 327.36 82.6621 29.25 6.2
24/5/15 369.69 84.6315 29.59 6.22
31/5/15 328.8 79.8573 27.9 6.01
7/6/15 320.5 80.9812 27.9 6.03
14/6/15 312.87 84.0148 28.41 6.13
21/6/15 325.62 86.1831 27.5 6.2
28/6/15 362.18 86.193 26.59 6.13
5/7/15 443.58 85.3277 26.65 6.21
12/7/15 412.15 87.5059 27.1 6.42
19/7/15 401.96 85.3476 25.27 6.36
26/7/15 415 87.0882 26.45 6.49
2/8/15 362.04 80.8619 25.93 6.29
9/8/15 329.08 81.6775 25.32 6.08
16/8/15 357.53 75.59 24.1 6.07
23/8/15 320.4 76.36 25.49 5.82
30/8/15 349.46 72.15 24.69 5.61
6/9/15 330.8 75.13 23.71 5.55
13/9/15 323.27 75.83 24.46 5.65
20/9/15 346.48 71.44 22.93 5.67
27/9/15 350.66 73.39 22.6 5.62
4/10/15 339.59 75.53 25.6 5.64
11/10/15 373.53 76.55 25 5.44
18/10/15 400.01 77.35 24.59 5.58
26/10/15 477.69 76.73 23.02 5.4
2/11/15 551.39 76.59 22.7 5.31
9/11/15 471.79 75.76 20.23 5.14
16/11/15 476.89 79.83 20.5 5.41
23/11/15 518.39 80.12 18.77 5.4
30/11/15 540.58 80.22 17.93 5.41
7/12/15 605.46 78.95 17.2 5.2
14/12/15 616.24 81.57 16.87 5.48
21/12/15 581.21 83.32 18.34 5.46
28/12/15 582.38 85.53 17.86 5.61
4/1/16 642.2 79.42 16.35 5.3
11/1/16 554.28 78.88 15.07 5.33
18/1/16 573.92 76.56 15.26 5.54
25/1/16 532.58 78.67 15.35 5.63
1/2/16 529.39 76.6 16.2 5.65
8/2/16 567.05 73.33 15.09 5.57
15/2/16 609.61 73.43 16.61 5.28
22/2/16 606.68 70.72 15.59 5.27
29/2/16 548.07 75.74 17.67 5.13
7/3/16 543.69 76.37 17.61 5.16
14/3/16 584.58 78.16 18.1 5.22
21/3/16 589.97 74.82 17 5.25
27/3/16 585.82 72.99 16.97 5.26
3/4/16 555.66 70.76 16.18 5.16
10/4/16 574.93 75 19.28 5.24
17/4/16 616.19 75.04 20.36 5.4
24/4/16 588.28 73.89 20.68 5.36
1/5/16 655.87 74.35 18.46 5.6
8/5/16 642.67 77.39 18.2 5.68
15/5/16 612.75 78.12 18.85 5.66
22/5/16 701.27 78.9 19.37 5.67
29/5/16 788.69 75.75 18.53 5.59
5/6/16 903.09 75.49 18.8 5.46
12/6/16 1053.05 72.03 18.08 5.31
19/6/16 905.65 72.57 17.54 5.35
26/6/16 897.08 73.83 19.09 5.58
3/7/16 871.54 72.41 19.05 5.59
10/7/16 895.01 75.94 20.37 5.75
17/7/16 893.52 77.14 19.3 5.8
24/7/16 823.18 77.35 19.52 5.77
31/7/16 787.93 76.15 20.03 5.66
7/8/16 750.5 76.01 20.68 5.45
14/8/16 760 73.45 21.29 5.48
21/8/16 770 73.26 20.88 5.3
28/8/16 815.6 70.91 19.85 5.12
4/9/16 814 70.87 20.78 5.06
11/9/16 834.99 72.24 20.09 5.1
18/9/16 786.2 73.4 21.53 5.19
25/9/16 819.42 72.4 22.38 5.18
2/10/16 815.57 74.38 23.3 5.01
9/10/16 854 74.58 22.54 5.08
16/10/16 861.02 74.9 23.04 5.04
23/10/16 925 72.75 22.98 4.95
31/10/16 925.83 70.99 22.27 4.9
7/11/16 931.9 75.78 24.94 4.72
14/11/16 1000.52 76.86 24.1 4.93
21/11/16 1002.97 78.17 26.5 5.03
28/11/16 1024.27 78.6 25.02 4.95
5/12/16 1075.2 80.67 25.98 4.99
12/12/16 1106.2 81.06 25 4.91
19/12/16 1235.94 82.5 24.63 5.04
26/12/16 1381.4 82.41 25.06 5.1
2/1/17 1244.41 84.13 25.5 5.26
9/1/17 1095.16 83.86 26.33 5.22
16/1/17 1223.2 81.58 26.35 5.14
23/1/17 1238.34 82.98 27.52 5.11
30/1/17 1347.74 81.68 26.2 5.08
6/2/17 1341.48 82.9 25.88 5.16
13/2/17 1375.95 85.39 26.64 4.84
20/2/17 1553.46 83.02 25.06 4.81
27/2/17 1690.27 83.2 25.34 4.59
6/3/17 1649.1 84.5 23.67 4.64
13/3/17 1362.27 84.77 24.84 4.76
20/3/17 1277.61 83.38 24.26 4.59
26/3/17 1472.88 85.91 24.04 4.66
2/4/17 1612.83 84.77 24.59 4.56
9/4/17 1588.75 86.25 24.31 4.16
16/4/17 1683.46 85.64 24.04 4.23
23/4/17 1781.71 87.4 23.72 4.22
30/4/17 2196.67 84.4 22.62 4.4
7/5/17 2595.07 81.67 23.75 4.36
14/5/17 2860.85 80.23 24.28 4.43
21/5/17 3094.79 80.14 24.01 4.48
28/5/17 3493.27 80.38 24.07 4.49
4/6/17 3889.46 79.19 23.54 4.37
11/6/17 3588.86 81.86 22.99 4.38
18/6/17 3503.31 81.25 22.41 4.35
25/6/17 3342.76 82.81 23.28 4.3
2/7/17 3415.51 82.13 24.59 4.32
9/7/17 2510 83.12 25.13 4.3
16/7/17 3541.5 83.97 24.49 4.1
23/7/17 3529.74 83.76 25.33 4.11
30/7/17 4060.53 80.72 25.72 4.07
6/8/17 5318.14 80.5 25.55 4.15
13/8/17 5298.76 79.09 25.39 3.9
20/8/17 5620 77.72 26.68 3.92
27/8/17 6018.4 75.48 27.42 3.67
3/9/17 5319.46 73.24 27.29 3.7
10/9/17 4593.05 76.28 26.26 3.65
17/9/17 4625.38 76.62 25.95 3.58
24/9/17 5565.36 75.25 25.78 3.49
1/10/17 5887.35 76.3 26.61 3.44
8/10/17 7226.76 76.66 26.36 3.52
15/10/17 7713.93 78.97 26.68 3.52
22/10/17 8018.65 78.24 26.59 3.55
30/10/17 9692.39 77.79 27.69 3.5
6/11/17 7924.89 80.85 28.07 3.46
13/11/17 10693.55 80.92 27.12 3.45
20/11/17 12297.99 80.57 27.97 3.48
27/11/17 15024.19 79.17 27.58 3.42
4/12/17 21184.87 79.62 27.17 3.69
11/12/17 25986.55 79.94 27.71 3.69
18/12/17 18939.79 80.39 29.1 3.66
25/12/17 19050.74 80.34 29.57 3.63
1/1/18 22862.21 81.16 30.58 3.73
8/1/18 19041.51 80.88 31.53 3.74
15/1/18 15148.37 79.83 30.69 3.57
22/1/18 14445.12 78.65 30.85 3.56
29/1/18 10225.82 80.79 30.81 3.67
5/2/18 10382.72 76.25 29.13 3.49
12/2/18 13338.45 74.02 31.52 3.43
19/2/18 12300.72 75.46 30.68 3.48
26/2/18 14763.94 75.73 29.63 3.27
5/3/18 12143.73 76.87 28.32 3.44
12/3/18 10646.88 75.34 29.16 3.35
19/3/18 11039.19 72.81 28.77 3.22
25/3/18 8835.98 72.31 28.21 3.14
1/4/18 9130.39 73.49 28.64 3.1
8/4/18 10654.32 73.16 29.73 3.1
15/4/18 11357.21 72.06 30.86 3.08
22/4/18 12432.76 71.54 31.11 3.15
29/4/18 12682.62 72.76 31.49 3.24
6/5/18 11560.03 70.53 33.16 3.2
13/5/18 11318.46 70.5 34.08 2.85
20/5/18 9752.02 69.87 33.07 2.87
27/5/18 10233.1 68.7 33.08 2.78
3/6/18 8956.31 69.37 34.07 2.77
10/6/18 8717.19 68.98 33.56 2.94
17/6/18 9008.23 69.88 32.36

2.77

In: Math

4. The mean score on a standardized test is 540 with a standard deviation of 55....

4. The mean score on a standardized test is 540 with a standard deviation of 55. What percent of students taking the test scored above 625? (nearest hundredth)

5. True or False. A z-score is the number of standard deviations from the median.

6. True or False. A z-score cannot be negative.

7. True or False. If the standard deviation is small, the data values are very varied.

8. True or False.   The standard error of the mean is smaller than the standard deviation of the population.  

9. True or False.   The z a/2  value cannot be a negative number.

In: Math

In a clinical​ trial, 20 out of 823 patients taking a prescription drug daily complained of...

In a clinical​ trial, 20 out of 823 patients taking a prescription drug daily complained of flulike symptoms. Suppose that it is known that 1.9​% of patients taking competing drugs complain of flulike symptoms. Is there sufficient evidence to conclude that more than 1.9​% of this​ drug's users experience flulike symptoms as a side effect at the alpha equals 0.01 level of​ significance?

In: Math

A medical researcher wants to compare the pulse rates of smokers and non-smokers. He believes that...

A medical researcher wants to compare the pulse rates of smokers and non-smokers. He believes that the pulse rate for smokers and non-smokers is different and wants to test this claim at the 0.05 level of significance. The researcher checks 72 smokers and finds that they have a mean pulse rate of 75, and 81 non-smokers have a mean pulse rate of 72. The standard deviation of the pulse rates is found to be 6 for smokers and 9 for non-smokers. Let μ1 be the true mean pulse rate for smokers and μ2 be the true mean pulse rate for non-smokers.

Step 1 of 4: State the null and alternative hypotheses for the test.

Step 2 of 4: Compute the value of the test statistic. Round your answer to two decimal places.

Step 3 of 4: Determine the decision rule for rejecting the null hypothesis H0H0. Round the numerical portion of your answer to two decimal places.

....reject H0 if

Step 4 of 4: Make the decision for the hypothesis test.

....reject null hypothesis...fail to reject null hypothesis

In: Math

An agronomist is conducting a field experiment to identify the best management practice for minimizing spread...

An agronomist is conducting a field experiment to identify the best management practice for minimizing spread of a certain plant disease in corn. He compares four different management strategies designed so that they would reduce the spread of the disease. He has set up a field study with a total of 25 experimental plots planted with corn and with 5 treatments (4 disease prevention treatments and a control treatment). Each treatment has been assigned to 5 randomly selected plots. Plant biomass was then measured from each plot at the end of the experiment. The ANOVA table and the treatment means are shown below.

ANOVA:

  

DF

Sum of Squares

Mean Square

F-value

Treatment

4

345

86

2.4

Error

20

714

36

    

a)(10 points) Conduct all pairwise comparisons between the treatment means using LSD, (=0.05). Present the results using letters assigned to treatment means (Use letters in the column Letters for part a) in the below table)

             

Show LSD value:

b)(10 points) Conduct all pairwise comparisons between the treatment means using Tukey’s HSD (=0.05). Present the results using letters assigned to treatment means. (Use the column Letters for part b) in the below table)

Show HSD value:

                                                NAME:____________________________

c)(10 points) Did you expect to see differences in conclusions obtained using the two methods (LSD and Tukey’s)? Which method would you use for this analysis? For full credit, provide an explanationof your choice.

             

Treatment

Mean values of the plant biomass

Letters for part a)

Letters for part b)

Management 1

6.6

Management 2

14.6

Management 3

31.4

Management 4

24.1

Control (no management)

2.2

Step by step procedure by hand, possibly shortest way to go about this problem would be ideal. thank you in advance

In: Math

3) Here are the weights (kg) of 15 male lions and 17 female lions (all adults)....

3) Here are the weights (kg) of 15 male lions and 17 female lions (all adults). Construct a correct parallel boxplot for these data. males: 176.0 175.7 174.2 185.1 168.1 165.1 177.3 172.4 188.3 162.4 167.3 154.6 176.8 181.8 182.5 females: 105.8 98.1 128.3 114.7 113.6 135.0 125.3 113.5 110.7 109.2 104.1 153.4 105.2 130.4 129.8 111.6 135.0 PLOT ON PAPER PLEASE AND SHOW WORK

In: Math