Based on data from a college, scores on a certain test are normally distributed with a mean of 1532 1532 and a standard deviation of 316 316. LOADING... Click the icon to view the table with standard scores and percentiles for a normal distribution. a. Find the percentage of scores greater than 1848 1848. nothing % (Round to two decimal places as needed.) b. Find the percentage of scores less than 900 900. nothing % (Round to two decimal places as needed.) c. Find the percentage of scores between 1374 1374 and 2006 2006. nothing % (Round to two decimal places as needed.)
Standard score Percent
-3.0 0.13
-2.5 0.62
-2 2.28
-1.5 6.68
-1 15.87
-0.9 18.41
-0.5 30.85
-0.1 46.02
0 50.00
0.10 53.98
0.5 69.15
0.9 81.59
1 84.13
1.5 93.32
2 97.72
2.5 99.38
3 99.87
3.5 99.98
In: Math
Part 2: Analyzing Study Time per Week
You spoke with your instructor and she claimed that the average number of hours that you should study has to be more than 5 hours per week which will help you achieve an above average grade on any subject. She also suggested as a practice that you can test her claim and let her know what your conclusion is. So you decided to contact your peers and gather information to conduct a hypothesis to test your instructors claim.
Questions:
In: Math
Compute the confidence interval for the difference of two population means. Show your work.
Sample Mean 1= 17
Population standard deviation 1= 15
n1= 144
Sample Mean 2= 26
Population Standard Deviation 2= 13
n2 = 121
Confidence Level= 99
In: Math
The variance in drug weights is critical in the pharmaceutical industry. For a specific drug, with weights measured in grams, a sample of 20 units provided a sample variance of s^2 = 0.49.
a) construct a 90% confidence interval estimate for the population variance
b) construct a 90% confidence interval estimate of the population standard deviation
In: Math
Find the t-value such that the area in the right tail is 0.025 with 9 degrees of freedom. nothing (Round to three decimal places as needed.) (b) Find the t-value such that the area in the right tail is 0.25 with 29 degrees of freedom. nothing (Round to three decimal places as needed.) (c) Find the t-value such that the area left of the t-value is 0.15 with 7 degrees of freedom. [Hint: Use symmetry.] nothing (Round to three decimal places as needed.) (d) Find the critical t-value that corresponds to 60% confidence. Assume 13 degrees of freedom. nothing (Round to three decimal places as needed.)
In: Math
1. Utilizing the sample size chart, what would be the minimum sample size for the following situations?
a. one sample test ES = .8,*a = .05/2, 1- B = .90
b. two sample test (independent) ES = .8, *a = .01, 1- B = .80
c. two sample test (independent) ES = .2, *a = .05/2, 1- B = .95
d. one sample test ES = .5, *a = .01, 1- B = .80
e. two sample test ES = .8, *a = .05/2, 1- B = .95
f. one sample test ES = .5, *a = .01, 1- B = .90
In: Math
The eigenvalue is a measure of how much of the variance of the observed variables a factor explains. Any factor with an eigenvalue ≥1 explains more variance than a single observed variable, so if the factor for socioeconomic status had an eigenvalue of 2.3 it would explain as much variance as 2.3 of the three variables. This factor, which captures most of the variance in those three variables, could then be used in another analysis. The factors that explain the least amount of variance are generally discarded. How do we determine how many factors are useful to retain?
In: Math
Consider the following results for two independent random samples taken from two populations.
Sample 1:
n1 = 40
x̅1 = 13.9
σ1 = 2.3
Sample 2:
n2 = 30
x̅2 = 11.1
σ2 = 3.4
What is the point estimate of the difference between the two population means? (to 1 decimal)
Provide a 90% confidence interval for the difference between the two population means (to 2 decimals).
Provide a 95% confidence interval for the difference between the two population means (to 2 decimals).
In: Math
Last rating period, the percentages of viewers watching several channels between 11 P.M. and 11:30 P.M. in a major TV market were as follows: WDUX (News) WWTY (News) WACO (Cheers Reruns) WTJW (News) Others 15% 21% 25% 17% 22% Suppose that in the current rating period, a survey of 2,000 viewers gives the following frequencies: WDUX (News) WWTY (News) WACO (Cheers Reruns) WTJW (News) Others 280 401 504 354 461
(a) Show that it is appropriate to carry out a chi-square test using these data. Each expected value is ≥
(b) Test to determine whether the viewing shares in the current rating period differ from those in the last rating period at the .10 level of significance. (Round your answer to 3 decimal places.) χ2 χ 2 H0. Conclude viewing shares of the current rating period from those of the last.
In: Math
The weight of trout in a fish farm follows the distribution N(200,502). A trout is randomly selected. (a) What is the probability that its weight does not exceed 175g? (b) What is the probability that its weight is greater than 230g? (c) What is the probability that its weight is between 225g and 275g? (d) What is the probability that out of eight trout selected randomly from the fish farm, less than three of them will not weigh more than 175g?
In: Math
At a particular amusement park, most of the live characters have
height requirements of a minimum of 57 in. and a maximum of 63 in.
A survey found that women's heights are normally distributed with
a mean of 62.4 in. and a standard deviation of 3.6 in. The survey
also found that men's heights are normally distributed with a mean
of 68.3 in. and a standard deviation of 3.6 in.
Part 1:
Find the percentage of men meeting the height requirement.
The percentage of men who meet the height requirement is
____?____.
(Round answer to nearest hundredth of a percent - i.e.
23.34%)
What does the result suggest about the genders of the people who
are employed as characters at the amusement park?
Since most men___?___ the height requirement, it
likely that most of the characters are ___?___
.
(Use "meet" or "do not meet" for the first blank and "men" or
"women" for the second blank.)
Part 2: I was able to solve part 2 on my
own.
If the height requirements are changed to exclude only the tallest
50% of men and the shortest 5% of men, what are the new height
requirements?
The new height requirements are a minimum of 62.4
in. and a maximum of 68.3 in.
(Round to one decimal place as needed.)
In: Math
GRADED PROBLEM SET #5
Answer each of the following questions completely. There are a total of 20 points possible in the assignment.
In: Math
Part 1: Analyzing your College’s School Graduation Rate
You recently went through your college website and some information there got your attention. There was a claim that your college has a 77% graduation rate. You thought it would be interesting to check the validity of this statement since these days you are reading about hypothesis testing in your Statistics online course. You contacted the research department and got access to the data for the last graduation and out of 200 students 165 graduated.
To complete Case 1 please answer the following questions:
In: Math
The probability that a random gift box in Overwatch (PC game) has one of the character skins you want is .1. Suppose you get a gift box every game you play, and that you play until you have obtained 2 of these skins. a. What is the probability that you play until you have x boxes that do not have the desired prize? Write down the formula as well as the notation for the pdf. b. What is the probability that you play exactly 5 times? Show the R code. c. What is the probability that you play at most 5 times? Show the R code. d. How many boxes without the desired skins do you expect to get? Show the formula
In: Math
Describe the sampling distribution of ModifyingAbove p with caret. Assume the size of the population is 15 comma 000. nequals200, pequals0.4 Choose the phrase that best describes the shape of the sampling distribution of ModifyingAbove p with caret below. A. Approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10. B. Not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis less than 10. C. Approximately normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10. D. Not normal because n less than or equals 0.05 Upper N and np left parenthesis 1 minus p right parenthesis greater than or equals 10. Determine the mean of the sampling distribution of ModifyingAbove p with caret. mu Subscript ModifyingAbove p with caret Baseline equals nothing (Round to one decimal place as needed.) Determine the standard deviation of the sampling distribution of ModifyingAbove p with caret. sigma Subscript ModifyingAbove p with caret Baseline equals nothing (Round to three decimal places as needed.)
In: Math