Questions
A psychologist is interested in constructing a 95% confidence interval for the proportion of people who...

A psychologist is interested in constructing a 95% confidence interval for the proportion of people who accept the theory that a person's spirit is no more than the complicated network of neurons in the brain. 74 of the 715 randomly selected people who were surveyed agreed with this theory. Round answers to 4 decimal places where possible. a. With 95% confidence the proportion of all people who accept the theory that a person's spirit is no more than the complicated network of neurons in the brain is between and . b. If many groups of 715 randomly selected people are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population proportion of all people who accept the theory that a person's spirit is no more than the complicated network of neurons in the brain and about percent will not contain the true population proportion.

In: Math

What approaches are there by which coefficients are estimated for linear and logistic regression? How is...

What approaches are there by which coefficients are estimated for linear and logistic regression?

How is the deviance affected when an explanatory term is omitted (i know that it increases, but surely there is more to it?)

In what situations would we use Beta-binomial regression?

In: Math

Please discuss the purpose of hypothesis testing. In your response, provide an example of a null...

Please discuss the purpose of hypothesis testing. In your response, provide an example of a null hypothesis and alternative hypothesis. Why is hypothesis testing important for researchers?

Note: The response needs to be at a minimum of 350 words typed please.

In: Math

Calculate the weekly return for BIT and construct a histogram in Excel. Does the data on...

  1. Calculate the weekly return for BIT and construct a histogram in Excel. Does the data on return rates appear normally distributed? On the basis of z-scores do you find evidence of outliers? Hint: the formula for a return is (Current Price – Previous price)/Previous price multiplied by 100.
  2. Date BIT
    11/3/13 52.06
    18/3/13 53.84
    25/3/13 99.99
    1/4/13 139.23
    8/4/13 113.07
    15/4/13 123.93
    22/4/13 141.36
    29/4/13 126.5
    6/5/13 120.39
    13/5/13 125.5
    20/5/13 142.52
    27/5/13 137.88
    3/6/13 115.66
    10/6/13 120.98
    17/6/13 125.28
    24/6/13 111.97
    1/7/13 97.54
    8/7/13 114.95
    15/7/13 96.5
    22/7/13 92
    29/7/13 99.95
    5/8/13 125.49
    12/8/13 104.1
    19/8/13 109.53
    26/8/13 158.75
    2/9/13 136.12
    9/9/13 147.87
    16/9/13 143.09
    23/9/13 142.08
    30/9/13 140.24
    7/10/13 151.77
    14/10/13 193.52
    21/10/13 213.89
    28/10/13 233.5
    4/11/13 331.05
    11/11/13 547.08
    18/11/13 974.55
    25/11/13 1191.99
    2/12/13 1016.27
    9/12/13 1027.82
    16/12/13 781.78
    23/12/13 889.11
    30/12/13 999
    6/1/14 1037.92
    13/1/14 977.1
    20/1/14 1000
    27/1/14 928.99
    3/2/14 850
    10/2/14 740
    17/2/14 728.37
    24/2/14 650
    3/3/14 674.73
    10/3/14 669.53
    17/3/14 646.83
    24/3/14 560
    31/3/14 518.31
    7/4/14 475
    14/4/14 567.54
    21/4/14 469
    28/4/14 502.16
    5/5/14 456
    12/5/14 510.9
    19/5/14 648.66
    26/5/14 752.71
    2/6/14 750
    9/6/14 671.71
    16/6/14 690
    23/6/14 665
    30/6/14 661.2
    7/7/14 692.14
    14/7/14 614.12
    21/7/14 600.84
    28/7/14 665.93
    4/8/14 687.76
    11/8/14 584.97
    18/8/14 543
    25/8/14 510.53
    1/9/14 537.92
    8/9/14 562.43
    15/9/14 424.44
    22/9/14 460.15
    29/9/14 353.36
    6/10/14 481.64
    13/10/14 485.55
    20/10/14 449.98
    27/10/14 419.9
    3/11/14 440.98
    10/11/14 463.96
    17/11/14 448.09
    24/11/14 471.5
    1/12/14 476
    8/12/14 419.55
    15/12/14 434.97
    22/12/14 443.46
    29/12/14 362.8
    5/1/15 350.09
    12/1/15 290.02
    19/1/15 480.51
    26/1/15 289.48
    2/2/15 309.59
    9/2/15 323.9
    16/2/15 323.5
    23/2/15 354.85
    2/3/15 351.34
    9/3/15 405.86
    16/3/15 349.82
    23/3/15 380
    30/3/15 320.56
    6/4/15 379.94
    13/4/15 365
    20/4/15 300
    27/4/15 324.68
    4/5/15 295.91
    11/5/15 345.03
    18/5/15 327.36
    25/5/15 369.69
    1/6/15 328.8
    8/6/15 320.5
    15/6/15 312.87
    22/6/15 325.62
    29/6/15 362.18
    6/7/15 443.58
    13/7/15 412.15
    20/7/15 401.96
    27/7/15 415
    3/8/15 362.04
    10/8/15 329.08
    17/8/15 357.53
    24/8/15 320.4
    31/8/15 349.46
    7/9/15 330.8
    14/9/15 323.27
    21/9/15 346.48
    28/9/15 350.66
    5/10/15 339.59
    12/10/15 373.53
    19/10/15 400.01
    26/10/15 477.69
    2/11/15 551.39
    9/11/15 471.79
    16/11/15 476.89
    23/11/15 518.39
    30/11/15 540.58
    7/12/15 605.46
    14/12/15 616.24
    21/12/15 581.21
    28/12/15 582.38
    4/1/16 642.2
    11/1/16 554.28
    18/1/16 573.92
    25/1/16 532.58
    1/2/16 529.39
    8/2/16 567.05
    15/2/16 609.61
    22/2/16 606.68
    29/2/16 548.07
    7/3/16 543.69
    14/3/16 584.58
    21/3/16 589.97
    28/3/16 585.82
    4/4/16 555.66
    11/4/16 574.93
    18/4/16 616.19
    25/4/16 588.28
    2/5/16 655.87
    9/5/16 642.67
    16/5/16 612.75
    23/5/16 701.27
    30/5/16 788.69
    6/6/16 903.09
    13/6/16 1053.05
    20/6/16 905.65
    27/6/16 897.08
    4/7/16 871.54
    11/7/16 895.01
    18/7/16 893.52
    25/7/16 823.18
    1/8/16 787.93
    8/8/16 750.5
    15/8/16 760
    22/8/16 770
    29/8/16 815.6
    5/9/16 814
    12/9/16 834.99
    19/9/16 786.2
    26/9/16 819.42
    3/10/16 815.57
    10/10/16 854
    17/10/16 861.02
    24/10/16 925
    31/10/16 925.83
    7/11/16 931.9
    14/11/16 1000.52
    21/11/16 1002.97
    28/11/16 1024.27
    5/12/16 1075.2
    12/12/16 1106.2
    19/12/16 1235.94
    26/12/16 1381.4
    2/1/17 1244.41
    9/1/17 1095.16
    16/1/17 1223.2
    23/1/17 1238.34
    30/1/17 1347.74
    6/2/17 1341.48
    13/2/17 1375.95
    20/2/17 1553.46
    27/2/17 1690.27
    6/3/17 1649.1
    13/3/17 1362.27
    20/3/17 1277.61
    27/3/17 1472.88
    3/4/17 1612.83
    10/4/17 1588.75
    17/4/17 1683.46
    24/4/17 1781.71
    1/5/17 2196.67
    8/5/17 2595.07
    15/5/17 2860.85
    22/5/17 3094.79
    29/5/17 3493.27
    5/6/17 3889.46
    12/6/17 3588.86
    19/6/17 3503.31
    26/6/17 3342.76
    3/7/17 3415.51
    10/7/17 2510
    17/7/17 3541.5
    24/7/17 3529.74
    31/7/17 4060.53
    7/8/17 5318.14
    14/8/17 5298.76
    21/8/17 5620
    28/8/17 6018.4
    4/9/17 5319.46
    11/9/17 4593.05
    18/9/17 4625.38
    25/9/17 5565.36
    2/10/17 5887.35
    9/10/17 7226.76
    16/10/17 7713.93
    23/10/17 8018.65
    30/10/17 9692.39
    6/11/17 7924.89
    13/11/17 10693.55
    20/11/17 12297.99
    27/11/17 15024.19
    4/12/17 21184.87
    11/12/17 25986.55
    18/12/17 18939.79
    25/12/17 19050.74
    1/1/18 22862.21
    8/1/18 19041.51
    15/1/18 15148.37
    22/1/18 14445.12
    29/1/18 10225.82
    5/2/18 10382.72
    12/2/18 13338.45
    19/2/18 12300.72
    26/2/18 14763.94
    5/3/18 12143.73
    12/3/18 10646.88
    19/3/18 11039.19
    26/3/18 8835.98
    2/4/18 9130.39
    9/4/18 10654.32
    16/4/18 11357.21
    23/4/18 12432.76
    30/4/18 12682.62
    7/5/18 11560.03
    14/5/18 11318.46
    21/5/18 9752.02
    28/5/18 10233.1
    4/6/18 8956.31
    11/6/18 8717.19
    18/6/18 8252.91
    25/6/18 8489.05
    2/7/18 8953.63
    9/7/18 8555.52
    16/7/18 9947.28
    23/7/18 11114.06
    30/7/18 9559.81
    6/8/18 8719.77
    13/8/18 8920.44
    20/8/18 9172.49
    27/8/18 10081.22
    3/9/18 8802.43
    10/9/18 9058.83
    17/9/18 9118.22
    24/9/18 9139.68
    1/10/18 9264.69
    8/10/18 8735.74
    15/10/18 9005.48
    22/10/18 9019.61
    29/10/18 8908.97
    5/11/18 8841.39
    12/11/18 7579.24
    19/11/18 5435.57
    26/11/18 5586.65
    3/12/18 4914.89
    10/12/18 4440.44
    17/12/18 5596.18
    24/12/18 5456.26
    31/12/18 5686.6
    7/1/19 4908.14
    14/1/19 4962.34
    21/1/19 4942.09
    28/1/19 4734.24
    4/2/19 5132.33
    11/2/19 5083.2
    18/2/19 5213.99
    25/2/19 5340.09
    4/3/19 5555.14
    11/3/19 5626.45
    18/3/19 5617.53
    25/3/19 5738.09
    1/4/19 7253.71
    8/4/19 7214.66
    15/4/19 7437.26
    22/4/19 7405.25
    29/4/19 8120.41
    6/5/19 9962.31
    13/5/19 11884.94
    20/5/19 12617.35
    27/5/19 12606.94
    3/6/19 10983.83
    10/6/19 12961.26
    17/6/19 15572.87
    24/6/19 15180.16
    1/7/19 16368.05
    8/7/19 14657.08
    15/7/19 15057.73
    22/7/19 13891.59
    29/7/19 16132.89
    5/8/19 17037.56
    12/8/19 15348.79

In: Math

The data frame TestScores in the PASWR packages gives the test grades of 20 students taking...

The data frame TestScores in the PASWR packages gives the test grades of 20 students taking a basic statistic course.

a) Use the function EDA() on the data. Can normality be assumed?
b) Perform the test for normal distribution.

Use R to solve and show R code

In: Math

A randomized controlled experiment has 50 participants, of whom 20 are women. A simple random sample...

A randomized controlled experiment has 50 participants, of whom 20 are women. A simple random sample of 25 participants are assigned to the treatment group and the remainder to the control group.

a) Say whether the following statement is true or false. If it is true, provide a math expression for the chance. If it is false, provide math expressions for the two chances.

?(the treatment group has 16 women) = ?(the control group has 16 women)P(the treatment group has 16 women) = P(the control group has 16 women)

b) Say whether the following statement is true or false, and justify your answer.

The event "the treatment group has 16 women" is independent of the event "the control group has 16 women".

c) Write a math expression for the chance that there are at least six women in both groups.

[Hint: This can be done by just thinking about the women in one of the groups. Any other way will prove quite a bit harder.]

In: Math

The method of tree ring dating gave the following years A.D. for an archaeological excavation site....

The method of tree ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution. 1285 1250 1187 1236 1268 1316 1275 1317 1275

(a) Use a calculator with mean and standard deviation keys to find the sample mean year x and sample standard deviation s. (Round your answers to the nearest whole number.)

x = ____A.D.

s = _____yr

(b) Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (Round your answers to the nearest whole number.)

lower limit A.D.

upper limit A.D.

________________________________________________________________________

How much does a sleeping bag cost? Let's say you want a sleeping bag that should keep you warm in temperatures from 20°F to 45°F. A random sample of prices ($) for sleeping bags in this temperature range is given below. Assume that the population of x values has an approximately normal distribution.

50 90 95 110 85 60 30 23 100 110
105 95 105 60 110 120 95 90 60 70

(a) Use a calculator with mean and sample standard deviation keys to find the sample mean price x and sample standard deviation s. (Round your answers to two decimal places.)

x = $
s = $


(b) Using the given data as representative of the population of prices of all summer sleeping bags, find a 90% confidence interval for the mean price μ of all summer sleeping bags. (Round your answers to two decimal places.)

lower limit     $
upper limit     $

In: Math

The accompanying data set provides the closing prices for four stocks and the stock exchange over...

The accompanying data set provides the closing prices for four stocks and the stock exchange over 12 days:

Date A B C D Stock Exchange
9/3/10 127.37 18.34 21.03 15.51 10432.45
9/7/10 127.15 18.18 20.44 15.51 10334.67
9/8/10 124.92 17.88 20.57 15.82 10468.41
9/9/10 127.35 17.95 20.52 16.02 10498.61
9/10/10 128.37 17.82 20.42 15.98 10563.84
9/13/10 128.36 18.64 21.16 16.21 10616.07
9/14/10 128.61 18.83 21.29 16.22 10565.83
9/15/10 130.17 18.79 21.69 16.25 10627.97
9/16/10 130.34 19.16 21.76 16.36 10595.39
9/17/10 129.37 18.82 21.69 16.26 10517.99
9/20/10 130.97 19.12 21.75 16.41 10661.11
9/21/10 131.16 19.02 21.55 16.57 10687.95

With the help of the Excel Exponential Smoothing tool, I was able to forecast each of the stock prices using simple exponential smoothing with a smoothing constant of 0.3 (ie, damping factor of 0.7). I was also able to calculate the MAD of each of the stocks:

MAD of Stock A = 1.32

MAD of Stock B = 0.37

MAD of Stock C = 0.41

MAD of Stock D = 0.26

MAD of Stock Exchange = 83.85

Help me to calculate the Mean Square Error (MSE) of the stocks.

In: Math

Inter State Moving and Storage Company is setting up a control chart to monitor the proportion...

Inter State Moving and Storage Company is setting up a control chart to monitor the proportion of residential moves that result in written complaints due to late delivery, lost items, or damaged items. A sample of 60 moves is selected for each of the last 12 months. The number of written complaints in each sample is 8, 9, 3, 6, 1, 5, 10, 7, 7, 8, 8, and 10.

1. Insert the mean proportion defective, UCL, and LCL. (Round your intermediate calculations and final answers to 2 decimal places.)

Mean proportion defective
UCL
LCL


2. Does it appear that the number of complaints is out of control for any of the months? Yes or No?

Thank you!

In: Math

Overproduction of uric acid in the body can be an indication of cell breakdown. This may...

Overproduction of uric acid in the body can be an indication of cell breakdown. This may be an advance indication of illness such as gout, leukemia, or lymphoma.† Over a period of months, an adult male patient has taken eleven blood tests for uric acid. The mean concentration was x = 5.35 mg/dl. The distribution of uric acid in healthy adult males can be assumed to be normal, with σ = 1.89 mg/dl. (a) Find a 95% confidence interval for the population mean concentration of uric acid in this patient's blood. What is the margin of error? (Round your answers to two decimal places.)

lower limit

upper limit

margin of error

(b) Find the sample size necessary for a 95% confidence level with maximal margin of error E = 1.10 for the mean concentration of uric acid in this patient's blood. (Round your answer up to the nearest whole number.)
_______ blood tests

In: Math

Total plasma volume is important in determining the required plasma component in blood replacement therapy for...

Total plasma volume is important in determining the required plasma component in blood replacement therapy for a person undergoing surgery. Plasma volume is influenced by the overall health and physical activity of an individual. Suppose that a random sample of 44 male firefighters are tested and that they have a plasma volume sample mean of x = 37.5 ml/kg (milliliters plasma per kilogram body weight). Assume that σ = 7.00 ml/kg for the distribution of blood plasma. (a) Find a 99% confidence interval for the population mean blood plasma volume in male firefighters. What is the margin of error? (Round your answers to two decimal places.)

lower limit

upper limit

margin of error

(b) What conditions are necessary for your calculations? (Select all that apply.)

A)the distribution of weights is uniform

B)σ is unknown

C)the distribution of weights is normal

D) n is large

E) σ is known

(c) Interpret your results in the context of this problem. select one

A).The probability that this interval contains the true average blood plasma volume in male firefighters is 0.01.

B)1% of the intervals created using this method will contain the true average blood plasma volume in male firefighters.

C)99% of the intervals created using this method will contain the true average blood plasma volume in male firefighters.

D)The probability that this interval contains the true average blood plasma volume in male firefighters is 0.99.

(d) Find the sample size necessary for a 99% confidence level with maximal margin of error E = 2.40 for the mean plasma volume in male firefighters. (Round up to the nearest whole number.)

_______male firefighters

In: Math

A farmer must decide what crops to grow on a 300-hectare tract of land. He can...

A farmer must decide what crops to grow on a 300-hectare tract of land. He can grow oats, wheat, or barley, which yield 50, 100 and 80 kg/hectare (respectively) and sell for $1.00, $0.80, and $0.60 per kg (respectively). Production costs (fertilizer, labor, etc.) are $40, $50, and $40 per hectare for growing oats, wheat and barley, respectively. Government regulations restrict the farmer to a maximum of 150 hectares of wheat and his crop rotation schedule requires that he plants at least 50 hectares in oats and 50 hectares in barley. Because of his storage arrangements, the farmer wants the number of hectares of oats to be equal to or less than half the number of hectares of barley.

a. Formulate algebraically the linear programming model of this problem that will maximize the farmer profit (i.e. revenue – cost) and help him/her decides what crops to grow on his/her land (i.e. define the decision variables, objective function, constraints).

b. Formulate this same linear programming problem on a spreadsheet and SOLVE using Excel solver (Provide a printout of the corresponding “Excel Spreadsheet” and the “Answer Report”). Include “managerial statements” that communicate the results of the analyses.

In: Math

When a truckload of apples arrives at a packing​ plant, a random sample of 175 is...

When a truckload of apples arrives at a packing​ plant, a random sample of 175 is selected and examined for​ bruises, discoloration, and other defects. The whole truckload will be rejected if more than 6​% of the sample is unsatisfactory. Suppose that in fact 10% of the apples on the truck do not meet the desired standard. What is the probability that the shipment will be accepted​ anyway?

​P(accepted)=??

​(Round to three decimal places as​ needed.)

In: Math

You are playing blackjack at a casino and have a hand with a total of 19....

You are playing blackjack at a casino and have a hand with a total of 19. You decide to stay. The dealer flips over their facedown card to reveal a total of 16. What is the probability that you win? Assume you are playing with an infinite deck.

A.8/13

B.9/13

C.10/13

D.11/13

In: Math

Explain the advantages and disadvantages of bar charts and pie charts. Include discussion of the type...

Explain the advantages and disadvantages of bar charts and pie charts. Include discussion of the type of data that is best suited for each and justify why this is the best form of data for bar and pie charts by providing specific examples.

In: Math