The 4M company has a work center with a single turret lathe. Jobs arrive at this work center according to a Poisson process at a mean rate of 2 jobs per day, The lathe processing time has an exponential distribution with a mean of 0.25 day per job.
a) On average, how many jobs are waiting.in the work center?
b) On average, how long will a job stay in the center?
c).Since each job takes a big space, the waiting jobs are currently waiting in the warehouse. The production manager is proposing to add a storage space near the lathe. If an arriving job will have at least 90% chance waiting near the lathe, how big should be the storage space near the lathe?
In: Math
Why is it “harder” to find a significant outcome (all other things being equal) when the research hypothesis is being tested at the .01 rather than the .05 level of significance?
In: Math
How can Chi Square test for independence be used to evaluate test re-test reliability?
In: Math
The American Bar Association reports that the mean length of time for a hearing in juvenile court is 25 minutes. Assume that this this your population mean. As a lawyer who practices in the juvenile court, you think that the average hearing much shorter than this. You take a sample of 20 other lawyers who do juvenile work and ask them how long their last case in juvenile court was. The mean hearing length for this sample of 20 was 23 minutes., with a standard deviation of 6. Test the null hypotheses that the population mean is 25 minutes against the alternative that is less than 25. Set your alpha at .05.
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A copier cost $200 for each repair call, after 3 calls they are free (For example 1 call= $200, 3 or more calls = $600). The following chart shows the probability of how many repair calls you will have in 1 year. Questions 36-37
pls show work
|
# Repairs |
0 |
1 |
2 |
3 or more |
|
Probability |
0.30 |
0.41 |
0.20 |
0.10 |
36. What is the expected repair call costs for 1 year?
$150.00
$200.00
$206.00
$220.00
$300.00
37. What is the probability that one repair call cost will be more than $200 for 1 year?
.70
.40
.30
.20
.10
38. The daily high temperature of Los Angeles in the month of December is normally distributed with a mean of 58 degrees Fahrenheit and a standard deviation of 2 degrees fahrenheit. What percent of high temperatures are between 60 and 64?
68%
84%
15.85%
16%
None of the above
39. If P(A) = 0.38, P(B) = 0.83, and P (A ∩ B) = 0.57; then P(A U B) =
1.21
0.64
0.78
1.78
None of the above
In: Math
Consider the probability that at least 36 out of 298 cell phone calls will be disconnected. Choose the best description of the area under the normal curve that would be used to approximate binomial probability.
The option are
Area to the right of 35.5
Area to the right of 36.5
Area to the left of 35.5
Area to the left of 36.5
Area between 35.5 and 36.5
In: Math
In: Math
In: Math
Must solve in R code
Question 2
The random variable X is a payout table of a casino slot machine. The probability mass function is given:
X -5 0 2
10 20 40 60
1000
Probability 0.65 0.159
0.10 0.05 0.02 0.01
0.01 0.001
Please simulate the results for playing the slot machine 10,000,000
times. Find the mean of these 10,000,000 simulated payout outcomes
.
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When one uses an ANOVA, explain the difference between “main effects” and “interaction effects”. Give examples of each.
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According to a survey in a country, 18% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. (b) What is the probability that in a random sample of 900 adults, more than 22% do not own a credit card? The probability is what.? (Round to four decimal places as needed.) Interpret this probability. If 100 different random samples of 900 adults were obtained, one would expect nothing to result in more than 22% not owning a credit card. (Round to the nearest integer as needed.).
(c) What is the probability that in a random sample of 900 adults, between 17% and 22% do not own a credit card?
Interpret this probability. If 100 different random samples of 900 adults were obtained, one would expect ? to result in between 17% and 22% not owning a credit card.
(Round to the nearest integer as needed.)
Would it be unusual for a random sample of 900 adults to result in 153 or fewer who do not own a credit card? Why? Select the correct choice below and fill in the answer box to complete your choice
The result
is notis not
unusual because the probability that
ModifyingAbove p with caretp
is less than or equal to the sample proportion is
nothing,
which is
greatergreater
than 5%.
B.The result
is notis not
unusual because the probability that
ModifyingAbove p with caretp
is less than or equal to the sample proportion is
nothing,
which is
lessless
than 5%.
C.The result
isis
unusual because the probability that
ModifyingAbove p with caretp
is less than or equal to the sample proportion is
nothing,
which is
lessless
than 5%.
D.The result
isis
unusual because the probability that
ModifyingAbove p with caretp
is less than or equal to the sample proportion is
nothing,
which is
greatergreater
than 5%.
In: Math
Statistics:
Construct a stem and leaf diagram, a frequency distribution table, plus develop a bar chart, pie chart, histogram, polygon and an ogive from the following data set.
When you construct the pie charts, bar graphs, etc. Use the calculation of 2K to find the number of classes you will need to construct the frequency distribution table. You will need to use lower class limits, lower-class boundaries, midpoints upper-class boundaries, upper-class limits, frequency, relative frequency, and cumulative frequency.
DATA:
90, 92, 94, 100, 100, 91, 95, 96, 93, 23, 31, 57, 42, 59, 48, 58, 49, 37, 62, 75, 83, 88, 89, 70, 71, 79, 85, 77, 69, 82, 85.
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The Pew Research Center took a random sample of 2928 adults in the United States in September 2008. In this sample, 53% of 2928 people believed that reducing the spread of acquired immune sample deficiency disease (AIDS) and other infectious diseases was an important policy goal for the U.S. government.
INTERPRET:
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Directions: Answer the following questions. Round probabilities to four digits after the decimal. For full credit, you will need to show your work justifying how you determined numerical values. You may consider adding additional blank space to this document, printing, filling out by hand, and then uploading a scan or pictures of your answers. You may also re-write these questions on a separate sheet of paper and use as much space as you need to answer the questions.
Charles is a notoriously bad student who never studies for his quizzes. One day, his teacher gives a four question, multiple-choice quiz. Each question has five answer options (a, b, c, d, and e) and each question has only one correct answer option. Since Charles doesn’t study, we might assume that he is going to guess on each of the four questions.
Let X be a discrete random variable representing the number of questions Charles may correctly answer.
Part 1. (5 points) Complete the following probability distribution table:
|
X |
P(X) |
X · P(X) |
X2 ·P(X) |
|
0 |
|||
|
1 |
|||
|
2 |
|||
|
3 |
|||
|
4 |
Part 2. (4 points) Using the table you constructed, find the expected value, μ, and the standard deviation, σ. Please show your work.
Part 3. (2 points) A statistician might consider an outcome with probability less than 0.05 to be “unusual”. Based on this criterion, should we be surprised if Charles guesses three or more questions correctly? Please explain briefly.
Part 4. (2 points) Alternatively, a statistician might consider an outcome to be “unusual” if it is more than two standard deviations away from the mean. Based on this criterion, should we be surprised if Charles guesses three or more questions correctly? Please explain briefly.
Part 5. (2 points) Suppose Charles happens to get three out of four questions correct. When computing the probabilities in problem 1, we assumed that Charles was guessing on every question; based on your answers to problems 3 and 4, do you think our assumption is plausible? What is an alternative explanation for Charles’s performance?
In: Math
The following eight observations were drawn from a normal population whose variance is 100:
12
8
22
15
30
6
29
58
Part A
What is the standard error of the sample mean, based on the known population variance? Give your answer to two decimal places in the form x.xx
Standard error:
Part B
Find the lower and upper limits of a 90% confidence interval for the population mean. Give your answer to two decimal places in the form xx.xx
Lower limit:
Upper limit:
Part C
True or false:
If the population was not normally distributed the confidence interval calculation above would not be valid. Answer by writing T or F in the space provided.
Answer:
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