Question1

A market researcher wants to study TV viewing habits of residents in a particular area. A random sample 0f 70 respondents is selected. The results are as follows

Viewing time per week Mean=14 hours, S=3.8 hours

50 respondents watch the evening news on at least three week nights

(a)      Construct a 90% confidence interval estimate for the mean amount of TV watched per week.

(b)      Construct a 95% CI estimate of population proportion who watches evening news on at least three week nights.

Question 2

Following data gives the amount that a sample of 10 customers spent for lunch ($) at a fast food restaurant:

$8.50, $7, $5.80,  $9, $5.60,  $7.80,  $6.50, $5.40,  $7.50,  $5.50

Construct a 95% confidence interval estimate for the population mean amount spent on lunch at the fast food restaurant.

Question 3

A cell phone provider has the business objective of wanting to estimate the proportion of subscribers who would upgrade to a new cell phone with improved features if it were made available at a substantially reduced cost. Data are collected from a random sample of 500 subscribers. The results indicated that 135 of the subscribers would upgrade to a new cell phone at a reduced cost. Construct a 95% confidence interval estimate for the population proportion of subscribers that would upgrade to a new cell phone at a reduced cost.

Question 4

You are the manager of a restaurant for a fast food. Last month the mean waiting time at the drive through window for branches in your region was 3.8 minutes. You select a random sample of 49 orders. The sample mean waiting time is 3.57 minutes, with a sample standard deviation of 0.8 minutes. At the .05 level of significance is there evidence that population mean waiting time is different from 3.8 minutes?

Two types of medication for hives are being tested to determine if there is a difference in the proportions of adult patient reactions. Twenty out of a random sample of 200 adults given medication A still had hives 30 minutes after taking the medication. Twelve out of another random sample of 180 adults given medication B still had hives 30 minutes after taking the medication. Test at a 1% level of significance.

1. (Write all answers as a decimal rounded to the 3rd decimal place)

Personnel tests are designed to test a job​ applicant's cognitive​ and/or physical abilities. A particular dexterity test is administered nationwide by a private testing service. It is known that for all tests administered last​ year, the distribution of scores was approximately normal with mean 74 and standard deviation 7.7. a. A particular employer requires job candidates to score at least 79 on the dexterity test. Approximately what percentage of the test scores during the past year exceeded 79​? b. The testing service reported to a particular employer that one of its job​ candidate's scores fell at the 90th percentile of the distribution​ (i.e., approximately 90​% of the scores were lower than the​ candidate's, and only 10​% were​ higher). What was the​ candidate's score?

Patients with chronic kidney failure may be treated by dialysis, in which a machine removes toxic wastes from the blood, a function normally performed by the kidneys. Kidney failure and dialysis can cause other changes, such as retention of phosphorus, that must be corrected by changes in diet. A study of the nutrition of dialysis patients measured the level of phosphorus in the blood of several patients on six occasions. Here are the data for one patient (in milligrams of phosphorus per deciliter of blood).

The measurements are separated in time and can be considered an SRS of the patient's blood phosphorus level. Assume that this level varies Normally with

σ = 0.8 mg/dl.

(a) Give a 95% confidence interval for the mean blood phosphorus level.

Fill in the blanks for "x" and "y". ) A bulk supply of CAT6 cables were purchased to implement a wired office network. The network designer randomly tests 12 of the cables and finds the attenuation is on average 22.7dB with a sample standard deviation of 1.9 dB. She wishes to estimate the 95% confidence interval for the mean attenuation of all of the cables. Find the 95% confidence interval (α=0.05) for the mean attenuation rounded to the

Suppose these data show the number of gallons of gasoline sold by a gasoline distributor in Bennington, Vermont, over the past 12 weeks.

(a)

Compute four-week and five-week moving averages for the time series.

(b)

Compute the MSE for the four-week moving average forecasts. (Round your answer to two decimal places.) __________

Compute the MSE for the five-week moving average forecasts. (Round your answer to two decimal places.) ____________

Basic guide to developing a research design ( Please provide EXAMPLES in terms to Politics !!)
1. What are the treatment and outcome variables? How are they defined and measured?
2. What are the two (or more) groups in your research? That is, what is the treatment
group and what is the control group?
a. How is the treatment assigned to the group? Random vs. selected by something
else? If not randomly assigned, what determines the assignment of the
treatment?
b. Other than the value(s) of the treatment variable, how else might the two
groups differ? What confounding variables might be different between the two?
These variables are potential threats to internal validity

Use R.  Provide Solution and R Code within each problem.

For this section use the dataset “PlantGrowth”, available in base R (you do not need to download any packages).

a.Construct a 95% confidence interval for the true mean weight.

b.Interpret the confidence interval in 1. in the context of the problem.

c.Write down the null and alternative hypothesis to determine if the mean weight of the plants is less than 5.

d.Conduct a statistical test to determine if the mean weight of the plants is less than 5. Use α = 0.05.

i.Pvalue

ii.Conclusion

In an article in the Journal of Advertising, Weinberger and Spotts compare the use of humor in television ads in the United States and in the United Kingdom. Suppose that independent random samples of television ads are taken in the two countries. A random sample of 400 television ads in the United Kingdom reveals that 142 use humor, while a random sample of 500 television ads in the United States reveals that 126 use humor. (a) Set up the null and alternative hypotheses needed to determine whether the proportion of ads using humor in the United Kingdom differs from the proportion of ads using humor in the United States. H0: p1 − p2 0 versus Ha: p1 − p2 0. (b) Test the hypotheses you set up in part a by using critical values and by setting α equal to .10, .05, .01, and .001. How much evidence is there that the proportions of U.K. and U.S. ads using humor are different? (Round the proportion values to 3 decimal places. Round your answer to 2 decimal places.) z H0 at each value of α; evidence. (c) Set up the hypotheses needed to attempt to establish that the difference between the proportions of U.K. and U.S. ads using humor is more than .05 (five percentage points). Test these hypotheses by using a p-value and by setting α equal to .10, .05, .01, and .001. How much evidence is there that the difference between the proportions exceeds .05? (Round the proportion values to 3 decimal places. Round your z value to 2 decimal places and p-value to 4 decimal places.) z p-value H0 at each value of α = .10 and α = .05; evidence. (d) Calculate a 95 percent confidence interval for the difference between the proportion of U.K. ads using humor and the proportion of U.S. ads using humor. Interpret this interval. Can we be 95 percent confident that the proportion of U.K. ads using humor is greater than the proportion of U.S. ads using humor? (Round the proportion values to 3 decimal places. Round your answers to 4 decimal places.) 95% of Confidence Interval [ , ] the entire interval is above zero.

1. A survey of the mean number of cents off that coupons give was conducted by randomly surveying one coupon per page from the coupon sections of a recent San Jose Mercury News. The following data were collected: 20¢; 75¢; 50¢; 65¢; 30¢; 55¢; 40¢; 40¢; 30¢; 55¢; $1.50; 40¢; 65¢; 40¢. Assume the underlying distribution is approximately normal. You wish to conduct a hypothesis test (α = 0.05 level) to determine if the mean cents off for coupons is less than 50¢.
   1. State the null and alternate hypotheses clearly.
   2. Conduct the hypothesis test based on the test statistic and critical value(s). Clearly indicate each.
   3. What is the p-value? Use the p-value to conduct the same test
   4. Report your conclusion in words, in the context of the problem.
   5. What is the power of the for an alternative hypothesis value of 49¢?

Four fair dice, colored red, green, blue, and white, are tossed.

(a) Determine the probability of getting all four face values equal to 3.

(b) After tossing, a quick glance at the outcome indicated that two of the face values were 3 but no other information (about their color or the values of the remaining two faces) was noted. Now determine the probability of getting all four face values equal to 3.

(c) After tossing it was further noted that, out of the two observed face values of 3, one was red in color. Now determine the probability of getting all four face values equal to 3.

(d) After tossing, it was finally confirmed that the two observed face values of 3 were red and white. Now determine the probability of getting all four face values equal to 3.

(e) You should get distinct answers for the above four probabilities. Qualitatively explain why the above four probabilities make sense.

These are supposed to be the correct answers: (a) 1/1296 (b) 1/171, (c) 1/91, and (d) 1/36.

Each of the first 6 letters of the alphabet is printed on a separate card. The letter “a” is printed twice. What is the probability of drawing 4 cards and getting the letters f, a, d, a in that order? Same question if the order does not matter.

Suppose that a category of world class runners are known to run a marathon (26 miles) in an average of 149 minutes with a standard deviation of 12 minutes. Consider 49 of the races.
Let X = the average of the 49 races.

a.) X ~ N (149, ? )

b.Find the probability that the runner will average between 148 and 151 minutes in these 49 marathons. (Round your answer to four decimal places.)

c. Find the 80th percentile for the average of these 49 marathons. (Round your answer to two decimal places.)

d. Find the median of the average running times.

You wish to test the following claim (Ha) at a significance level of α=0.002.

      Ho:p1=p2
      Ha:p1>p2

You obtain a sample from the first population with 43 successes and 267 failures. You obtain a sample from the second population with 85 successes and 581 failures. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

What is the p-value for this sample? (Report answer accurate to four decimal places.)
p-value =

The p-value is...

• less than (or equal to) α

• greater than α

This test statistic leads to a decision to...

• reject the null
• accept the null
• fail to reject the null

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion.
• There is not sufficient evidence to warrant rejection of the claim that the first population proportion is greater than the second population proportion.
• The sample data support the claim that the first population proportion is greater than the second population proportion.
• There is not sufficient sample evidence to support the claim that the first population proportion is greater than the second population proportion.

Question 2)

You wish to test the following claim (Ha) at a significance level of α=0.10.

      Ho:p1=p2
      Ha:p1≠p2

You obtain 12.3% successes in a sample of size n1=759 from the first population. You obtain 8.8% successes in a sample of size n2=646 from the second population. For this test, you should NOT use the continuity correction, and you should use the normal distribution as an approximation for the binomial distribution.

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

What is the p-value for this sample? (Report answer accurate to four decimal places.)
p-value =

The p-value is...

• less than (or equal to) α

• greater than α

This test statistic leads to a decision to...

• reject the null
• accept the null
• fail to reject the null

As such, the final conclusion is that...

• There is sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion.
• There is not sufficient evidence to warrant rejection of the claim that the first population proportion is not equal to the second population proprtion.
• The sample data support the claim that the first population proportion is not equal to the second population proprtion.
• There is not sufficient sample evidence to support the claim that the first population proportion is not equal to the second population proprtion.

Questiom 3)

Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .10 significance level.

The null and alternative hypothesis would be:

H0:μM=μF

H1:μM>μF

H0:pM=pF

H1:pM>pF

H0:pM=pF

H1:pM≠pF

H0:μM=μF

H1:μM<μF

H0:μM=μF

H1:μM≠μF

H0:pM=pF

H1:pM<pF

The test is:

right-tailed

left-tailed

two-tailed

Based on a sample of 20 men, 40% owned cats
Based on a sample of 80 women, 65% owned cats

The test statistic is: (to 2 decimals)

The p-value is: (to 2 decimals)

Based on this we:

• Reject the null hypothesis
• Fail to reject the null hypothesis