Fill in the blanks for "x" and "y". ) A bulk supply of CAT6 cables were...

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Expert Solution

We have given that,

Sample mean =22.7
Sample standard deviation =1.9
Sample size =12
Level of significance=1-0.95=0.05
Degree of freedom =11

t critical value is (by using t table)=2.201

Confidence interval formula is

=(21.49,23.91)



Lower confidence limit=21.49

Upper confidence limit=23.91

milcah answered 1 year ago

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