The Table in my homework question below is completely wrong. I am not sure where I went wrong in my calculations but coud you rework this question and answer the parts below??

Assume that we want to construct a confidence interval. Do one of the​ following, as​ appropriate: (a) find the critical value tα/2​, ​(b) find the critical value zα/2​, or​ (c) state that neither the normal distribution nor the t distribution applies. Here are summary statistics for randomly selected weights of newborn​ girls: n=151 x = 29.1 hg S =7.6 hg The confidence level is 95​%. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice. A. t Subscript alpha divided by 2 tα/2 = ​(Round to two decimal places as​ needed.) B. z Subscript alpha divided by 2 zα/2 = ​(Round to two decimal places as​ needed.) C. Neither the normal distribution nor the t distribution applies.

Pls answer all three parts for UPVOTE

Data set:

Students Outside US

Students in US:

a) Construct a 5-number summary and boxplot using the variable “hours spent on school work at home” for both groups.

b) Compare the means for both groups to answer the research questions in the first paragraph. Which group has a higher mean GPA? Which group spends more time on their homework? What conclusions can you draw about students who were born in the USA and those who were born outside the USA based on this analysis?

c) Identify any outliers in both groups

Justin is interested in buying a digital phone. He visited 9 stores at random and recorded the price of the particular phone he wants. The sample of prices had a mean of 337.63 and a standard deviation of 30.04.

(a) What t-score should be used as the multiplier for a 95% confidence interval for the mean, ?, of the distribution?
t =

(b) Calculate a 95% confidence interval for the mean price of this model of digital phone:
(Enter the smaller value in the left answer box.)
___ to ___

The Pew Research Center Internet Project conducted a survey of 657 Internet users. This survey provided a variety of statistics on them. If required, round your answers to four decimal places.

(a) The sample survey showed that 90% of respondents said the Internet has been a good thing for them personally. Develop a 95% confidence interval for the proportion of respondents who say the Internet has been a good thing for them personally.

___ to ___

(b) The sample survey showed that 67% of Internet users said the Internet has generally strengthened their relationship with family and friends. Develop a 95% confidence interval for the proportion of respondents who say the Internet has strengthened their relationship with family and friends.

___ to ___

(c) Fifty-six percent of Internet users have seen an online group come together to help a person or community solve a problem, whereas only 25% have left an online group because of unpleasant interaction. Develop a 95% confidence interval for the proportion of Internet users who say online groups have helped solve a problem.

__ to __

The types of browse favored by deer are shown in the following table. Using binoculars, volunteers observed the feeding habits of a random sample of 320 deer.

Use a 5% level of significance to test the claim that the natural distribution of browse fits the deer feeding pattern.

(a) What is the level of significance?


State the null and alternate hypotheses.

H₀: The distributions are different.
H₁: The distributions are the same.

H₀: The distributions are the same.
H₁: The distributions are the same.    

H₀: The distributions are the same.
H₁: The distributions are different.

H₀: The distributions are different.
H₁: The distributions are different.

(b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to at least three decimal places. Round the test statistic to three decimal places.)


Are all the expected frequencies greater than 5?

Yes

No    

What sampling distribution will you use?

binomial

Student's t    

uniform

normal

chi-square

What are the degrees of freedom?


(c) Estimate the P-value of the sample test statistic.

P-value > 0.100

0.050 < P-value < 0.100    

0.025 < P-value < 0.050

0.010 < P-value < 0.025

0.005 < P-value < 0.010

P-value < 0.005

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis that the population fits the specified distribution of categories?

Since the P-value > α, we fail to reject the null hypothesis.

Since the P-value > α, we reject the null hypothesis.    

Since the P-value ≤ α, we reject the null hypothesis.

Since the P-value ≤ α, we fail to reject the null hypothesis.

(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, the evidence is sufficient to conclude that the natural distribution of browse does not fit the feeding pattern.

At the 5% level of significance, the evidence is insufficient to conclude that the natural distribution of browse does not fit the feeding pattern.

Historically, the time needed for college students to complete their degree follows a normal distribution with a mean of 4 years and a standard deviation of 1.2 years. You wish to see if the mean time m has changed in recent years, so you collect information from 5 recent college graduates.

                                                       4.25      4            3.75       4.5 5

Is there evidence that the mean time is different from 4 years?

a. Check the needed conditions for both the test statistic and confidence interval. (Do not do a stemplot.)

b. State Ho and Ha

c. Calculate the test statistic (if applicable – state the degrees of freedom)

d. Find the p-value

e. What is the conclusion for this problem? Do you reject Ho?

f. Calculate the 98% confidence interval.

g. Interpret this confidence interval

QUESTION 2

Part 1

In a survey of 800 college students in the United States, 608 indicated that they believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action. Assuming that the sample is representative of college students in the United States, construct a 95% confidence interval for the proportion of college students who have this belief. (Use a table or technology. Round your answers to three decimal places.)

(___,___)

PART B

Interpret the interval. Chose 1

A. We are 95% confident that the mean number of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls within this interval.

B. There is a 95% chance that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls within this interval.    

C. There is a 95% chance that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls directly in the middle of this interval.

D. We are 95% confident that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls within this interval.

E. We are 95% confident that the true proportion of U.S. college students who believe that a student or faculty member on campus who uses language considered racist, sexist, homophobic, or offensive should be subject to disciplinary action falls directly in the middle of this interval.

Cultivated amaranth grains (Amaranthus caudatus) come in three colors: black, brown, and pale. Geneticists asked whether this phenotype could result from a dominant epistatic control. Crossing black-seeded and pale-seeded A. caudatus populations (homozygous lines) gave the following counts of black, brown, and pale seeds in the second generation (F2).

In genetics, dominant epistasis should lead to 12/16 of all such seeds being black, 3/16 Brown, and 1/16 pale. Do the experimental data above support the conclusion that seed coat color in cultivated amaranth grains is due to dominant epistasis?

Please find the Ho, Ha, test statistic, df, exact probability of the test statistic, and conclusion relative to the hypothesis. Is this a 1-tailed or 2-tailed test? Use Excel functions and math calculations, please.

I think you Chi-Squared for this, but I am not sure.

Why will a design for a Graeco-Latin square of size 3 not work well?

Pick a profession, identify events that might affect the variation ( you must include all three ; cyclical, seasonal and irregular ) of the secular trend. List at least three ways that this information could be beneficial to the industry.

To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material.

1. Use these data to test whether the population mean times for mixing a batch of material differ for the three manufacturers. Use = .05.
   
   Compute the values below (to 2 decimals, if necessary).

   Sum of Squares, Treatment
   Sum of Squares, Error
   Mean Squares, Treatment
   Mean Squares, Error

   
   
   Calculate the value of the test statistic (to 2 decimals).
   
   
   
   The p-value is Selectless than .01between .01 and .025between .025 and .05between .05 and .10greater than .10
   
   What is your conclusion?
   
   SelectConclude the mean time needed to mix a batch of material is not the same for all manufacturersDo not reject the assumption that mean time needed to mix a batch of material is the same for all manufacturers
   
2. At the = .05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3.
   
   Calculate Fisher's LSD Value (to 2 decimals).
   
   
   
   What is your conclusion about the mean time for manufacturer 1 and the mean time for manufacturer 3?
   
   SelectCannot conclude there is a difference in the mean time for these manufacturersThese manufacturers have different mean times

Review the steps involved in a statistical hypothesis test. How do we set up the null and alternative hypotheses?

How do we set the level of significance?

Can you think of a business research situation where you could apply such processes?

A professor has noticed that, even though attendance is not a component of the final grade for the class, students that attend regularly generally get better grades. In fact, 36% of those who come to class on a regular basis receive A's. Only 4% who do not attend regularly get A's. Overall, 60% of students attend regularly. Based on this class profile, suppose we are randomly selecting a single student from this class, and answer the questions below.

Hint #1: pretend that there are 1000 students in the class and use the values given in the problem to construct the appropriate contingency table. Round cell frequencies to the nearest integer

C) P(receives A's) =

D) P(attends regularly | receives A's)

E) P(does not attend regularly | does not receive A's) =