The mean systolic blood pressure for people in the United States is reported to be 122 millimeters of mercury (mmHg) with a standard deviation of 22.8 millimeters of mercury. The wellness department of a large corporation is investigating if the mean systolic blood pressure is different from the national mean. A random sample of 200 employees in a company were selected and found to have an average systolic blood pressure of 124.7 mmHg.
a) What is the probability a random employees blood pressure is higher than 135 mmHg.
b) What is the probability that 200 randomly selected employees mean blood pressure is greater than 127 mmHg.
c) The wellness department is providing a new health program to their employees. Past studies have shown 9.9 % of their employees have high blood pressure. Find the probability that if the wellness department examines 200 randomly selected employees, less than 12 employees will have high systolic blood pressure. Do you think the new program significantly lowers the number of employees with a high blood pressure.
In: Math
| Age | HRS1 |
| 58 | 32 |
| 24 | 46 |
| 32 | 40 |
| 29 | 40 |
| 34 | 86 |
| 49 | 40 |
| 60 | 40 |
| 78 | 25 |
| 39 | 5 |
| 67 | 15 |
| 22 | 40 |
In: Math
The weight of navel oranges of a domestic farm is normally distributed with a mean of 8.0oz and a standard deviation of 1.5oz. Suppose that you bought 10 oranges randomly sampled.
a) what are the mean of the sampling distribution and the standard error of the mean?
b) what is the probability that the sample mean is between 8.5 and 10.0 oz?
c) The probability is 90% that the sample mean will be between what two values symmetrically distributed around the population mean?
In: Math
By utilising Annexure A, answer the following questions:
|
Process |
Mean |
Standard Deviation |
Lower Specification |
Upper Specification |
|
1 |
6.0 |
0.14 |
5.5 |
6.7 |
|
2 |
7.5 |
0.10 |
7.0 |
8.0 |
|
3 |
4.6 |
0.12 |
4.3 |
4.9 |
|
Numbers of observations in subgroup n |
Factor for X- bar Chart A2 |
Factors for R Charts Lower control limit D3 |
Factors for R Charts Upper control limit D4 |
|
2 |
1.88 |
0 |
3.27 |
|
3 |
1.02 |
0 |
2.57 |
|
4 |
0.73 |
0 |
2.28 |
|
5 |
0.58 |
0 |
2.11 |
|
6 |
0.48 |
0 |
2.00 |
|
7 |
0.42 |
0.08 |
1.92 |
|
8 |
0.37 |
0.14 |
1.86 |
|
9 |
0.34 |
0.18 |
1.82 |
|
10 |
0.31 |
0.22 |
1.78 |
|
11 |
0.29 |
0.26 |
1.74 |
|
12 |
0.27 |
0.28 |
1.72 |
|
13 |
0.25 |
0.31 |
1.69 |
|
14 |
0.24 |
0.33 |
1.67 |
|
15 |
0.22 |
0.35 |
1.65 |
|
16 |
0.21 |
0.36 |
1.64 |
|
17 |
0.20 |
0.38 |
1.62 |
|
18 |
0.19 |
0.39 |
1.61 |
|
19 |
0.19 |
0.40 |
1.60 |
|
20 |
0.18 |
0.41 |
1.59 |
In: Math
Carson Trucking is considering whether to expand its regional service center in Mohab, UT. The expansion requires the expenditure of $10,500,000 on new service equipment and would generate annual net cash inflows from reduced costs of operations equal to $4,000,000 per year for each of the next 7 years. In year 7 the firm will also get back a cash flow equal to the salvage value of the equipment, which is valued at $1.1 million. Thus, in year 7 the investment cash inflow totals $5,100,000. Calculate the project's NPV using a discount rate of 7 percent.
If the discount rate is 7 percent, then the project's NPV is $ ___
In: Math
We want to test the claim that people are taller in the morning than in the evening. Morning height and evening height were measured for 30 randomly selected adults and the difference (morning height) − (evening height) for each adult was recorded in the table below. Use this data to test the claim that on average people are taller in the morning than in the evening. Test this claim at the 0.01 significance level.
(a) In mathematical notation, the claim is which of the following? μ = 0 μ ≠ 0 μ > 0 μ < 0 (b) What is the test statistic? Round your answer to 2 decimal places. t x =(c) Use software to get the P-value of the test statistic. Round to 4 decimal places. P-value = (d) What is the conclusion regarding the null hypothesis? reject H0fail to reject H0 (e) Choose the appropriate concluding statement. The data supports the claim that on average people are taller in the morning than in the evening. There is not enough data to support the claim that on average people are taller in the morning than in the evening. We reject the claim that on average people are taller in the morning than in the evening. We have proven that on average people are taller in the morning than in the evening. |
DATA ( n = 30 )
AM-PM Height
Difference
| cm |
| -0.13 |
| 0.26 |
| 0.65 |
| 0.21 |
| -0.40 |
| -0.01 |
| -0.06 |
| 0.60 |
| -0.15 |
| 0.60 |
| 0.78 |
| 0.32 |
| 1.18 |
| 0.15 |
| 0.27 |
| -0.26 |
| -0.06 |
| 0.95 |
| -0.26 |
| 0.07 |
| 0.59 |
| -0.09 |
| -0.01 |
| -0.24 |
| 0.25 |
| 0.19 |
| 0.74 |
| 0.43 |
| 0.20 |
| -0.11 |
In: Math
The following data come from the 2016 ANES, V36 and V87W, both recoded into 3 categories. One question asked about party identification. The other asked about support for building a wall on the border between the United States and Mexico. The results were as follows:
|
Partisanship |
Oppose |
Not sure |
Favor |
|
Democrat |
620 |
217 |
199 |
|
Independent |
401 |
327 |
602 |
|
Republican |
155 |
218 |
874 |
|
Total |
1176 |
762 |
1675 |
Calculate appropriate percentages for the table, justify your choice of row, column, or total percentages, and comment on the relationship.
In: Math
A factorial experiment was designed to test for any significant differences in the time needed to perform English to foreign language translations with two computerized language translators. Because the type of language translated was also considered a significant factor, translations were made with both systems for three different languages: Spanish, French, and German. Use the following data for translation time in hours.
| Language | |||
| Spanish | French | German | |
| System 1 | 7 | 14 | 14 |
| 11 | 18 | 18 | |
| System 2 | 9 | 14 | 19 |
| 13 | 16 | 25 | |
Test for any significant differences due to language translator system (Factor A), type of language (Factor B), and interaction. Use = .05.
| Source of Variation | Sum of Squares | Degrees of Freedom | Mean Square | F | p-value |
| Factor A | |||||
| Factor B | |||||
| Interaction | |||||
| Error | |||||
| Total |
In: Math
A high school teacher hypothesizes a negative relationship
between performance in exams and performance in presentations. To
examine this, the teacher computes a correlation of 0.58 from a
random sample of 18 students from class. What can the teacher
conclude with an α of 0.01?
a) Compute the appropriate test statistic(s) to
make a decision about H0.
(Hint: Make sure to write down the null and alternative hypotheses
to help solve the problem.)
critical value = ; test statistic =
Decision: ---Select--- Reject H0 Fail to reject H0
b) Compute the corresponding effect size(s) and
indicate magnitude(s).
If not appropriate, input and/or select "na" below.
effect size = ; ---Select--- na trivial
effect small effect medium effect large effect
c) Make an interpretation based on the
results.
There is a significant positive relationship between performance in exams and performance in presentations.There is a significant negative relationship between performance in exams and performance in presentations. There is no significant relationship between performance in exams and performance in presentations.
In: Math
a human resource survey revealed that 30% of job applicants cheat on their psychometric test. use the binomial formula to find the probability that the number of job applicants in a sample of 14 who cheat on their psychometric test is:
a. exactly 8
b. less than 2
c. at least 1
In: Math
A clinical trial is conducted comparing a new pain reliever for arthritis to a placebo. Participants are randomly assigned to receive the new treatment or a placebo and the outcome is pain relief within 30 minutes. The data are shown here.
| Pain Relief | No Pain Relief | |
| New Medication | 45 | 75 |
| Placebo | 20 | 100 |
Is there a significant difference in the proportions of
patients reporting pain relief?
Run the test at a 5% level of significance.
H0: p1= p2(equivalent to RD = 0, RR=1 or OR=1)
Can they reject the H0?
Group of answer choices
Yes, Reject H0, there is a statistically significant difference in the proportions of patients reporting pain relief in the new medication and placebo groups
No, Fail to Reject H0, there is no statistically significant difference in the proportions of patients reporting pain relief between the new medication and placebo groups
Not enough information to answer this research question
In: Math
perform Levene’s test for equal variance. Note, this is a one‐way ANOVA testing for the equality of 16 variances (each combination of promotion/discount). 0.1 signigicance
2. perform 2-way anova with replication
To answer these questions, an experiment was designed using laundry detergent pods. For ten weeks, 160 subjects received information about the products. The factors under consideration were the number of promotions (1, 3, 5, or 7) that were described during this ten‐ week period and the percent that the product was discounted (10%, 20%, 30%, or 40%) off the average non‐promotional price. Ten individuals were randomly assigned to each of the sixteen combinations. The data reflecting what the sub‐ jects would expect to pay for the product (i.e., their reference price) at the end of the 10‐week period. 0.1 significance
| Stop 'N Shop Reference Pricing Data | Note: the headings reflect the number of promotions and the percent discount | Stop 'N Shop Case.xlsx | |||||||||||||
| (for example: N5D30 represents 5 promotions with a 30 percent discount). | |||||||||||||||
| N1D10 | N3D10 | N5D10 | N7D10 | N1D20 | N3D20 | N5D20 | N7D20 | N1D30 | N3D30 | N5D30 | N7D30 | N1D40 | N3D40 | N5D40 | N7D40 |
| 11.36 | 11.33 | 11.15 | 10.82 | 10.83 | 11.46 | 11.16 | 10.71 | 12.20 | 12.14 | 11.37 | 11.15 | 12.45 | 12.16 | 11.57 | 11.30 |
| 11.76 | 11.39 | 11.44 | 11.17 | 11.03 | 11.20 | 11.03 | 11.32 | 11.85 | 12.06 | 11.61 | 11.71 | 12.14 | 12.41 | 11.62 | 11.48 |
| 11.73 | 11.51 | 11.08 | 11.31 | 11.16 | 11.46 | 11.12 | 10.61 | 11.84 | 11.72 | 11.43 | 11.06 | 12.04 | 11.94 | 12.01 | 11.65 |
| 11.68 | 11.49 | 11.35 | 11.17 | 11.75 | 11.14 | 11.36 | 10.93 | 11.74 | 11.99 | 11.37 | 11.41 | 12.15 | 12.24 | 11.88 | 11.15 |
| 11.82 | 11.83 | 11.20 | 11.37 | 11.26 | 11.61 | 11.36 | 11.00 | 11.81 | 11.22 | 11.28 | 11.67 | 11.95 | 11.92 | 11.00 | 11.52 |
| 11.95 | 11.59 | 11.67 | 10.87 | 11.92 | 11.25 | 11.07 | 11.06 | 11.79 | 11.68 | 11.67 | 11.01 | 12.22 | 11.72 | 11.60 | 11.67 |
| 11.68 | 11.43 | 11.40 | 10.98 | 11.74 | 11.27 | 11.23 | 11.16 | 11.85 | 11.56 | 11.74 | 11.24 | 12.26 | 11.96 | 11.78 | 11.65 |
| 11.43 | 11.73 | 11.41 | 10.95 | 11.90 | 11.48 | 10.93 | 11.34 | 11.92 | 11.94 | 11.02 | 11.33 | 12.19 | 11.63 | 11.63 | 11.78 |
| 11.57 | 11.86 | 11.32 | 11.05 | 11.57 | 10.96 | 11.31 | 10.78 | 11.99 | 11.71 | 11.92 | 11.47 | 12.36 | 11.95 | 11.66 | 11.13 |
| 11.85 | 11.28 | 11.16 | 10.71 | 11.69 | 11.74 | 10.93 | 11.29 | 12.50 | 11.82 | 11.70 | 11.49 | 12.04 | 12.23 | 11.78 | 11.96 |
In: Math
To characterize random uncertainty of a pressure measuring technique, twelve pressure measurements were made of a certain constant pressure source, giving the following results in kPa: 125, 128, 129, 122, 126, 125, 125, 130, 126, 127, 124, and 123. (a) Estimate the 95% confidence interval of the next measurement obtained with this technique; (b) Estimate the 95% confidence interval of the average of next 5 measurements obtained with this technique; (c) Using only the 12 measurements available, how would you report the value of measured pressure, including the 95% confidence interval?
In: Math
Consider a Bernoulli random variable X such that P(X=1) = p. Calculate the following and show steps of your work:
a) E[X]
b) E[X2]
c) Var[X]
d) E[(1 – X)10]
e) E[(X – p)4]
f) E[3x41-x]
g) var[3x41-x]
In: Math
1-what is the dummy variable and what is the purpose of included in regression model ?
2- explaining the meaning of adjust r square?
3-if adjust r square computed. would it be higher , equal of lower than value of r square?
In: Math