Question

In: Statistics and Probability

Find the probability that the sum is as stated when a pair of dice is rolled....

Find the probability that the sum is as stated when a pair of dice is rolled. (Enter your answers as fractions.) (a) odd and less than 5 (b) odd or less than 5

Solutions

Expert Solution

Solution:

We are given that: two dice are rolled.

Thus sample space of rolling of two dice is:

X = sum of numbers obtained on uppermost faces of two dice

then following is the table which gives all possible values of sum of numbers and their frequencies.

For example: (1,1) gives sum = 1+1=2 ,

(1,2) gives sum = 1+2=3

and so on.

We get:

Die 1 Die 2 Sum
1 1 2
1 2 3
1 3 4
1 4 5
1 5 6
1 6 7
2 1 3
2 2 4
2 3 5
2 4 6
2 5 7
2 6 8
3 1 4
3 2 5
3 3 6
3 4 7
3 5 8
3 6 9
4 1 5
4 2 6
4 3 7
4 4 8
4 5 9
4 6 10
5 1 6
5 2 7
5 3 8
5 4 9
5 5 10
5 6 11
6 1 7
6 2 8
6 3 9
6 4 10
6 5 11
6 6 12

Thus frequency distribution is:

X = Sum of Numbers Frequency
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
N = 36

Part a) P( Sum is odd and less than 5 ) =................?

From above frequency table, we can see: Sum less than 5 are ( 2,3,4) and out of which odd sum is only 3

and sum =3 has frequency 2

Thus we have to find:

P( Sum is odd and less than 5 ) = P( Sum = 3)

P( Sum is odd and less than 5 ) = 2 / 36

P( Sum is odd and less than 5 ) = 1/18

Part b) P(Sum is odd or less than 5 )=........?

P(Sum is odd or less than 5 )=P( Sum is Odd ) + P( Sum is less than 5) - P( Sum if odd and less than 5)

From given frequency distribution, we can see:

Sum is odd has following outcomes: ( 3, 5, 7, 9, 11) with corresponding frequencies ( 2, 4, 6, 4, 2)

Thus

P(Sum is odd) = (2+4+6+4+2) / 36

P(Sum is odd) = 18/36

and

Outcomes of Sum is less than 5 are ( 2, 3, 4) with frequencies ( 1 , 2 , 3 )

Thus

P( Sum is less than 5 ) = (1+2+3)/36

P( Sum is less than 5 ) = 6/36

and

From part a) we have:

P( Sum is odd and less than 5 ) = 2 / 36

Thus

P(Sum is odd or less than 5 )=P( Sum is Odd ) + P( Sum is less than 5) - P( Sum if odd and less than 5)

P(Sum is odd or less than 5 )= 18/36 + 6/36 - 2/36

P(Sum is odd or less than 5 )= (18+6-2) / 36

P(Sum is odd or less than 5 )= 22/36

P(Sum is odd or less than 5 )= 11 / 18


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