In: Math
A global research study found that the majority of today's working women would prefer a better work-life balance to an increased salary. One of the most important contributors towork-life balance identified by the survey was "flexibility," with 45% of women saying that having a flexible work schedule is either very important or extremely important to their career success. Suppose you select a sample of 400 working women.
The probability that in the sample fewer than 53% say that having a flexible work schedule is either very important or extremely important to their career success is
The probability that in the sample between 41% and 53% say that having a flexible work schedule is either very important or extremely important to their career success is
The probability that in the sample more than 47% say that having a flexible work schedule is either very important or extremely important to their career success is
Solution:
Given ,
p = 0.45 (population proportion)
1 - p = 1 - 0.45 = 0.55
n = 400 (sample size)
Let be the sample proportion.
he sampling distribution of is approximately normal with
mean = = p = 0.45
SD = =
=
= 0.02487468592
a)Find P(Sample proportion is less than 53%)
= P( < 0.53)
=
= P(Z <(0.53-0.45)/ 0.02487468592 )
= P(Z < 3.216)
= 0.9994 ...use z table
P(Sample proportion is less than 53%) = 0.9994
b) Find P(Sample proportion is between 41% and 53%)
= P(0.41 < < 0.53)
= P( < 0.53) - P( < 0.41)
= -
= P(Z <(0.53-0.45)/ 0.02487468592 ) - P(Z <(0.41-0.45)/ 0.02487468592 )
= P(Z < 3.216) - P(Z < -1.608)
= 0.9994 - 0.0539
= 0.9455
P(Sample proportion is between 41% and 53%) = 0.9455
c)
P(Sample proportion is more than 47%)
= P( > 0.47)
=
= P(Z > (0.47-0.45)/ 0.02487468592 )
= P(Z > 0.804)
= P(Z < -0.804)
= 0.2107
P(Sample proportion is more than 47%) = 0.2107