Question

Multiple choice questions: Circle the correct answer

4) Considering distributing a file of F = 10 Gbits to 200 peers. The server has an upload rate of 10 Mbps, and each peer has a download rate of 1 Mbps and an upload rate of 200 Kbps. If client-server distribution is used to distribute the file to these 200 peers, the minimum distribution time is approximately equal to

(a) 10,000 sec; (b) 20,000 sec; (c) 100,000 sec; (d) 200,000 sec; (e) None of the above.

4.A) Referring to Problem 4), if P2P is used to distribute the file, the minimum distribution time is approximately equal to

(a) 40,000 sec; (b) 10,000 sec; (c) 4,000 sec; (d) 1,000 sec; (e) None of the above.

Answer 1

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Solution:

4) Considering distributing a file of F = 10 Gbits to 200 peers. The server has an upload rate of 10 Mbps, and each peer has a download rate of 1 Mbps and an upload rate of 200 Kbps. If client-server distribution is used to distribute the file to these 200 peers, the minimum distribution time is approximately equal to

Answer: b) 20,000 sec

Formula : Dcs = max {NF/us, F/dmin}

Given:

F = 10 Gbits = 10 * 1024 Mbits

us = 10 Mbps ; dmin = 1 Mbps , u = 200 kbps = 200/1024 Mbps

Calculation:

c = max{200/1024 *10* 1024) *10, 10*1024/1}

Dcs = 20,000 sec

4. A) Referring to Problem 4), if P2P is used to distribute the file, the minimum distribution time is approximately equal to

Formula : Dp2p = max{F/us , F/dmin, NF/(us +  summation(i=1ton) ui)}

Answer (e) None of the above.

The value approximately equals to 20000

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