In: Accounting
is the new manager of the materials storeroom for
Parr
Manufacturing.
Mary
has been asked to estimate future monthly purchase costs for part #696, used in two of
Parr's
products.
Mary
has purchase cost and quantity data for the past 9 months as follows:
Month
Cost of Purchase
Quantity Purchased
January
$12,675
2,720 parts
February
12,110
2,820
March
17,426
4,095
April
15,825
3,724
May
13,025
2,912
June
14,022
3,321
July
15,290
3,688
August
10,094
2,262
September
14,970
3,552
Estimated monthly purchases for this part based on expected demand of the two products for the rest of the year are as follows:
Month |
Purchase Quantity Expected |
October |
3,310 parts |
---|---|
November |
3,750 |
December |
3,040 |
1. |
The computer in
Mary's office is down, andMary has been asked to immediately provide an equation to estimate the future purchase cost for part #696.Mary grabs a calculator and uses the high-low method to estimate a cost equation. What equation does she get? |
2. |
Using the equation from requirement 1, calculate the future expected purchase costs for each of the last 3 months of the year. |
3. |
After a few hours
Mary's computer is fixed.Mary uses the first 9 months of data and regression analysis to estimate the relationship between the quantity purchased and purchase costs of part #696. The regression lineMary obtains is as follows: y =$1,945.9 +3.71X Evaluate the regression line using the criteria of economic plausibility, goodness of fit, and significance of the independent variable. Compare the regression equation to the equation based on the high-low method. Which is a better fit? Why? |
4. |
Use the regression results to calculate the expected purchase costs for October, November, and December. Compare the expected purchase costs to the expected purchase costs calculated using the high-low method in requirement 2. Comment on your results. |
Answer:
1.
The equation Mary gets is:
Purchase costs = $1,008 + ($4 x Quantity purchased)
That is y = $1,046 + $4x
2.
Month | Expected cost |
October | 14,286 |
November | 16,046 |
December | 13,206 |
3. As per the regression done , the actual estimate of fixed cost is low with all the provided data points. Here the variable rate is less, though the fixed cost is more for the regression line than for high-low cost equation done.
4.
Month | Expected cost |
October | 14,226.00 |
November | 15,858.40 |
December | 13,224.30 |
Calculation:
Here Mary will pick need to choose the highest point of activity, 4,095 (March) at $17,426 of cost, and the lowest point of activity, 2,262 parts (August) at $10,094
Costdriver: Quantity Purchased | Cost | |
Highest observation of cost driver | 4,095 | 17,426 |
Lowest observation of cost driver | 2,262 | 10,094 |
Difference | 1,833 | 7,332 |
The purchase cost is calculated as below
Purchase costs = a + b x Quantity purchased
So,
Slope Coefficient = $7,332/1833 = $4 per part
a = $17,426 ─ ($4 x 4095) = $1,046
The equation Mary gets is:
y = $1,046 + $4x
2.
Here we need to take the equation from requirement 1, we need to calculate the future expected purchase costs for each of the last 3 months of the year.
y = $1,046 + $4x
Here we need to replace the 'x' with the Purchase Quantity Expected
So,
Month | Purchase Quantity Expected | Formula | Expected cost |
October | 3,310 | y = $1,046+ ($4 x 3310) | 14,286 |
November | 3,750 | y = $1,046+ ($4 x 3750) | 16,046 |
December | 3,040 | y = $1,046+ ($4 x 3040) | 13,206 |
3.
Here we need to input the data provided for the first 9 months into the graphical format. Could do this by MS EXCEL or manually drawing it in a graph paper as below:
The regression line we got is same as the one mary have got rounded
y = $1,945.9 + 3.71x
The regression line fits the data rightly as the distance between the regression line and observations is less. An r-squared value of greater than 0.97 which means, more than 97% of the cost change can be due to the change in quantity. Thus quantity purchased is correlated with purchasing cost for part #696.
The actual estimate of fixed cost is low with all the provided data points. Here the variable rate is less, though the fixed cost is more for the regression line than for high-low cost equation done.
4.
Here we need to take the equation from requirement 3, and we need to calculate the future expected purchase costs for each of the last 3 months of the year.
y = $1945.9 + $3.71x
Here we need to replace the 'x' with the Purchase Quantity Expected
So,
Month | Purchase Quantity Expected | Formula | Expected cost |
October | 3,310 | y = $1,945.9+ ($3.71x 3310) | 14,226.00 |
November | 3,750 | y = $1,945.9+ ($3.71x 3750) | 15,858.40 |
December | 3,040 | y = $1,945.9+ ($3.71x 3040) | 13,224.30 |