Question

In: Statistics and Probability

A survey found that​ women's heights are normally distributed with mean 62.4 in. and standard deviation...

A survey found that​ women's heights are normally distributed with mean 62.4 in. and standard deviation 3.1 in. The survey also found that​ men's heights are normally distributed with mean 69.3 in. and standard deviation 3.9 in. Consider an executive jet that seats six with a doorway height of 55.8 in. a. What percentage of adult men can fit through the door without​ bending? The percentage of men who can fit without bending is nothing​%. ​(Round to two decimal places as​ needed.) b. Does the door design with a height of 55.8 in. appear to be​ adequate? Why​ didn't the engineers design a larger​ door? A. The door design is​ adequate, because although many men will not be able to fit without​ bending, most women will be able to fit without bending.​ Thus, a larger door is not needed. B. The door design is​ inadequate, because every person needs to be able to get into the aircraft without bending. There is no reason why this should not be implemented. C. The door design is​ adequate, because the majority of people will be able to fit without bending.​ Thus, a larger door is not needed. D. The door design is​ inadequate, but because the jet is relatively small and seats only six​ people, a much higher door would require major changes in the design and cost of the​ jet, making a larger height not practical. c. What doorway height would allow​ 40% of men to fit without​ bending? The doorway height that would allow​ 40% of men to fit without bending is nothing in. ​(Round to one decimal place as​ needed.)

Solutions

Expert Solution

Solution:

Given:

Women's heights are normally distributed with mean 62.4 in. and standard deviation 3.1 in.

Thus

Men's heights are normally distributed with mean 69.3 in. and standard deviation 3.9 in.

Thus

An executive jet that seats six with a doorway height of 55.8 in

Part a) What percentage of adult men can fit through the door without​ bending?

That is we have to find:

P( Xm < 55.8) = ............?

Find z score for xm = 55.8

z score formula:

P( Xm < 55.8) = P( Z < -3.46)

Look in z table for z= -3.4 and 0.06 and find area.

P( Z < -3.46) = 0.0003

P( Xm < 55.8) = P( Z < -3.46)

P( Xm < 55.8) = 0.0003

P( Xm < 55.8) = 0.03%

The percentage of men who can fit without bending is 0.03%

Part b) Does the door design with a height of 55.8 in. appear to be​ adequate? Why​ didn't the engineers design a larger​ door?

Correct option is:

D. The door design is​ inadequate, but because the jet is relatively small and seats only six​ people, a much higher door would require major changes in the design and cost of the​ jet, making a larger height not practical.

Part c) What doorway height would allow​ 40% of men to fit without​ bending?

That is we have to find x value such that:

P( Xm < xm ) = 0.40

Thus first find z such that P( Z < z ) =0.40

Look in z table for Area = 0.4000 or its closest area and find corresponding z value.

Area 0.4013 is closest to 0.4000, and it corresponds to -0.2 and 0.05

thus z = -0.25

Now use following formula to find x value.


Related Solutions

A survey found that​ women's heights are normally distributed with mean 62.4 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 62.4 in. and standard deviation 2.1 in. The survey also found that​ men's heights are normally distributed with mean 67.3 in. and standard deviation 3.1 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in. and a maximum of 63 in. 1.Find the percentage of men meeting the height requirement. What does the result suggest about the genders of...
A survey found that? women's heights are normally distributed with mean 63.9 in and standard deviation...
A survey found that? women's heights are normally distributed with mean 63.9 in and standard deviation 2.4 in. A branch of the military requires? women's heights to be between 58 in and 80 in. a. Find the percentage of women meeting the height requirement. Are many women being denied the opportunity to join this branch of the military because they are too short or too? tall? b. If this branch of the military changes the height requirements so that all...
A survey found that​ women's heights are normally distributed with mean 62.6 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 62.6 in. and standard deviation 2.6 in. The survey also found that​ men's heights are normally distributed with a mean 67.6 in. and standard deviation 2.7. Complete parts a through c below. a. Most of the live characters at an amusement park have height requirements with a minimum of 4 ft 9 in. and a maximum of 6 ft 3 in. Find the percentage of women meeting the height...
A survey found that? women's heights are normally distributed with mean 62.7 in. and standard deviation...
A survey found that? women's heights are normally distributed with mean 62.7 in. and standard deviation of 3.4 in. The survey also found that? men's heights are normally distributed with mean of 69.3 in. and a standard deviation of 3.6 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 55 in. and a maximum of 64 in. Complete parts? (a) and? (b) below. a)Find the percentage of men meeting the height...
A survey found that​ women's heights are normally distributed with mean 63.763.7 in and standard deviation...
A survey found that​ women's heights are normally distributed with mean 63.763.7 in and standard deviation 2.32.3 in. A branch of the military requires​ women's heights to be between 58 in and 80 in. a. Find the percentage of women meeting the height requirement. Are many women being denied the opportunity to join this branch of the military because they are too short or too​ tall? b. If this branch of the military changes the height requirements so that all...
A survey found that​ women's heights are normally distributed with mean 62.1 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 62.1 in. and standard deviation 3.1 in. The survey also found that​ men's heights are normally distributed with mean 69.6 in. and standard deviation 3.7 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in. and a maximum of 63in. Complete parts​ (a) and​ (b) below. a. Find the percentage of men meeting the height requirement. What does the...
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation of 3.7 in. The survey also found that​ men's heights are normally distributed with a mean 68.6 in. and standard deviation 3.3 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 55 in. and a maximum of 62 in. Complete parts​ (a) and​ (b) below. a. Find the percentage of men meeting the height requirement....
A survey found that women's heights are normally distributed with mean 62.6 in. and standard deviation...
A survey found that women's heights are normally distributed with mean 62.6 in. and standard deviation 2.4 in. The survey also found that men's heights are normally distributed with mean 67.1 in. and standard deviation 3.4 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 56 in. and a maximum of 64 in. Complete parts (a) and (b) below. a. Find the percentage of men meeting the height requirement. What does...
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 63.3 in. and standard deviation 2.3 in. The survey also found that​ men's heights are normally distributed with mean 69.1 in. and standard deviation 3.1 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 57in. and a maximum of 62 in. Complete parts​ (a) and​ (b) below. a. Find the percentage of men meeting the height requirement. What does the...
A survey found that​ women's heights are normally distributed with mean 63.9 in. and standard deviation...
A survey found that​ women's heights are normally distributed with mean 63.9 in. and standard deviation 3.1 in. The survey also found that​ men's heights are normally distributed with mean 69.1 in. and standard deviation 3.4 in. Most of the live characters employed at an amusement park have height requirements of a minimum of 57 in. and a maximum of 62 in. Complete parts​ (a) and​ (b) below. a. Find the percentage of men meeting the height requirement. What does...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT