In: Statistics and Probability
Use t distribution to answer this question:
2. Medical schools A and B reported the following summary of MCAT (Medical Aptitude Test) verbal scores. Test the claim that the applicants of Medical school A score higher than their counterparts of Medical school B. (a) At α = 5%, use the Classical approach to conclude it. (b) Using the P-value approach to conclude it.
Medical school A : n=16, X bar=420, S2= 144
Medical school B : n=8, X bar=408,S2= 128
a) H0:
H1:
The test statistic t = ()/sqrt(s1^2/n1 + s2^2/n2)
= (420 - 408)/sqrt(144/16 + 128/8)
= 2.4
DF = (s1^2/n1 + s2^2/n2)^2/((s1^2/n1)^2/(n1 - 1) + (s2^2/n2)^2/(n2 - 1))
= (144/16 + 128/8)^2/((144/16)^2/15 + (128/8)^2/7)
= 15
At 5% significance level the critical value is t0.95, 15 = 1.753
As the test statistic value is greater than the critical value ( 2.4 > 1.753), we should reject the null hypothesis.
So there is sufficient evidence to support the claim that the applicants of Medical school A score gigher than their counterparts of Medical school B.
b) The P-value = P(T > 2.4)
= 1 - P(T < 2.4)
= 1 - 0.9851
= 0.0149
As the P-value is less than the significance level (0.0149 < 0.05), we should reject the null hypothesis.
So there is sufficient evidence to support the claim that the applicants of Medical school A score gigher than their counterparts of Medical school B.