In: Physics
Solution :
To understand how to generate a reducible representation of the 3n translation, rotation and vibrational degrees of freedom from a character table, let us consider an example of a molecule, BF3.
STEP 1: Identify the point group of the
molecule.
BF3 belongs to D3h point group.
STEP 2 : Determination of degrees of
freedom
BF3 is a non-linear molecule , with 4 atoms.
Using the equation 3N, there are (3 x 4=12) 12 degrees of freedom.
Similarly,using the equation 3n-6, we find that there are (12-6=6)
6 vibrational degrees of freedom.
STEP 3 : Determination of irreducible representations of
The three axes are put on each atom.
is then evaluated by observing the effect on the axes by all the
symmetry operations.
E | 2C3 | 3C2 | σ h | 2S3 | 3σ v | |
12 | 0 | -2 | 4 | -2 | 2 |
The contributions from each symmetry species are as follows:
Therefore, Γ tot = A1 ’ + A2 ’ + 3E’ + 2A2” + E”. From the above contriutions of each symmetry, we can conclude that, Γ tot has twelve degrees of freedom as already shown in step 2.
STEP 3: DETERMINATION OF :
We know that, Γ tot = Γ trans + Γ
rot + Γ vib
From the character table, Γ trans = E’ +
A2 ”
Also, Γ rot = A2’ + E”
Therefore, using Γvib = Γ tot – Γ
trans - Γrot, we arrive at Γ vib =
A1’ + 2E’ + A2”
Γ
vib has six degrees of freedom.
STEP 4 : SPLITTING INTO STRETCHES AND
BONDS
BF3 has three bonds, so it has 3 stretches and 3
bends.
STEP 5 : DETERMINATION OF IRREDUCIBLE REPRESENTATION
OF
One axis is put on each bond.
E | 2C3 | 3C2 | σ h | 2S3 | 3σ v | |
3 | 0 | 1 | 3 | 0 | 1 |
The contributions of each symmetry element are as follows:
Γ stretch = A1’ + E’
STEP 6 : DETERMINATION OF
Γ bend = Γ vib - Γ stretch
Γbend
= E’ + A2 ”