Question

In: Statistics and Probability

1.         You are going to toss one coin and roll one die. Using a tree diagram...

1.         You are going to toss one coin and roll one die. Using a tree diagram determine how many outcomes are possible and list the sample space. (6 points).

Then based on your sample space answer the following questions: (2 points each)

a.         What is the probability you will toss a tail and roll a composite number?

b.         What is the probability you will toss a head or roll a number greater than 3?

c.         What is the probability you will toss a tail AND not roll number less than 3?

d.         What is the probability you will toss a tail and roll a divisible by 3?

e.         What are the odds in favor you will toss a head or roll a number less than 4?

Solutions

Expert Solution

Following is the tree diagram:

Total number of possible outcomes : 2*6 = 12

The sample space is

S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

Since each of these 12 outcomes are equally likely so probability of each outcome is 1/12.

Composite numbers: 4, 6

Prime numbers: 1, 2, 3, 5

a)

The probability you will toss a tail and roll a composite number is

P(tail and composite number) = P(T4) + P(T6) = 1/12 + 1/12 = 2/12 = 1/6

b)

The probability you will toss a head or roll a number greater than 3 is

P(head or roll greater than 3) = P(H1) + P(H2) + P(H3) + P(H4) + P(H5) + P(H6) +P(T4) + P(T5) + P(T6) = 9 /12 = 0.75

c)

The  probability you will toss a tail AND not roll number less than 3 is

P(tail and  not roll number less than 3) = P(T3) + P(T4) + P(T5) + P(T6) = 4/12 = 1/3

d)

The probability you will toss a tail and roll a divisible by 3 is

P(tail and divisible by 3) = P(T3) + P(T6) = 1/12 + 1/12 = 1 /6

e)

The number of outcomes in favor of event " you will toss a head or roll a number less than 4" is 9 so

P(E) = P(head or roll a number less than 4) = P(H1) + P(H2) + P(H3) + P(H4) + P(H5) + P(H6) +P(T1) + P(T2) + P(T3) = 9/12

By the complement rule,

P(E') = 1 - P(E) = 3/12

The dds in favor you will toss a head or roll a number less than 4 is

odds in favor = P(E) : P(E') = 9/12 : 3/12 = 9 : 3 = 3 :1


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