In: Statistics and Probability
Let p1 and p2 be the respective proportions of women with iron-deficiency anemia in each of two developing countries. A random sample of 2000 women from the first country yielded 439 women with iron-deficiency anemia, and an independently chosen, random sample of 1700 women from the second country yielded 316 women with iron-deficiency anemia. Can we conclude, at the 0.05 level of significance, that the proportion of women with anemia in the first country is greater than the proportion of women with anemia in the second country?Perform a one-tailed test. Then fill in the table below.
Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)
Null Hypothesis: ?
Alternative Hypothesis: ?
Type of test statistic: ? (z, t, chi square, F)
The value of the test statistic: ? (round to 3 decimal places)
The p-value: ? (round to 3 decimal places)
Can we conclude that the proportion of women with anemia in the first country is greater than the proportion of women with anemia in the second country? (yes or no)
p1: Population proportion of women with iron-deficiency anemia in Country 1
p2 : Population proportion of women with iron-deficiency anemia in Country 2
Null hypothesis : proportion of women with anemia in the first country is equal to the proportion of women with anemia in the second country i.e p1=p2 ; p1-p2 =0
Alternate Hypothesis : Proportion of women with anemia in the first country is greater than the proportion of women with anemia in the second country ; p1 > p2 ; p1-p2 > 0
Ho : p1 - p2 = 0
Ha : p1 - p2 > 0 (Right Tailed test)
Type of Statistic : Z
Country 1 | Country 2 | |
Number of women in the sample(n) | n1=2000 | n2=1700 |
Number of women with iron-deficiency anemia(x) | x1=439 | x2=316 |
Sample proportion of Proportion of women with iron-deficiency anemia | =439/200=0.2195 | ==316/1700=0.1859 |
The value of the test statistic = 2.5271
For Right tailed test:
p-value = 0.0058
As P-Value i.e. is less than Level of significance i.e (P-value:0.0058 < 0.05:Level of significance); Reject Null Hypothesis
At 0.05 level of significance , There is sufficient evidence to conclude that that the proportion of women with anemia in the first country is greater than the proportion of women with anemia in the second country
Can we conclude that the proportion of women with anemia in the first country is greater than the proportion of women with anemia in the second country? (yes or no)
Ans : Yes