Question

A.
Write a program 
1. Prompt the user to enter a positive integer n and read in the input.
2. Print out n of Z shape of size n X n side by side which made up of *.

B.
Write a C++ program that
        1. Prompt user to enter an odd integer and read in the value  to n.
        2. Terminate the program if n is not odd.
        3. Print out a cross shape of size n X n made up of *, where the * is in the mid row and mid column

C.
Write a C++ program that
        1. Prompt user to enter two integer a and b.
        2. Then prints a + b rows each of which contains a ∗ b columns of Xs, but after each group of b complete columns the program prints a | symbol. 

Answer 1

A.) printing a Z

In this program we have to print a pattern that looks like a Z, with '*' characters

First , get the value of n from user

Then, loop for i , j = 0 to n

Inside, the loop, if i is 0 ot n-1, print '*'. If (i,j) is a secondary diagonal element , print '*'. Otherwise print a white space

program:

#include <iostream>

using namespace std;

int main(){
   int n;
   cout<<"Enter n: "; cin>>n;
   for(int i = 0; i<n; i++){
       for(int j = 0; j<n; j++){
           if(i==0)
               cout<<"*";
           else if(i==n-1)
               cout<<"*";
           else if(i+j == n-1)
               cout<<"*";
           else
               cout<<" ";
       }
       cout<<"\n";
   }
}

sample input and output:

B.) Printing a cross

• In this program, we have to print a cross with '*' characters
• First, get an odd integer n from user. After reading, check if n is even, if yes then terminate the program
• loop for i, j = 0 to n.
• Inside the loop, check if (i,j) are diagonal elements or secondary diagonal elements. If yes, then print '*' . otherwise, print a white space

program:

#include <iostream>

using namespace std;

int main(){
   int n;
   cout<<"Enter a odd integer: "; cin>>n;
   if(n%2==0){
       cout<<n<<" is not odd\n";
       return 0;
   }
   for(int i = 0; i<n; i++){
       for(int j = 0; j<n; j++){
           if(i==j)
               cout<<"*";
           else if(i+j==n-1)
               cout<<"*";
           else
               cout<<" ";
       }
       cout<<endl;
   }
   return 0;
}

sample input and output:

C.) Grid of X and |

• In this program, we have to print a grid of 'X' and '|'
• get the values of a and b from user.
• loop for i = 0 to a+b and j = 0 to a*b.
• Inside the loop, print 'X'. if j+1 is divisible by b, then print '|'

program:

#include <iostream>

using namespace std;

int main(){
   int a, b;
   cout<<"Enter two integers: "; cin>>a>>b;
   for(int i = 0; i<a+b; i++){
       for(int j = 0; j < a*b; j++){
           cout<<"X";
           if((j+1)%b==0)
               cout<<"|";
       }
       cout<<endl;
   }
}

sample input and output: