In: Math
The following null and alternative hypotheses have been stated: H0: µ1 - µ2 = 0 HA: µ1 - µ2 = ø to test the null hypothesis, random samples have been selected from the two normally distributed populations with equal variances. the following sample data were observed. sample from population 1: 33, 29, 35, 39, 39, 41, 25, 33, 38. sample from population 2: 46, 43, 42, 46, 44, 47, 50, 43, 39. the test null hypothesis using an alpha level equal to 0.05.
= 34.67
s1 = 5.24
= 44.44
s2 = 3.21
The pooled sample variance(sp2) = ((n1 - 1)s1^2 + (n2 - 1)s2^2)/(n1 + n2 - 2)
= (8 * (5.24)^2 + 8 * (3.21)^2)/(9 + 9 - 2)
= 18.88
The test statistic t = ()/sqrt(sp2/n1 + sp2/n2)
= (34.67 - 44.44)/sqrt(18.88/9 + 18.88/9)
= -4.77
DF = 9 + 9 - 2 = 16
At = 0.05, the critical values are t* = +/- 2.120
Since the test statistic value is less than the lower critical value (-4.77 < -2.120), so we should reject the null hypothesis.