Question

Write python 3 code to define a function that uses three arguments, and returns a result.

The function returns True if the first argument is more than or equal to the second argument and less than or equal to the third argument, otherwise it returns False.

Write a python 3 code for function main, that does the following:

• creates a variable and assign it the value True.
• uses a while loop which runs as long as the variable of the previous step is True,
• inside the while loop, get a number from the user and
• if passing that number to the function of the previous question along with 0 and 10, results in a True value returned, then add that number to a running sum. Otherwise make the loop stop without using break.
• After the loop stops, print the running sum of all the values the user entered.

Call main at the end.

Make sure to use conversion or casting functions as needed.

Answer 1

Dear Student ,

As per requirement submitted above kindly find below solution.

Python program :

#Python function
def compareNumber(number1,number2,number3):
    #check numbers
    if number1>=number2 and number1<=number3:
        #if the first argument is more than or equal to the
        # second argument and less than or equal to the third argument
        return True
    else :
        return False
#main() function
def main():
    flag=True #loop variable
    sum=0 #declared variable to store sum
    #using while loop
    while(flag):
        #asking user to enter a number
        number=int(input("Enter a number : "))
        #calling function and pass the number
        if(compareNumber(number,0,10)):
            #if compareNumber() returns true then
            #add to the variable sum
            sum=sum+number
        else:
            flag=False #set flag to false
    #print sum
    print("Sum : ",sum)
#call main() function
main()

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Please refer to the screenshot of the code to understand the indentation of the code :

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Output :

NOTE :PLEASE FEEL FREE TO PROVIDE FEEDBACK ABOUT THE SOLUTION.