Question

In: Chemistry

A 1.0-L buffer solution is 0.130 molL−1 in HNO2 and 0.195 molL−1 in NaNO2. 1.) Determine...

A 1.0-L buffer solution is 0.130 molL−1 in HNO2 and 0.195 molL−1 in NaNO2.

1.) Determine the concentrations of HNO2 and NaNO2 after addition of 1.9 g HCl.

2.) Determine the concentrations of HNO2 and NaNO2 after addition of 1.9 g NaOH.

3.) Determine the concentrations of HNO2 and NaNO2 after addition of 1.9 g HI.

Solutions

Expert Solution


Related Solutions

A 1.0-L buffer solution is 0.135 M in HNO2 and 0.195 M in NaNO2. Part A...
A 1.0-L buffer solution is 0.135 M in HNO2 and 0.195 M in NaNO2. Part A Determine the concentrations of HNO2 and NaNO2 after addition of 1.3 g HCl. Express your answers using three significant figures separated by a comma. [HNO2], [NaNO2] =   M   SubmitMy AnswersGive Up Part B Determine the concentrations of HNO2 and NaNO2 after addition of 1.3 g NaOH. Express your answers using three significant figures separated by a comma. [HNO2], [NaNO2] =   M   Part C Determine...
13) A 1.0-L buffer solution is 0.105 M in HNO2 and 0.175 M in NaNO2. Part...
13) A 1.0-L buffer solution is 0.105 M in HNO2 and 0.175 M in NaNO2. Part A Determine the concentrations of HNO2 and NaNO2 after addition of 1.2 g HCl. Express your answers using three significant figures separated by a comma. [HNO2], [NaNO2] =   M   Part B Determine the concentrations of HNO2 and NaNO2 after addition of 1.2 g NaOH. Express your answers using three significant figures separated by a comma. [HNO2], [NaNO2] =   M   Part C Determine the concentrations...
Calculate the PH of 1.00 L of a buffer that is 0.130 M HNO2 and 0.170...
Calculate the PH of 1.00 L of a buffer that is 0.130 M HNO2 and 0.170 M NaNO2. What is the PH of the same buffer after the addition of 1.00 mL of 12.0 M HCl. (pKa of HNO2 = 3.40). Original Buffer: After HCl is added:
calculate the ph of 1.0 l of a buffer that is .01 m of HNO2 and...
calculate the ph of 1.0 l of a buffer that is .01 m of HNO2 and .15 m NaO2. what is the ph of the same buffer and after the additon of 1.0 l of 12m hcl (pka of HNO2 is 3.4)
A​ 360.0 ml buffer solution is 0.130 mol/L in HF and 0.130 mol/L in NaF.
A​ 360.0 ml buffer solution is 0.130 mol/L in HF and 0.130 mol/L in NaF.                                                                             Part A : what mass of NaOH could this buffer neutralize before the PH rises above 4.00?                          Part B: If the same volume of the buffer was 0.370mol/L in NaF, what mass of NaOH could be handled before the pH rises above 4.0?        the Ka of HF is 3.5*10^-4      this is all the information given, I can look up more ka or...
HNO2 (aq) + NaOH (aq) → NaNO2 (aq) + H2O (l)                          Ka of HNO2 = 4.5...
HNO2 (aq) + NaOH (aq) → NaNO2 (aq) + H2O (l)                          Ka of HNO2 = 4.5 x 10-4 H2O (l) + NO2- (aq) ↔ HNO2 (aq) + OH- (aq)                                  Kb of NO2- = 2.2 x 10-11 Exactly 100 mL of 0.10 M nitrous acid (HNO2) are titrated with a 0.10 M NaOH solution. Calculate the pH for: A:The initial solution B:At the half-equivalence point C:The point at which 80 mL of the base has been added D:The equivalence point...
For 500.0 mL of a buffer solution that is 0.185 molL−1 in C2H5NH2 and 0.175 molL−1...
For 500.0 mL of a buffer solution that is 0.185 molL−1 in C2H5NH2 and 0.175 molL−1 in C2H5NH3Cl, calculate the initial pH and the final pH after adding 0.020 mol of HCl.
A 120.0 mL buffer solution is 0.110 molL−1 in NH3 and 0.135 molL−1 in NH4Br. If...
A 120.0 mL buffer solution is 0.110 molL−1 in NH3 and 0.135 molL−1 in NH4Br. If the same volume of the buffer were 0.255 molL−1 in NH3 and 0.400 molL−1 in NH4Br, what mass of HCl could be handled before the pH fell below 9.00? the answer is not 0.084g!
A 110.0 mL buffer solution is 0.110 molL−1 in NH3 and 0.125 molL−1 in NH4Br. (A)...
A 110.0 mL buffer solution is 0.110 molL−1 in NH3 and 0.125 molL−1 in NH4Br. (A) What mass of HCl will this buffer neutralize before the pH falls below 9.00? (Kb(NH3)=1.8×10−5)? (B) If the same volume of the buffer were 0.265 molL−1 in NH3 and 0.390 molL−1 in NH4Br, what mass of HCl could be handled before the pH fell below 9.00?
A 130.0 mL buffer solution is 0.105 molL−1 in NH3 and 0.135 molL−1 in NH4Br. What...
A 130.0 mL buffer solution is 0.105 molL−1 in NH3 and 0.135 molL−1 in NH4Br. What mass of HCl will this buffer neutralize before the pH falls below 9.00? (Kb(NH3)=1.8×10−5). If the same volume of the buffer were 0.270 molL−1 in NH3 and 0.400 molL−1 in NH4Br, what mass of HCl could be handled before the pH fell below 9.00.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT