Question

In: Statistics and Probability

A 15-member Board of Directors is organizing for the upcoming year.    2.         They must elect a president,...

A 15-member Board of Directors is organizing for the upcoming year.   

2.         They must elect a president, a vice-president, and a treasurer.  How many different slates of candidates are possible?  

3.         They must choose four members to serve on the finance committee. How many different committees could be formed?

The age and gender breakdown of the Board is

Female

Male

25 – 35 years old

3

2

36 – 45 years old

1

4

Over 46 years old

2

3

If one member is randomly chosen to organize the annual meeting, what is the probability that the person will be

4.         Female

            

5.         A female or a person 25-35 years old

6.         A male between 36 and 45 years old.

The Board has narrowed the options for the annual meeting to the following:

City:  Annapolis or Baltimore

Month:  March or June or September  

Venue: Hotel or College

7.         Draw a tree diagram to show the sample space for all possible choices.  

8.         If one package is chosen at random what is the probability that it is in Annapolis at a hotel?

Solutions

Expert Solution

Please note nCx = n! / [(n-x)!*x!]

Some important probabilities for faster calculations:

(a) nC0 = 1, eg5C0 = 1, 99C0 = 1

(b) nCn = 1, eg10C10 = 1, 75C75 = 1

(c) nC1 = n, ,eg5C1 = 5, 99C1 = 99

_____________________________________________________

2) Since the president, VP and treasurer cannot hold 2 posts at the same time, the total possible ways

= 15C1 * 14C1 * 13C1

= 15 * 14 * 13 = 2730

______________________________________________________

3) 4 Members for the finance committee. Choose 4 out of 15 = 15C4= 1365

______________________________________________________

For Questions 4, 5 and 6

Probability = Favorable Outcomes / Total Outcomes

Female Male Total
25 – 35 years old 3 2 5
36 – 45 years old 1 4 5
Over 46 years old 2 3 5
Total 6 9 15

4) P(That a Randomly chosen person is a Female) = 6/15 = 2/5 = 0.4

5) P(A Female or a Person 25 - 35 Years Old) = P(Female) + P(A person 25 - 35 years old) - P(A Female and a Person 25 - 35 Years Old)

= 6/15 + 5/15 - 3/15 = 8/15 = 0.533

6) (A Male between 36 - 45 years old) = 4/15 = 0.267

__________________________________________________________________________

8) P(Annapolis at a Hotel): By referring to the diagram, the required probability = 1/4

_________________________________________________________________________

7) The Tree Diagram is as below. The Individual Probabilities are

P(Annapolis) = P(Baltimore) = 1/2

P(March) = P(June) = P(September) = 1/3

P(Hotel) = P(College) = 1/2


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