Question

In: Statistics and Probability

Times (in seconds) for the 100 freestyle and 100 backstroke were recorded for three top swimmers...

Times (in seconds) for the 100 freestyle and 100 backstroke were recorded for three top swimmers on a university swim team: 46.17 and 50.05; 46.72 and 50.22; 46.89 and 52.95.

(a) Assuming these to be representative samples of all top swimmers' times for the two events, use software to produce a 95% confidence interval for the mean of the time differences, freestyle minus backstroke, for the two events

Solutions

Expert Solution

Given that  swim team

freestyle : 46.17 and 50.05; 46.72

backstroke: 50.22; 46.89 and 52.95.

freestyle

Sample Mean = x̄ = Σxᵢ / n = 142.94 / 3 = 47.64

s2 = Sample Variance = Σ(xi - x̄)2/(n - 1) = 8.8157/2 = 4.407

s = Sample Standard Deviation = √ Sample Variance = √4.407 = 2.09

backstroke

Sample Mean = x̄ = Σxᵢ / n = 150.06 / 3 = 50.02

s2 = Sample Variance = Σ(xi - x̄)2/(n - 1) = 18.4218/2 = 9.211

s = Sample Standard Deviation = √ Sample Variance = √9.211 = 3.035


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