Question

Let x = age in years of a rural Quebec woman at the time of her first marriage. In the year 1941, the population variance of x was approximately σ2 = 5.1. Suppose a recent study of age at first marriage for a random sample of 51 women in rural Quebec gave a sample variance s2 = 2.8. Use a 5% level of significance to test the claim that the current variance is less than 5.1. Find a 90% confidence interval for the population variance. (a) What is the level of significance? State the null and alternate hypotheses. Ho: σ2 = 5.1; H1: σ2 > 5.1 Ho: σ2 = 5.1; H1: σ2 ≠ 5.1 Ho: σ2 < 5.1; H1: σ2 = 5.1 Ho: σ2 = 5.1; H1: σ2 < 5.1 (b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? What assumptions are you making about the original distribution? We assume a normal population distribution. We assume a binomial population distribution. We assume a exponential population distribution. We assume a uniform population distribution. (c) Find or estimate the P-value of the sample test statistic. P-value > 0.100 0.050 < P-value < 0.100 0.025 < P-value < 0.050 0.010 < P-value < 0.025 0.005 < P-value < 0.010 P-value < 0.005 (d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Since the P-value > α, we fail to reject the null hypothesis. Since the P-value > α, we reject the null hypothesis. Since the P-value ≤ α, we reject the null hypothesis. Since the P-value ≤ α, we fail to reject the null hypothesis. (e) Interpret your conclusion in the context of the application. At the 5% level of significance, there is insufficient evidence to conclude that the variance of age at first marriage is less than 5.1. At the 5% level of significance, there is sufficient evidence to conclude that the that the variance of age at first marriage is less than 5.1. (f) Find the requested confidence interval for the population variance. (Round your answers to two decimal places.) lower limit upper limit Interpret the results in the context of the application. We are 90% confident that σ2 lies within this interval. We are 90% confident that σ2 lies below this interval. We are 90% confident that σ2 lies outside this interval. We are 90% confident that σ2 lies above this interval.

Answer 1

SolutionA:

level of significance=0.05

Ho: σ2 = 5.1;

H1: σ2 < 5.1

b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)

chi sq=(n-1)*s^2/σ^2

chi sq=(51-1)*2.8/5.1

=27.45

degrees of freedom=n-1=51-1=50

since sample size ,n=51,n>30 follows normal dsitribution

We assume a normal population distribution.

the value of the chi-square statistic for the sample=27.45

Solutionc:

  

p value can be found ine xcel as

=CHISQ.DIST.RT(27.45;50)

p=0.996054042

p>0.1

P-value > 0.100

Solutiond:

p>0.05

Fail to reject H0.

Since the P-value > α, we fail to reject the null hypothesis.

Solutione:

(e) Interpret your conclusion in the context of the

At the 5% level of significance, there is insufficient evidence to conclude that the variance of age at first marriage is less than 5.1.

Find the requested confidence interval for the population variance. (Round your answers to two decimal

the 90% confidence interval for variance s

2.07<sigma^2<4.03

. We are 90% confident that σ2 lies within this interval.