In: Statistics and Probability
Excel Assignment
Using the information below develop a linear program to determine the best course of action for Grain Agricultural Enterprises.
Draper Agricultural Enterprises operates 3 ranches in the West. The acreage and irrigation water available for the three ranches are shown below:
Farm |
Acreage |
Water Available (Acre Feet) |
1 |
400 |
1,500 |
2 |
600 |
2,000 |
3 |
300 |
900 |
Three crops can be grown; however, the maximum acreage which can be grown of each crop is limited by the amount of appropriate harvesting equipment available. The three crops are describe below:
Crop |
Total Harvesting Capacity (In Acres) |
Water Requirements (In Acre-Feet/Acre) |
Expected Profit (In $/Acre) |
Rye |
700 |
6 |
400 |
Corn |
800 |
4 |
300 |
Barley |
300 |
2 |
100 |
Any combination of crops can be grown on a farm.
The following 3 steps are involved in developing a linear program for the given assignment:
Step 1: Define Your Variables
First, we need to decide how much of each of the three crops needs to be grown in each of the three farms.
Hence let: xij be the number of tons of crops i (i=1, 2, 3 for Rye, Corn and Barley respectively) that is to be grown in farm j (j=1 for Farm1, j=2 for Farm2 and j=3 for Farm3) where xij >=0, i =1,2,3; j=1,2,3
Note: It is given that any combination of the three given crops can be grown on a farm.
Step 2 - Define the Objective Function
The objective is to maximize total profit, say P, i.e.
Maximize P = 400[x11+ x12+x13] + 300[x21+ x22+x23] + 100[x31+ x32+x33] subject to the constraints defined below.
The basic assumptions are:
Step 3 - Writing the Constraints
x11 + x12 + x13 <= 700
x21 + x22 + x23 <= 800
x31 + x32 + x33 <= 300
x11 + x21 + x31 <= 400
x12 + x22 + x32 <= 600
x13 + x23 + x33 <= 300
6x11 + 4x21 + 2x31 <=
1500
6x12 + 4x22 + 2x32 <=
2000
6x13 + 4x23 + 2x33 <= 900