Question

The television show Green’s Anatomy has been successful for many years. That show recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to Green’s Anatomy.

Assume that an advertiser wants to verify that 20% share value by conducting its own survey, and a pilot survey begins with 12 households have TV sets in use at the time of a Green’s Anatomy broadcast. (Round answers to four decimal places)

Find the probability that none of the households are tuned to Green’s Anatomy. P(none) =

Find the probability that at least one household is tuned to Green’s Anatomy. P(at least one) =

Find the probability that at most one household is tuned to Green’s Anatomy. P(at most one) =

If at most one household is tuned to Green’s Anatomy, does it appear that the 20% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Green’s Anatomy unusual?) no, it is not wrong yes, it is wrong

Answer 1

The television show Green’s Anatomy has been successful for many years. That show recently had a share of 20, meaning that among the TV sets in use, 20% were tuned to Green’s Anatomy.

Assume that an advertiser wants to verify that 20% share value by conducting its own survey, and a pilot survey begins with 12 households have TV sets in use at the time of a Green’s Anatomy broadcast. (Round answers to four decimal places)

Binomial distribution used. n=12, p=0.20

Find the probability that none of the households are tuned to Green’s Anatomy. P(none) =0.0687

Find the probability that at least one household is tuned to Green’s Anatomy. P(at least one) = 0.9313

Find the probability that at most one household is tuned to Green’s Anatomy. P(at most one) = 0.2749

If at most one household is tuned to Green’s Anatomy, does it appear that the 20% share value is wrong? (Hint: Is the occurrence of at most one household tuned to Green’s Anatomy unusual?) Answer: no, it is not wrong

yes, it is wrong

( probability of at most one household is 0.2749 ( 27%) is more than the 20% share)

Binomial distribution used. n=12, p=0.20

Binomial Probabilities Table
	X	P(X)
	0	0.0687
	1	0.2062
	2	0.2835
	3	0.2362
	4	0.1329
	5	0.0532
	6	0.0155
	7	0.0033
	8	0.0005
	9	0.0001
	10	0.0000
	11	0.0000
	12	0.0000