In: Physics
The total weight of the person and the bike is \(W=625+98=723 \mathrm{~N}\)
The force \(\mathrm{F}\) on the two tires are equal since it is supportedlyequally. Then the force on each of the tire is \(F+F=W\)
\(2 \mathrm{~F}=723\)
\(\mathrm{F}=361.5 \mathrm{~N}\)
The force \(F=P A\) \(A=\frac{F}{P}=\frac{361.5}{7.60^{*} 10^{5}}=4.76 \times 10^{-4} m^{2}\)
So the area of contact is \(4.76^{*} 10^{-4} \mathrm{~m}^{2}\).