Question

In: Math

Download the dataset CARS1 from BlackBoard. a. Do not worry about outliers. Assume the data is...

Download the dataset CARS1 from BlackBoard. a. Do not worry about outliers. Assume the data is correct and any outliers will remain in the dataset. b. Do scatterplot and analyze the results. c. Test for correlation (correlation coefficient) d. Regress weight (column 2) against gas mileage in the city (column 1). Make sure you make gas mileage the dependent (Y) variable. e. Determine and fully explain R2 MPG City Weight 19 3545 23 2795 23 2600 19 3515 23 3245 17 3930 20 3115 22 3235 17 3995 22 3115 23 3240 17 4020 18 3220 19 3175 20 3450 19 3225 17 3985 32 2440 29 2500 28 2290

Solutions

Expert Solution

Y( gas mileage) Weight (X)
19 3545
23 2795
23 2600
19 3515
23 3245
17 3930
20 3115
22 3235
17 3995
22 3115
23 3240
17 4020
18 3220
19 3175
20 3450
19 3225
17 3985
32 2440
29 2500
28 2290

b)

From the scatter plot, we know that when increasing the value of Y decreases the values of weight and vice versa. Hence, the variable Y and weight have a negative association.

c)

Pearson correlation of Y and Weight = -0.871
P-Value = 0.000

Ans: The estimated p-value for correlation test is 0.000 and less than 0.05 level of significance. Hence, we can conclude that the variable Y and weight have significant association at 0.05 level of significance.

d)

The regression equation is
Y = 44.238 - 0.00708 Weight

Predictor Coef SE Coef T P
Constant 44.238 3.075 14.38 0.000
Weight -0.00708 0.00094 -7.53 0.000


S = 2.13437 R-Sq = 75.9% R-Sq(adj) = 74.6%

The estimated p-value for Weight is 0.000 and less than 0.05 level of significance. Hence, we can conclude that weight is the significant explanatory variable of gas mileage at 0.05 level of significance.

e) The estimated value of R2 is 75.9%. hence, 75.9% variation of the model is explained by the explanatory variable weight.


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