In: Statistics and Probability
The accompanying data are the amounts of fat (in ounces of fat per one hundred ounces of meat) found in samples of two types of meat products. The fat contents are normally distributed and have equal variances for the two meat types. Do the meats have different fat contents? That is, test the null hypothesis that the means are equal vs. the alternative that they are not equal. Use alpha = 0.05. Meat 1 - 30 26 30 19 25 37 27 38 26 31 Meat 2 - 40 34 28 29 26 36 28 37 35 42
Meat 1 ( X ) | Meat 2 ( Y ) | |||
30 | 1.21 | 40 | 42.25 | |
26 | 8.41 | 34 | 0.25 | |
30 | 1.21 | 28 | 30.25 | |
19 | 98.01 | 29 | 20.25 | |
25 | 15.21 | 26 | 56.25 | |
37 | 65.61 | 36 | 6.25 | |
27 | 3.61 | 28 | 30.25 | |
38 | 82.81 | 37 | 12.25 | |
26 | 8.41 | 35 | 2.25 | |
31 | 4.41 | 42 | 72.25 | |
Total | 289 | 288.9 | 335 | 272.5 |
Mean
Standard deviation
Mean
Standard deviation
To Test :-
H0 :-
H1 :-
Test Statistic :-
t = -1.8418
Test Criteria :-
Reject null hypothesis if
Result :- Fail to Reject Null Hypothesis
Conclusion :- Accept Null Hypothesis
There is insufficient evidence to support the claim that the meats have different fat contents at 5% level of significance.