In: Chemistry
The data in the table below were obtained for the reaction: 2ClO2(aq) + 2OH-(aq) ---> ClO3-(aq) + ClO2-(aq) + H2O(l) Experiment number [ClO2](M) [OH-](M) Initial Rate (M/s)
1 .020 .030 .00276
2 .060 .030 .0248
3 .020 .090 .00828
a. What is the order of the reaction with respect to ClO2?
b. What is the order of the reaction with the respect to OH-?
c. What is the overall order of the reaction?
d. What is the magnitude of the rate constant for the reaction?
The reaction being studied is
2ClO2(aq) + 2OH-(aq) ---> ClO3-(aq) + ClO2-(aq) + H2O(l)
Now as per the data provided
Experiment number [ClO2](M) [OH-](M) Initial Rate (M/s)
1 .020 .030 .00276
2 .060 .030 .0248
3 .020 .090 .00828
What we see by comparing experiment 1 and 2 is that concentration of OH- is kept constant but the concentration of [ClO2] has been increased 3 times and the initial rate of the reaction has changed by 0.0248/0.00276 = 9 times. This tells us that the rate is
rate [ClO2]2
So in answer to question a.
a) This is a second order reaction with respect to ClO2
Now let us compare experiment 1 and 3 where ClO2 is kept constant but the concentration of OH- has chnage by 3 times. The initial rates differ by 0.00828/0.00276 = 3.
This tells us that the rate is
rate [OH-]
So in answer to question b.
b) This is a first order reaction with respect to OH-
The overall order of a reaction is the sum of the exponents of the individual reactants.
c) The overall order of the reaction is 2+1 = 3.
d) The rate constant for this reaction is got from the expression
rate = k[ClO2]2[OH-]
so from any one of the data points we will get get the value of k
0.00276 M/s = k (0.02M)2 x (0.03M)
0.00276 M/s = k x 0.000012 M3
k = 0.00276/0.000012 M-2s-1
k = 2.3 x 102M-2s-1 magnitude of the rate constant for the reaction