Question

Having indentation problems. I have no idea why one of my breaks are screwing up. This should be a easy fix and thumbs up for you lads out there. here's my code. Ill leave a comment on where the break problem is. Also if you could do be a solid and run it to see if it executes. Thanks!

Python Code:

def to_euro(dollar):
    return float(dollar)*0.81;

def to_yen(dollar):
    return float(dollar)*106.45;

def to_peso(dollar):
    return float(dollar)*18.58;

def main():
    while(1):
        x=input("Enter 1 for Euro, 2 for Japanese Yen, 3 for Mexican Peso: ");
        x=int(x);
        if(x==1 or x==2 or x==3):
            break;
        else:
         print("Error: Invalid choice");
    while(1):
        y=input("Enter US Dollar: ");
    y=float(y);
    if(y<0):
        print("Can't be negetive");
    else:
        break; #here is the error
    if(x==1):
        print("Its is converted to ",to_euro(y)," Euro" );
    elif(x==2):
        print("Its is converted to ",to_yen(y)," Yen" );
    else:
        print("Its is converted to ",to_peso(y)," Peso" );

main()

Answer 1

Explanation:

Here is the code which has the correct indentation, the error was there because, the code was not inside the while loop.

Code:

def to_euro(dollar):
return float(dollar)*0.81

def to_yen(dollar):
return float(dollar)*106.45

def to_peso(dollar):
return float(dollar)*18.58

def main():
  
while(1):
x=input("Enter 1 for Euro, 2 for Japanese Yen, 3 for Mexican Peso: ")
x=int(x)
  
if(x==1 or x==2 or x==3):
break
else:
print("Error: Invalid choice")
  
while(1):
y=input("Enter US Dollar: ")
  
y=float(y)
  
if(y<0):
print("Can't be negetive")
else:
break
  
if(x==1):
print("Its is converted to ",to_euro(y)," Euro" )
elif(x==2):
print("Its is converted to ",to_yen(y)," Yen" )
else:
print("Its is converted to ",to_peso(y)," Peso" )

main()

Output:

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