In: Statistics and Probability
n the last quarter of 2007, a group of 64 mutual funds had a mean return of 2.5% with a standard deviation of 4.6%. Consider the Normal model N(0.025,0.046) for the returns of these mutual funds. a) What value represents the 40th percentile of these returns? b) What value represents the 99th percentile? c) What's the IQR, or interquartile range, of the quarterly returns for this group of funds? (Please show work)
Given
Mean = 2.5% = 0.025
Standard deviation = 4.6% = 0.046
a)
The 40th percentile of these returns.
40 % means 0.40
From the standard normal distribution table we can get the Z-value
Z = -0.25
= 0.0135
b)
99th percentile means 0.99
From standard normal table
Z = 2.33
= 0.1322
c)
The IQR, or interquartile range, of the quarterly returns for this group of funds
IQR = Q3 - Q1
Q3 means 75% = 0.75
Q1 means 25% = 0.25
Again from standard normal table
Z value at 0.75 = 0.67
Z value at 0.25 = -0.67
At 75 % or Q3
0.67 = ( - 0.025) / 0.046
= 0.0558
At 25% or Q1
= -0.0058
IQR = Q3 - Q1
= 0.0558 - (-0.0058)
= 0.0616