In: Statistics and Probability
The Dow Jones Industrial Average has had a mean gain of 432 pear year with a standard deviation of 722. A random sample of 40 years is selected. What is the probability that the mean gain for the sample was between 250 and 500?
0.669
0.137
0.331
0.863
Solution :
Given that,
mean = = 432
standard deviation = = 722
n = 40
= 432
= (/n) = ( 722 / 40 ) = 114.1582
P ( 250 < x < 500 )
P ( 250 - 432 / 114.1582 ) < ( - / ) < ( 500 - 432 / 114.1582 )
P ( - 182 / 114.1582 < z < 68 / 114.1582 )
P ( -1.594 < z < 0.596 )
P ( z < 0.596 ) - P ( z < -1.594 )
Using z table
= 0.7244 - 0.0555
= 0.6689
Probability = 0.669
Option 0.669 is correct.