A sailor strikes the side of his ship just below the surface of the sea. He...

A sailor strikes the side of his ship just below the surface of the sea. He hears the echo of the wave reflected from the ocean floor directly below 10.0 s later. How deep is the ocean at this point? (Note: Use the bulk modulus method to determine the speed of sound in this fluid, rather than using a tabluated value.)
_____ m

Solutions

Expert Solution

the echo time t = 10 s

speed of the water wave v = √K/ρ ................ (1)

bulkmodulus of the water K = 2*10⁹ N/m²

density of sea water ρ = 1.025*10³ kg/m³

the velocity v = 2d/t ................... (2)

compare eq (1) and (2) , we get

2d/t = √K/ρ

dept of the ocean is

d = (t / 2)√K/ρ

= (10 s/2)√[(2*10⁹ N/m²)/(1.025*10³ kg/m³)]

= 6.98*10³ m

= 6.98 km

= 7 km (approximately)

genius_generous answered 1 year ago

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