John is rollerblading down a long, straight path. At time zero, there is a mailbox about 1m in front of him.

John is rollerblading down a long, straight path. At time zero, there is a mailbox about 1m in front of him. In the 5s time period that follows, John's velocity is given by the velocity versus time graph in the figure. Taking the mailbox to mark the zero location, with positions beyond the mailbox as positive, plot his position versus time in the given position versus time graph.

Assuming that all the numbers given are exact, what is John's position at a time of 4.65 s4.65 s? Enter your answer to at least three significant digits.

position at 4.65 s4.65 s: _______ m

Solutions

Expert Solution

His initial position x = -1 m

His velocity is -2 m/s for the first second. Hence his position decreases linearly to -3 m from -1m in the first second.

His velocity is zero for the next second. Hence, his position remains the same -3 m for this second.

For the next three seconds, his velocity is constant and 2m/s. Therefore his position increases at a rate of 2 m per second from - 3m to 3 m. This is used to plot the graph of position vs time.

genius_generous answered 2 years ago

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