Question

In: Math

Let f(x)=(x^2+1)*(2x-3) Find the equation of the line tangent to the graph of f(x) at x=3....

Let f(x)=(x^2+1)*(2x-3)

Find the equation of the line tangent to the graph of f(x) at x=3.

Find the value(s) of x where the tangent line is horizontal.

Solutions

Expert Solution

we have

put x = 3,

now,

the slope of the tangent line is,

slope at x = 3,

the equation of the tangent line is,

put the x₀ = 3, y₀ = 30 and m = 38,

m=0 for the tangent line is horizontal,

we know that,

so,

hence no any real value of x where the tangent line is horizontal

milcah answered 1 year ago

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