Question

which of these subshell designations are possible and which are impossible

2p 2d 1.5p 4d 2f

Answer 1

there are the:

for "n" (or the numebrs prior to the letters)

n must be integer

n must be positive

ttherefore, 1.5p is NOT possible

Continue with

2p 2d 4d 2f

The maximum level is given by n-1

Therefore

for n = 2, then l = n-1 = 2-1 = 1; l= 1 (0,1)

for n = 4, then l = n-1 = 4-1 =3; l = 3 (0,1,2)

0 --> s

1 --> p

2 ---> d

For n = 2, then we can only have 2s, 2p ... 2d, 2f are impossible

Only 2p, 4d are left

For n = 2, l= 0,1,2 so s,p,d

4d is possible

Possilbe set: 2p and 4d