In: Math
Find the general solution of the given system.
dx/dt=6x-y
dy/dt=5x+4y
Given : dx/dt = 6x-y
dy/dt = 5x+4y
Dividing both the equation:
This is homogenous equation of x and y.
thus, dividing numerator and denominator by "x", gives
let y/x = Y, then y = Yx
differentiating both side
Cross multiplying:
breaking numerator in terms of differentiation of denominator (LHS)
integrating above differential equation:
as integration of f'(x)/f(x)dx is ln(f(x))
and integration of
thus ,
substituting back Y = y/x
ln(x^2)/2 = ln(x), cancelling this term both side,
{C is integral constant}