In: Math
Find the general solution of the given system.
dx/dt=6x-y
dy/dt=5x+4y
Given : dx/dt = 6x-y
dy/dt = 5x+4y
Dividing both the equation:

This is homogenous equation of x and y.
thus, dividing numerator and denominator by "x", gives

let y/x = Y, then y = Yx
differentiating both side

Cross multiplying:

breaking numerator in terms of differentiation of denominator (LHS)

integrating above differential equation:

as integration of f'(x)/f(x)dx is ln(f(x))
and integration of
thus ,

substituting back Y = y/x


ln(x^2)/2 = ln(x), cancelling this term both side,

{C is integral constant}