In: Math
Music Group |
Control Group |
||
30 |
28 |
30 |
23 |
32 |
25 |
23 |
26 |
28 |
30 |
24 |
20 |
26 |
29 |
29 |
20 |
30 |
28 |
26 |
26 |
20 |
27 |
20 |
21 |
24 |
29 |
26 |
23 |
33 |
27 |
21 |
20 |
31 |
26 |
22 |
26 |
26 |
28 |
25 |
27 |
30 |
27 |
SPSS.1 A study reveals that older adults work out a little harder when they listen to music. The table below contains the data from two groups of older adults: one group listened to music while walking; the other group did not listen to music. Stride length was measured as an indicator of how hard they were working out (higher numbers = longer stride = working out harder).
What are the sample means in this study?
Mmusic = Mcontrol =
SPSS.2 Paste your SPSS output of the descriptive statistics below.
SPSS.3 What t statistic was obtained (calculated) for the music and exercise study.
SPSS.4 Assuming a two-tailed hypothesis test with alpha = .05, use your t-table to look up the critical t-value for this study. What are the critical t-values?
SPSS.5 What p-value is obtained from your SPSS output?
SPSS.6 Is there a statistically significant effect of music on stride length?
Solution:
Here, we have to use two sample t test or independent samples t test for population means. The SPSS output for this test is given as below:
Group Statistics |
|||||
---|---|---|---|---|---|
Group |
N |
Mean |
Std. Deviation |
Std. Error Mean |
|
Stride |
Music Group |
21 |
27.9524 |
2.92363 |
.63799 |
Control Group |
21 |
24.0476 |
3.07370 |
.67074 |
Independent Samples Test |
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---|---|---|---|---|---|---|---|---|---|---|
Levene's Test for Equality of Variances |
t-test for Equality of Means |
|||||||||
F |
Sig. |
t |
df |
Sig. (2-tailed) |
Mean Difference |
Std. Error Difference |
95% Confidence Interval of the Difference |
|||
Lower |
Upper |
|||||||||
Stride |
Equal variances assumed |
.776 |
.384 |
4.218 |
40 |
.000 |
3.90476 |
.92570 |
2.03386 |
5.77567 |
Equal variances not assumed |
4.218 |
39.900 |
.000 |
3.90476 |
.92570 |
2.03371 |
5.77581 |
The null and alternative hypotheses for this test are given as below:
Null hypothesis: H0: There is no any statistically significant effect of music on stride length.
Alternative hypothesis: Ha: There is a statistically significant effect of music on stride length.
Means for both groups are given as below:
Mmusic =27.9524
Mcontrol =24.0476
Test statistic is given as below:
t statistic = 4.218
α = 0.05
Critical t-values = ±2.0227
[Critical t values = -2.0227 and 2.0227]
(by using t-table)
P-value = 0.000
P-value < α = 0.05
So, we reject the null hypothesis
There is sufficient evidence to conclude that there is a statistically significant effect of music on stride length.