Question

In: Math

Music Group Control Group 30 28 30 23 32 25 23 26 28 30 24 20...

Music Group

Control Group

30

28

30

23

32

25

23

26

28

30

24

20

26

29

29

20

30

28

26

26

20

27

20

21

24

29

26

23

33

27

21

20

31

26

22

26

26

28

25

27

30

27

SPSS.1 A study reveals that older adults work out a little harder when they listen to music. The table below contains the data from two groups of older adults: one group listened to music while walking; the other group did not listen to music. Stride length was measured as an indicator of how hard they were working out (higher numbers = longer stride = working out harder).

What are the sample means in this study?

                                                                      Mmusic =                   Mcontrol =

SPSS.2 Paste your SPSS output of the descriptive statistics below.

SPSS.3 What t statistic was obtained (calculated) for the music and exercise study.

SPSS.4 Assuming a two-tailed hypothesis test with alpha = .05, use your t-table to look up the critical t-value for this study. What are the critical t-values?

SPSS.5 What p-value is obtained from your SPSS output?

SPSS.6 Is there a statistically significant effect of music on stride length?

Solutions

Expert Solution

Solution:

Here, we have to use two sample t test or independent samples t test for population means. The SPSS output for this test is given as below:

Group Statistics

Group

N

Mean

Std. Deviation

Std. Error Mean

Stride

Music Group

21

27.9524

2.92363

.63799

Control Group

21

24.0476

3.07370

.67074

Independent Samples Test

Levene's Test for Equality of Variances

t-test for Equality of Means

F

Sig.

t

df

Sig. (2-tailed)

Mean Difference

Std. Error Difference

95% Confidence Interval of the Difference

Lower

Upper

Stride

Equal variances assumed

.776

.384

4.218

40

.000

3.90476

.92570

2.03386

5.77567

Equal variances not assumed

4.218

39.900

.000

3.90476

.92570

2.03371

5.77581

The null and alternative hypotheses for this test are given as below:

Null hypothesis: H0: There is no any statistically significant effect of music on stride length.

Alternative hypothesis: Ha: There is a statistically significant effect of music on stride length.

Means for both groups are given as below:

Mmusic =27.9524

Mcontrol =24.0476

Test statistic is given as below:

t statistic = 4.218

α = 0.05

Critical t-values = ±2.0227

[Critical t values = -2.0227 and 2.0227]

(by using t-table)

P-value = 0.000

P-value < α = 0.05

So, we reject the null hypothesis

There is sufficient evidence to conclude that there is a statistically significant effect of music on stride length.


Related Solutions

1- 25 28 24 21 28 26 23 22 29 21 29 24 22 25 26...
1- 25 28 24 21 28 26 23 22 29 21 29 24 22 25 26 18 27 26 29 23 21 26 27 21 25 27 24 29 22 25 24 24 21 29 22 25 21 22 22 25 22 25 Calculate a) arithmetic mean and b) standard deviation of the sample. A) b) - Represent a classified frequency table. Answer the following questions in this table with column calculations. Calculate a) arithmetic mean, b) quadratic mean, c)...
Resident Commuter 22 25 27 23 26 28 26 24 18 20 19 18 22 25...
Resident Commuter 22 25 27 23 26 28 26 24 18 20 19 18 22 25 24 35 25 20 26 24 27 26 18 19 23 18 23 22 28 25 20 24 18 30 26 18 18 19 32 23 26 30 22 22 22 21 18 20 19 19 18 29 19 22 18 22 19 26 35 19 19 18 19 32 26 19 19 21 23 18 20 18 29 23 21 19 36 27...
If the network : 192.168.5.0/22 ​​ 192.168.5.0/23 192.168.5.0/24 192.168.5.0/25 192.168.5.0/26 192.168.5.0/27 192.168.5.0/28 192.168.5.0/29 192.168.5.0/30 Questions :...
If the network : 192.168.5.0/22 ​​ 192.168.5.0/23 192.168.5.0/24 192.168.5.0/25 192.168.5.0/26 192.168.5.0/27 192.168.5.0/28 192.168.5.0/29 192.168.5.0/30 Questions : 1. Determine total of Subnets, 2. Determine total of Hosts per Subnet, 3. Determine the Subnet Block, 4. Specify Host-Broadcast Address.
old by years Interval Frequency 35-37 two 32-34 three 29-31 five 26-28 Six 23-25 four 20-22...
old by years Interval Frequency 35-37 two 32-34 three 29-31 five 26-28 Six 23-25 four 20-22 five 17-19 nine 14-16 Sixteen Calculate the above when Passport first used 1- what is the shape of the old distribution? 2- Which accurate statements can describe the relationship between the mean and median old? he mean and median are the same The mean is bigger than the median The mean is less than the median 3- Calculate percentile rank corresponding to the old...
Calculate the pH after addition of 0, 10, 20, 24, 24.90, 25, 25.10, 26, and 30...
Calculate the pH after addition of 0, 10, 20, 24, 24.90, 25, 25.10, 26, and 30 mL of 0.01 M NaOH in the titration of 50 mL of 0.005 M weak monoportic acid HA. Ka of the acid is = 1.00 x 10^-6 Kw= 1.00 x 10^-14 at 25 degrees Celsius
Day High temperature, C Low temperature, C 1 30 25 2 32 26 3 34 23...
Day High temperature, C Low temperature, C 1 30 25 2 32 26 3 34 23 4 29 20 5 31 19 6 30 21 7 25 18 The high and low temperatures of each day in Wichita KS are given in Table. (1 pt) (a) Plot the high temperature for 7 days as a function of day, i.e., high temperature on y-axis, and day # on x-axis. Use the red, empty square as a marker with the solid line....
MT scores: 11, 11, 16, 17, 19, 20, 21, 21 23 24 24 26 26 27...
MT scores: 11, 11, 16, 17, 19, 20, 21, 21 23 24 24 26 26 27 27 28 28 28 29 30 31 31 32 33 35 37 38 38 39 42 44 Questions for Class MT Score Distribution Analysis 1. Create a boxplot of MT scores. 2. Compute the probability that a randomly selected student from the class scored higher than 20. 3. Are the MT scores normally distributed? Why or why not? 4. Assuming a normal fit, compute...
MT scores: 11, 11, 16, 17, 19, 20, 21, 21 23 24 24 26 26 27...
MT scores: 11, 11, 16, 17, 19, 20, 21, 21 23 24 24 26 26 27 27 28 28 28 29 30 31 31 32 33 35 37 38 38 39 42 44 Questions for Class MT Score Distribution Analysis 1. Create a histogram of MT scores. 2. Describe the shape of the MT scores distribution. 3. Compute the mean and standard deviation. 4. Compute the 5-number summary. 5. Create a boxplot of MT scores. 6. Compute the probability that...
Question 12 (1 point) X 28 23 30 48 40 25 26 Y 91 106 112...
Question 12 (1 point) X 28 23 30 48 40 25 26 Y 91 106 112 192 155 130 101 The coefficient of determination for the above bivariate data is: Question 12 options: 0.60 0.70 0.80 0.90
Consider a sample with data values of 26, 25, 22, 17, 30, 36, 28, and 25....
Consider a sample with data values of 26, 25, 22, 17, 30, 36, 28, and 25. Compute the 20th, 25th, 65th, and 75th percentiles (to 1 decimal, if decimals are necessary). 20th percentile 25th percentile 65th percentile 75th percentile
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT